It’s always tricky to show everything clearly enough, especially when I want the question set out in exactly the same way you would get it. You could copy the reaction equations out so that you always have them in front of you as the video works through the calculation.
Y13 but the fact it’s an ionic equation isn’t as big a deal as you might think. It’s still about ratios. The acid-base titrations you do in y12 could be presented as ionic equations if we wanted.
This would have been more helpful if the bottom portion of the page was visible. Thanks
I’m sorry about that.
The middle section of this is unfortunately very hard to follow as the reaction equation is not visible.
It’s always tricky to show everything clearly enough, especially when I want the question set out in exactly the same way you would get it. You could copy the reaction equations out so that you always have them in front of you as the video works through the calculation.
Hi, why did you multiply the 25cm^3 sample by 4 and not 4.4 since wasn’t the original sample 110cm^3 and not 100cm?
No, the original 10cm3 sample was diluted 'to' 100cm3. So, 90cm3 of water was added and 10 cm3 became 100cm3.
Hi, is this a Year 12 or year 13 question? I am in year 12 and have not encountered titrations with ionic equations in any AS paper so far.
Y13 but the fact it’s an ionic equation isn’t as big a deal as you might think. It’s still about ratios. The acid-base titrations you do in y12 could be presented as ionic equations if we wanted.
Hello, may I ask what paper this is? Thank you so much for the video by the way. It helped immensely
Q8 AQA Paper 1 2020 - I'm glad the video was useful.
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hank you , this was useful
Glad it was helpful!