Closed subset of a compact set is compact | Compact set | Real analysis | Topology | Compactness

[@gunjankakkar9073]

I have watched alot of videos..bt my doubts were not cleared at all... Bt ur explaination is so clear..Gbu🥰

[@sabafatmanoori5472]

Super mam ... nd no doubt ..
Also it doesn't matter how many likes dislikes or subscribers u have...believe in ur self that u r seriously teaching very well....😊

[@OMGMaths]

Thank You 😊

[@gunjankakkar9073]

Great mam...u explain so clearly..
I wish i could find more teachers like u for other maths also

[@Devil3625]

Yes explain very clear

[@rajendrabehera9835]

Hii

[@gautamiwankhede6357]

bahut badhiya maam....keep up the work

[@monikachauhan8956]

Simplest and great explanation, 👌 thanku so much 🙏😊Bhut confused thi,but ab clear hai ye theorm

[@OMGMaths]

Most welcome 😊
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[@suryasainivedithasurya7749]

Thnx for providing such a understandble vedio mam,

[@OMGMaths]

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[@ritikathakur6178]

Your teaching skills are brilliant 💯💯💯✨✨✨

[@OMGMaths]

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[@sonad490]

Thanx for ur video 🙏🙏👍

[@snzmathematics5681]

Thanku worthy Mam
Ur approach is awesome 🙏🙏🙏🙏

[@OMGMaths]

It's my pleasure 🙏
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[@vikrantverma-if4sz]

प्रमेय 1. किसी संहत दूरीक समष्टि का एक संवृत उपसमुच्चय संहत होता है।
Mam is theorem me bhi yahi bna sakte hai kyua

[@sitakaushal7153]

🤗thanku

[@Themathjester]

Thanks

[@SANOJKUMAR-eh1jj]

Thanks you so much maam...🙏🙏🙏🙏

[@OMGMaths]

Most welcome 😊 Keep Watching and Share with others…

[@nayaabahmedn8228]

Thanks for amazing help

[@OMGMaths]

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[@cancerian4890]

Closed subspace k Liye b yhi proof ho ga Kya?

[@pragyagupta370]

intersection of G alpha,i and F is F right? The third last step?

[@ayanamaiti2823]

Yeah

[@OMGMaths]

th-cam.com/video/44FBHeBpbp0/w-d-xo.html : please watch this video and u will be able to understand the concept.

[@OMGMaths]

That step is not wrong you must watch this th-cam.com/video/44FBHeBpbp0/w-d-xo.html

[@SANOJKUMAR-eh1jj]

Eska pdf kha nhi milega ....kya ,maam

[@OMGMaths]

Sorry,I don’t have…

[@pushkarkumar3089]

Fine!!!

[@OMGMaths]

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[@pushkarkumar3089]

Yes~yes

[@ml.rahul2469]

thanks a lot mam

[@OMGMaths]

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[@smvlog6130]

Ma'am,ultimately this proof says that any subset of compact set compact right? Where is the thing that subset is closed? Ma'am ease reply..

[@pirateghost8953]

We are able to use F complement is open because of F is closed only

[@dhananjaytudu6864]

12:42 me mujhe samaj nahi aya madam

[@Jquee999]

if yo do an intersection of a set A with any set, the result will we subset of A only. So with that in mind, the result will be contained in A only. That is what is stated there.

[@KhemchandMatlani]

Thanks mam hum exam me pass ho jayega

[@OMGMaths]

I'm so glad! Thank You🙏
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[@devanshiagnihotri4472]

Easiest

[@OMGMaths]

Thank you 😊
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[@VolatileGuy103]

god

[@OMGMaths]

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[@prakashregar9760]

Great mam...u explain so clearly..
I wish i could find more teachers like u for other maths also