For the circuit shown in the figure, calculate (a) the current in the 2.00-Ω resistor and (b) the po

[@jmwjmw27]

Explanation at 2:52 was so much clearer than anything my professor ever said. Thank you so much, I can finally solve these types of problems

[@lilomimi94]

You made this so easy to understand! my professor ways were unclear!! thank youuu

[@guggystyle]

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[@meshalalmutairi5750]

what a Legend! saving Engineering students over the world.

[@johnnolen8338]

Great job. One thing that might help clarify the details a little, use the passive sign convention when writing KVL equations: If current enters an element via the element's positive terminal then the voltage across the element is considered to be positive, else it's negative. (Voltage drops are positive, voltage rises are negative.) Saves much writing of unnecessary minus signs, and it's easier to keep track of the proper direction of current. One other implication of the passive sign convention, power dissipated is positive whereas power delivered is negative.

[@apeerzada987]

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[@azmanazurah4133]

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[@stefhanyremigio1686]

Why did we solve for I6 in the second equation? and why did we solve for I4 in the third equation? Is there a specific reason or can we solve for any variable?

[@BogusQuacky]

Awesome! thanks!

[@alialsaedi9166]

Thank you!

[@guggystyle]

You're welcome!

[@jessicaleonard6849]

Great thank you!

[@murphyfudge7887]

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[@xikasprrzz3777]

Thanks.

[@anupama5646]

Thanks

[@ameerrifai4408]

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[@zhalehsad2023]

Hello, I sent you an email. And I asked you to solve a problem related to this question. Could you please do that ? Thank you !

[@josephguida5432]

Superposition.