I am confused with a small aspect, perhaps someone can please help. Why is your statement of "Nine times more CO2 than CO" at 6:00 plugged into the equation the way it is? Isn't that statement written as 9nCO2 : 1nCO So why arnt we plugging in and solving for CO2 instead?
I think that there´s something when he perfomed the atomic balances. According to Felder, you have to perform the atomic balance with the flow rate that reacted and in this case he's using the entire 100 moles of Butane. Somebody can explain why he did that?
When the combustion reaction is written, why is Carbon Monoxide not accounted for? We are told it is a product in the statement, so when writing the reaction, shouldn't it be accounted for?
Zach Hetzler @2:30 We are trying to solve for the amount of theoretical oxygen needed to completely burn all of the butane. When calculating theoretical oxygen, you assume that all the carbon in the fuel is oxidized to CO2 and all the hydrogen is oxidized to H2O.
Thanks for your question. When it says we have 25% excess oxygen, we first need to find the theoretical need of oxygen, then multiply it by 1.25. In other words, we are feeding the amount of oxygen we need, plus an extra 25%. Hopefully this helps.
can the extent of reaction method be applied here? tried to solve it with the extent of reaction which i found to be 45, I got mols of water right but the rest is off by a bit. is it wrong to only use the balanced equation you used because it doesn't account for the CO? so if i wanted to use the extent of reaction would i have 2 reactions?
since the carbon monoxide didnt show up reaction so you cannot solve with the extant. I mean the carbon monoxide didnt react in the reaction which means we cannot solve with the extant I hope you got it
you would have two reactions and therefore two extents to solve for which you can get with the 9:1 ratio of CO2 to CO by getting a relationship between the two extents and using them with the butane balance.
May I ask a question/clarification? Sorry, I am confused. If so, in no. 2 which is filling the details, what are the considered unknowns? Is it only the number of compounds included in the reactor? or we should also count the compound outside the separator and in the fresh feed?
The 5.5 mol butane/hr is what is coming out of the separator. The number comes from a combination of a given and previous calculations. We are given that the separator sends back 90% of the exit from the reactor to be recycled. Therefore the amount of butane in the exit of the separator is 10% of that, which is calculated to be 55 mol butane/hr at 3:30 in the video.
I’m confused, if you are doing an atomic material balance, for the carbon dioxide why didn’t you multiply it by 4, since you know from the stoichiometric ratio that there are four molecules of CO2 from the chemical equation?!
The elemental balance is written in terms of species in the stream x atoms in the species. The total number of atoms is accounted for this way, so the reaction stoichiometry is irrelevant.
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I am confused with a small aspect, perhaps someone can please help.
Why is your statement of "Nine times more CO2 than CO" at 6:00
plugged into the equation the way it is?
Isn't that statement written as 9nCO2 : 1nCO
So why arnt we plugging in and solving for CO2 instead?
I think that there´s something when he perfomed the atomic balances. According to Felder, you have to perform the atomic balance with the flow rate that reacted and in this case he's using the entire 100 moles of Butane. Somebody can explain why he did that?
When the combustion reaction is written, why is Carbon Monoxide not accounted for? We are told it is a product in the statement, so when writing the reaction, shouldn't it be accounted for?
Zach Hetzler @2:30 We are trying to solve for the amount of theoretical oxygen needed to completely burn all of the butane. When calculating theoretical oxygen, you assume that all the carbon in the fuel is oxidized to CO2 and all the hydrogen is oxidized to H2O.
I didn't know how did you get the 1.25. Because you said that 25% excess, is it supposed to be 6.25*0.25=1.625. Please explain it.
Thanks for your question. When it says we have 25% excess oxygen, we first need to find the theoretical need of oxygen, then multiply it by 1.25. In other words, we are feeding the amount of oxygen we need, plus an extra 25%. Hopefully this helps.
@@LearnChemE thank u so much ❤️❤️❤️
can the extent of reaction method be applied here? tried to solve it with the extent of reaction which i found to be 45, I got mols of water right but the rest is off by a bit. is it wrong to only use the balanced equation you used because it doesn't account for the CO? so if i wanted to use the extent of reaction would i have 2 reactions?
since the carbon monoxide didnt show up reaction so you cannot solve with the extant. I mean the carbon monoxide didnt react in the reaction which means we cannot solve with the extant I hope you got it
@@Faa334 can you explain more im a bit confuse
you would have two reactions and therefore two extents to solve for which you can get with the 9:1 ratio of CO2 to CO by getting a relationship between the two extents and using them with the butane balance.
May I ask a question/clarification? Sorry, I am confused. If so, in no. 2 which is filling the details, what are the considered unknowns? Is it only the number of compounds included in the reactor? or we should also count the compound outside the separator and in the fresh feed?
Also, in computing the % excess, why did it become 1.25 and not 0.25(650)? Did you add the percent of butane and oxygen?
in finding the overall conversion of butane, how did you get the 5.5 mol per hr going out
The 5.5 mol butane/hr is what is coming out of the separator. The number comes from a combination of a given and previous calculations. We are given that the separator sends back 90% of the exit from the reactor to be recycled. Therefore the amount of butane in the exit of the separator is 10% of that, which is calculated to be 55 mol butane/hr at 3:30 in the video.
Hello,
Could you please help me to solve another problem involving recycling ? Thanks
Thank you sir ! , this is so helpful
I tried using reaction extent for this problem and it didnt work for me, why is that??
because the carbon moxide didnt react in the reaction so u cannot solve with the extant reaction
I’m confused, if you are doing an atomic material balance, for the carbon dioxide why didn’t you multiply it by 4, since you know from the stoichiometric ratio that there are four molecules of CO2 from the chemical equation?!
The elemental balance is written in terms of species in the stream x atoms in the species. The total number of atoms is accounted for this way, so the reaction stoichiometry is irrelevant.
are the exiting streams of separation nco2w nh2ow...etc
Charlie Ni Yes, those are the exiting products. The other stream leaving the separator is the recycle stream.