LR(1) & LALR(1) Parsing Automaton

[@VictorAyswal]

You just saved my life for my test tomorrow. Thank you very much for this video.

[@tareqnasif4442]

after watching more than 10 videos , i just understand them from u . goood job , thnksssss

[@sundeeprayidi6238]

And now I will bunk my CD classes with swag. Thanks for the awesome explanation. Live long and prosper 🖖🏻.

[@Madalinos]

very very nice video, great work, keep going

[@Bigdasahjada]

Why don't we use transition of 'a' and 'b' on state I6 and I3 ? Because in lr(0) automata we make all the transitions for every item ! Please clear my doubt.

[@LeonsTerminal]

Those transitions would go to state already in the automata.
For I3 on 'a' would go to I3 again and I3 on 'b' would go to I4.
For I6 on 'a' it would go back to I6 and I6 on 'b' it would go to I7.

[@nashezbaernon]

Those should still be there. You need those transitions for the table.

[@zia6950]

Why on I3 and I6 you don't move to next state on " a " and "b"?

[@tryller007]

a and b are terminals, so there is nothing to move to.

[@mrkirby8622]

They should be there like the transition from I2 to I6 (a) - (I know it's been 4 years, meant for others who see this)

[@jorge-tutor]

great explanation, I finally understood both automaton in just 10 minutes! thank you

[@cristhiandavid1226]

I think i love you right now

[@pt8817]

Thanks for explanation. While transitioning the look ahead doesn’t change, but after transitioning while doing the closure the look ahead become the follow of the element having . In front. Why in I3 the look ahead of X -> .ax and X->.b is a/b while this is the closure of X-> a.X , a/b ? here is a /b as look ahead for X -> a.X is normal cause coming from the precedent state, but for the two others here follow of X should be $?

[@primitzisgate7]

if it is LL(2) we take the FIRST of the 2 first symbols after the one with the dot ????

[@ebichan_tw]

Thank you a lot, you saved my midterm!

[@tahiraslam1950]

Thank you sooo much :D finally i understand the concept behind Look Ahead......

[@mohammaddareer342]

amazing explanation

[@PanamaRobinZ]

Se que no me vas a entender pero...TE AMO HERMANO ERES EL PUTO AMO

[@sarazaanine626]

thank youuuu!

[@kamyexol8643]

Thank you so much this helped me a lot ~~

[@zia6950]

really great video for helping

[@19Pipe89]

Very well Explained!!

[@hasansakib3502]

black background use korechen kon software diye apu?

[@vladimirool]

Thank you! Nice teaching

[@simoneagliano1852]

Thank you, I have fix my ideas now

[@oggygodge]

Nice explanation

[@mirana7660]

SAVER, ISNT HE?

[@alitariq804]

effective explanation

[@swapnilmishra697]

between LR(0) AND LR(1) which is more powerful

[@selmanemohamed5146]

LR(1) i don't know why or how but i remember that the teacher told us so

[@flutterwind7686]

lr(0) has no concept of lookahead so its less powerfull (flexible)

[@pawe3039]

Thank you. Very helpful.

[@wasikhan6669]

Are you agreed with the concept that all LR(1) grammars are also LALR(1) grammars? Write your answer with the help of solid reasons.???

[@rikeshchhetri7590]

NICELY EXPLAINED

[@nikhilverma4976]

Thanks for the nice explanation

[@avlapak4525]

thanks