Concentration - Free Formula Sheet: bit.ly/3YfzBTf Chemistry 2 Final Exam Review: th-cam.com/video/lSmJN1_uVpI/w-d-xo.html Chemistry PDF Worksheets: www.video-tutor.net/chemistry-basic-introduction.html Next Video: th-cam.com/video/sNZhOA1BFPE/w-d-xo.html
He speaks the language of chemistry, doesn't make any mistakes, doesn't delay calculations, doesn't promote his channel, doesn't have bad quality issues whatsoever and best of all, he explains it the clearest in the shortest time!
replace oh with h...count how many replaced..and multiply the no. with given mass of compound...done. And for equaivalent mass , divide molar mass with the the no of replacebale oh with h, the same way u did with normality
Professor Organic Chemistry Tutor, thank you for an awesome Introduction into Normality for Acid Base Reactions in AP/General Chemistry. The definition of Normality along with the practice problems/examples are off the learning charts. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
He did it again 👏 Explaining it very well than our teachers (Probably because we learned it second hand unless you're in advance of studying right now)
Glad you are here , our prof just bailed on us last minute before our exams told us that she wont be teaching us until the end of our semester reason is that some student had trouble with internet and she over reacted that no one attended the class well anyways I'll be watching your videos till i learn
This man is legend of chemistry 🙏💕 even our university professors can't teach chemistry that well .. and one more thing , I'm in love with your voice 😁💖
can you tell me what the solution for this question 👇 A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity???? Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺
Thank you for this! I just didn't get it even after 2 of my teachers explained it to me and I even studied it from Mortimer's book but still couldn't figure it out. You explained really well and nowI finally get it and I'm so relieved! So I'm not dumb after all! 😂
can you tell me what the solution for this question 👇 A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity???? Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺
@@sherlockholmes6803 normality is molarity multiplied with n factor. So molarity will be normality divided by nf. Normality is given 3.0 and nf of aluminium sulfate is 6 (charge on cations ot anions is the nf for ionic compounds.) Divididing normality 3 by nf 6 gives 0.5 which will be the molarity
I paused at the moment wherein he added the #of equiv weight and mine is kinda different (a little but I hope this might help for some) N= #equiv of solute / V of soln in L But: #equiv of solute = mass solute / equiv weight But: equiv weight = molecular weight / f Wherein "f" are the H and OH
can you tell me what the solution for this question 👇 A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity???? Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺
Concentration - Free Formula Sheet: bit.ly/3YfzBTf
Chemistry 2 Final Exam Review: th-cam.com/video/lSmJN1_uVpI/w-d-xo.html
Chemistry PDF Worksheets: www.video-tutor.net/chemistry-basic-introduction.html
Next Video: th-cam.com/video/sNZhOA1BFPE/w-d-xo.html
He speaks the language of chemistry, doesn't make any mistakes, doesn't delay calculations, doesn't promote his channel, doesn't have bad quality issues whatsoever and best of all, he explains it the clearest in the shortest time!
Ok
this man has single handedly saved countless people's chem grades.
I owe him my medical entrance 🥴✨
Not only chemistry!!..
yes he does
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Yaaa
”thx for watching” Nah man thank YOU!!
saaame 😂
Yaaaas, like man! Thank YOU for teaching!
You mean “NaH man”
@@reallybiglizard NaBro
Yeah exactly
I am soo dumb that I don't even understand this when all other commenters are thanking this man😭😭
Same here😭😭😭
Don't underrate yourselves. Compare what he taught with what's provided in your textbook... You'd grab it faster. 😉
replace oh with h...count how many replaced..and multiply the no. with given mass of compound...done. And for equaivalent mass , divide molar mass with the the no of replacebale oh with h, the same way u did with normality
Never use negative words for yourself, you are intelligent enough to learn this concept . Relax
Memorise it.
This tutor is a wizard, I don't read my textbooks anymore, your videos are excellent. You must be a professor.
doesn't sound like one , lol
But hes very good
Tyler dewitt and you are the only 💥💥 chemistry teachers ...Thanq fr this explanation..
I agree with you
and prof dave explains
Aand melissa maribel
And me okno
Literally. I am so grateful to each of them
Professor Organic Chemistry Tutor, thank you for an awesome Introduction into Normality for Acid Base Reactions in AP/General Chemistry. The definition of Normality along with the practice problems/examples are off the learning charts. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
this literally saved me from failing my quiz, thanks a lot! Please make more videos, you're a great tutor!
@Yomangamer why do u think he's in 9th?
😥where was this video!!! Why didnt i see it before?! This helped me more than anything else!!!! Thanks!!!!!
I appreciate this video so much. No one else explained it this well. Thank you so much!!
Dammmmn u should have my tuition fee ❤
Best Online Tutor ,You deserve Five stars if you were an app❤❤
Here for my pharmaceutics exam. Thank you!
It helped me a lot and also now I understand normality concept a lot better. Thank you for your tutorial video!!
In my language (في لغتي )
شكرا جزيلا ❤
In your language (في لغتك)
Thank you so much ❤
و في الانمي اريغاتو غوسايمس 🌹🌹😊😊
A minute of silence for those people who have a test later. May you ace your test
Hello, I'm studying geology and we have a lesson about the subject. I benefited a lot from the video. Thank you
where are you studying ?
He did it again 👏
Explaining it very well than our teachers
(Probably because we learned it second hand unless you're in advance of studying right now)
I have never seen a teacher explaining the subjects as perfectly as you do😍😘😍😘😘
His clarity in voice is next lvl. He gives us the short method to deal with the calculations.
Thanks,you are one of the best channels on TH-cam
YOU SAVED MY LIFE! I hated this topic and neverr everr understood it no matter how hard I tried, thankss mann😭
Thanks for tge clarification man, I was going crazy with how confusing my textbook was😩
learned what i needed in the first 3 minutes thanks bro you saved my life
Just cant believe how much professors dont know how to explain. Just a 16 min video is worth a whole chapter
Glad you are here , our prof just bailed on us last minute before our exams told us that she wont be teaching us until the end of our semester reason is that some student had trouble with internet and she over reacted that no one attended the class well anyways I'll be watching your videos till i learn
Thanks to you🙏 sir, i have learnt this. You just saved someone's grade👏👏
Achievement-:"Compete the Indian teacher"
He breaks it down so well.
This man is legend of chemistry 🙏💕 even our university professors can't teach chemistry that well .. and one more thing , I'm in love with your voice 😁💖
Bruv you're my lifesaver. Thanks a ton bawseman
Thanks a lot!
Love ur voice anyway😄
Thank you very much🙏.. please never stop teaching
8:45 for finding ew first find the m.m then divide it by num of oxidation state,you will get the answer by this simple method
Thanks!
Great job, pro
advice < watch the video at 1.25 speed >
you are from heaven
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popping in here to say that u saved my life in my exam today man.
This helped me understand for prep with a nursing exam. Thanks very much
No problem.
Thank you for helping me solving my problems ☺️
Thank you. I like the sound of your voice
life saver for a jee aspirant like me
amazing tutor!!!!!!!!! Thank you very much for the help.
It is very helpful.
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Thank you!
I have enjoyed the whole 16.5 min. , it’s just awesome man, thnx
I find the first formula a whole lot easier than the second one.
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Thanks from 2019💛💛
Thank you man! You always save my chem grades🥺. Love all the way❤❤❤
it's 2021 and you still save me again and again
can you tell me what the solution for this question 👇
A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity????
Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺
@@sherlockholmes6803
Sorry I see it just right now:( hope you do good with your exam
@@OctobrTea I think its solution will be 0.5 but there is no option for that in the exam
why is this guy teaching all the subjects that i have doubts in ??
Thanks brother, your video made my day!
Thank you for this! I just didn't get it even after 2 of my teachers explained it to me and I even studied it from Mortimer's book but still couldn't figure it out. You explained really well and nowI finally get it and I'm so relieved! So I'm not dumb after all! 😂
Your profile pic!!!!!!!!!!!
can you tell me what the solution for this question 👇
A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity????
Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺
@@sherlockholmes6803 normality is molarity multiplied with n factor. So molarity will be normality divided by nf. Normality is given 3.0 and nf of aluminium sulfate is 6 (charge on cations ot anions is the nf for ionic compounds.) Divididing normality 3 by nf 6 gives 0.5 which will be the molarity
I used to watch ur videos in School and now I am watching ur videos in Uni
omg thank you so much, I appreciate this video a lots.
This video has really help me a lot
Thanks man I enjoyed the video and it is very clear
Nice explained
Love from india
Amaizing explanation ❤
Thank u, u amazing person this helped more then u could know thank uuuuu
he is good chemistry teacher
I paused at the moment wherein he added the #of equiv weight and mine is kinda different (a little but I hope this might help for some)
N= #equiv of solute / V of soln in L
But:
#equiv of solute =
mass solute / equiv weight
But:
equiv weight = molecular weight / f
Wherein "f" are the H and OH
Be a hero
You're amazing. I absolutely love your channel! Thank you so much! Keep posting:)
You said it prapti
I feel great watching this, thanks
Well explained! Thank you♥️
Thank you for your video. Helped a lot
pls answer below question
In a Titrimetric analysis , 25 cm3 of 0.1 N HNO3 would react completely with ________ cm3 of 0.25 N KOH
you re the best teacher
10:07 we can directly do using N= M*n
i like your voice. Its so soothing.
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Thank you very much for your explanation👍👍👏👏
Awesome bro,it was pretty helpful
You discuss acids and bases and great job 👍🏻, but in case if there was not an acid nor bases how can i find the Normality of that solution?
there will be salt given
Thanks ...this was intuitive
me hearing the calculator clacking
also me: What the?
You are the best just made my day
You my guy, are a hero
Thank you so much for your help 💞
Why would anyone in the world ever even consider using the second method when it was 500 times more complicated and took 3 times as long?
Nick Tokar my chemistry professor
ikr.
U can not always predict the no. Of h or oh so produced
bc my chemistry professor wants to
Thats ironic since i understand the second one easier than the first
This video is really helpful 👍
Thanks man, it saved me..❤️
10/10, thanks so much !
i thinks the first one is the best way to solve the problem
THANK YOU SO MUCH FOR THIS! VERY VERY HELPFUL! 💗 May you have more subscribers!
You are good
man you're the best
In 12:34, what if CaCO3 (Calcium carbonate), I will times to three or one)
I have a quiz later on analytical chem and I can't understand a thing hahahaa!!! Thank God for this!!! Hope that it can save me from doom nation😂
did it?
"I hope this video is helpful"
Dude very very helpful 😭😭😭 I wish I've discovered your channel when I was still in college ❤️
can you tell me what the solution for this question 👇
A 3.0 solution of aluminum sulfate Al2(SO4)3 Normality what the molarity????
Can you answer please I need it too much I have an exam tomorrow 🙏🙏🙏🤕🥺
50g of H2SO4 divided by 98g/mole is equal to 0.50mole divided by 15L of solution is equal to 0.33M. Normality = 0.33x2H=0.66N. Correct me if Im wrong.
I got 0.068N again. 50 / 98 = 0.5102. 0.5102 / 15 = 0.034. 0.034 x 2 = 0.068. Try dividing 0.5102 by 15 again. I believe you're missing a 0. I hope this helps :)
Thanks sir. It was very helpful
Wonderful explanation
you saved my life
list the following aqueous solutions in order of increasing boiling point:0.030M glycerine;0.020M KBr;0.030M Benzoic acid,hc7h5o2
can you answer this?plssss