What I really like about this channel after seen some videos and comments, is that this channel really tries to solve doubts and give replies to problems which many channel doesn't......... Thank u @AJSTUTORIAL
Well it is feasible. Don't be afraid by seeing such big powers *just follow the explanation in video n solve it*. Well the answer to your question is *256*. @akash_sonu #happytohelp #ajstutorial 🔥😎🤘
But that is the question 😅, n if the numbers are bigger than u have to follow the steps which i have explained in the video. #happytohelp #ajstutorial 😎🔥🤘
Sorry for the inconvenience. Your answer is correct *60*. We thought that it is 26*32 but your question is 26 raise to 32. So some misunderstanding happened. #happytohelp #ajstutorial 🔥😎✌️
I have took a *random number example* to find *mod*. Depending on sum you get in exam, you have to use your number and calculate *mod*. And it is 13^23 #happytohelp #ajstutorial 🔥🤙😎
whose right of neck is hurting after watching whole video? :D dude you could have saved me from this pain also, re-upload and correct video orientation
Well... This was my just second video on my channel , so, their are problem related to video orientation . I am busy with my job so I could not do anything about this now . Sorry #ajstutorial #keepsuporting 🔥🤙💪
You can actually do that. Just right click on your Home screen, then go to *graphics option*, then again go to *rotation option* and click on *rotate by 90 degrees*. #happytohelp #ajstutorial 🔥😎🤙
in your calculator go to BASE-N mode and in Dec type a-a/b*b Eg 147 mod 17 147-147/17*17 = 11 in Dec of BASE-N mode you will get 11 as answer OR in COMP mode of your calculator carry out simple division and then press shift fraction key to get answer in mixed fraction Eg: 147 mod 17 = 8.647058824 then shift fraction key 8 (11/17) here numerator is the answer => 11
What I really like about this channel after seen some videos and comments, is that this channel really tries to solve doubts and give replies to problems which many channel doesn't......... Thank u @AJSTUTORIAL
Thank u @Gudiya 🔥😎🤙
#happytohelp #ajstutorial
my neck enjoyed this
Sir huge respect 2 you , you are absolutely gem 💎
Sir this video really helped me where al other videos couldn't help me at all
Thank you so much sir ......🙏
So much respect and appreciate to you and your work. I even feel bad to use word 'video' (Instead I use word 'work' here) in your style of delivering
Thank you for your kind words.
If you like my videos please subscribe to my channel.
LINK : th-cam.com/users/ajstutorial
#happytohelp #ajstutorial 🔥🤙😎
Waahhhhh, subah mera paper, and I think it'll help me a lot
JazakAllah sir
I guess you spelled it wrong . It's *Arun* Sir
Exam ke ek din pehle*: Mai aur Mera dost appke bohot shukr guzar hai 🙏🙏
❤️🔥💪 #ajs_tutorial #subscribe
man your a life saver, Big Thanks from my whole squad !
no doubt
Thank you
#happytohelp #ajstutorial 🔥😎🤙
Great explanation. This is required in cryptography numericals.
Thanks you so much۔۔۔۔۔ main pichly ak ghnty se yh dhond rahi Thi
Sir you are amazing sir thank you 😊
thank you sir, been looking for this for a very long time
Thank u so much sir
love from Pakistan helped me a lot.
Keep sharing, keep subscribing .love from India 🇮🇳 🔥☺️✌️🤘😎 #ajs_tutorial
Good method
Works great
Thanks a lot
Absolutely Worth the time... Thank You
Thanks 🔥😎✌️
#happytohelp #ajstutorial
Fatte bhai ⚡️⚡️⚡️❤️🔥❤️🔥
Wow super sir thanks for sharing the video
Thanks Bro ur Videos are always the best !👍👍
Thank u 😊😊
Too awesome.....they never taught this in clg
Thanks 🔥😎🤙
#happytohelp #ajstutorial
anyone who need to find it urgently can use windows built in calculator but in exam you should follow the video method
Absolutely Georgeous 🥰
You are God ❤
bhai aap king hein
Thank you for this video helped me alot ❤️❤️
Thanks sir✨ I have my exams tomorrow
It helped me alot
Thank you so much
Thanks It will help me in INS
Thanks a lot❤❤
thank you so much!
nice bhaiya
thank you
Pls give me the solution of 37^32mod77 i tried with ur method but wont get the ans
love you bhai
Thank man👍🏻👍🏻❣️
Amazing 👏
Superrrrrrrrrrrrr
can someone use this method and tell me the answer for
216^2011 mod 3127
because i tried all these methods and answer isnt correct so anyone help!!!!!
nice
Awesome Video🙏
Thank you so much 😍👌🏼
Thanks for this.. though this is not feasible when dealing with powers of 2..
Like for eg 23^128 mod 287 ??
Well it is feasible. Don't be afraid by seeing such big powers *just follow the explanation in video n solve it*. Well the answer to your question is *256*. @akash_sonu
#happytohelp #ajstutorial 🔥😎🤘
@@AJSTutorial ah got it.. thanks again!
How i sove 3^97 mod 353 in binary form i tried but fail.
do u want help?
which step you failed in?
thanks mere dost
Awesome 👍
apko papa bol sakta hu bhai?
han bolskte ho 😂
iss se hard method hai kya
Maa chod diye bhaiyajii aapto 🔥🔥🔥💯💯💯💯💯💯💯💯
Hum bhi Guddu bhaiya k fan hai 🔥🔥🤙🤙😎😎😂😂.
#happytohelp #ajstutorial #subscribe
Thanks ☺️
Nice video
Bhaee 8 ka Square kyu lya hai? Usko tou humne 0 kardya tha na
Great way to clear doubts🙏🙏thanks bro!!
Thank u 🔥😎✌️
#happytohelp #ajstutorial
Brilliant video very usefull 😊
Can you please explain how to calculate 3^45 mod 353
Just follow the procedure as i have explained in the video. Answer to your question 3^45 mod 353 is *143*
#happytohelp #ajstutorial 🔥😎🤙
@@AJSTutorial but i get a decimal value for 13^16 mod 353 ...what to do? Should it be rounded off?
How did you get the answer..Can you please send me the steps 😅
Yes make it *round off* depending on 0.50 factor
#happytohelp #ajstutorial 🔥😎🤙
@@AJSTutorial but i get answer as 118
totally worth it
Thanks 🔥✌️
Power yar 💯
If I do this in online calculator ans shows 24
ita bada algo yaad nahi horaha paji
GODDDDDDDDD !!!!!!
I think it's GOOOD!!!! 😂😂🤘🤘
U can find this by formula M^e mod N
But that is the question 😅, n if the numbers are bigger than u have to follow the steps which i have explained in the video.
#happytohelp #ajstutorial 😎🔥🤘
Bhai 26^32 mod 77 ka value kya hai????
@@AJSTutorial I m getting 60 as answer
Sorry for the inconvenience.
Your answer is correct *60*.
We thought that it is 26*32 but your question is 26 raise to 32. So some misunderstanding happened.
#happytohelp #ajstutorial 🔥😎✌️
@@AJSTutorial no probs....Anyway ur teaching is way 2 awesome......
Thank u @rahul 🔥😎✌️
Toh 13^8 mod 287 kyon kiya??? Jab usse hum use hi nahi karre???
I have took a *random number example* to find *mod*. Depending on sum you get in exam, you have to use your number and calculate *mod*. And it is 13^23
#happytohelp #ajstutorial 🔥🤙😎
@@AJSTutorial I meant we could have taken 148^4 directly and then mod 287..!
10^29 mod 20711 anyone help
bro 15534
Your voice like Sanju Baba 😂
👍🏼
Bhai itna krna Hoga to direct kr skte h calcy se ..Kuch Naya banao bhai
Thik hai bhai kuch naya try karenge 🙏😅 #ajstutorial #happytohelp
Using scientific calculator only in 10 seconds
10 seconds🎉
whose right of neck is hurting after watching whole video? :D dude you could have saved me from this pain also, re-upload and correct video orientation
Well... This was my just second video on my channel , so, their are problem related to video orientation . I am busy with my job so I could not do anything about this now . Sorry #ajstutorial #keepsuporting 🔥🤙💪
Sorry I don't have a laptop that flips 90 Degrees...
You can actually do that. Just right click on your Home screen, then go to *graphics option*, then again go to *rotation option* and click on *rotate by 90 degrees*.
#happytohelp #ajstutorial 🔥😎🤙
@@AJSTutorial 🤣🤣
discard hi karna tha to calculate kyu kiya
2^97mod 131???
Follow the steps as explained in the video n answer to your question is 14
#happytohelp #ajstutorail 🔥😊✌️
U TOOK WRONG NUMBER IN LAST STEP SO U GOT DECIMAL NUMBER INSTEAD OF 8 U TOOK 9
baap video
How to calculate a mod(b) in one step
in your calculator go to BASE-N mode and in Dec
type
a-a/b*b
Eg 147 mod 17
147-147/17*17 = 11 in Dec of BASE-N mode
you will get 11 as answer
OR
in COMP mode of your calculator
carry out simple division and then press shift fraction key to get answer in mixed fraction
Eg: 147 mod 17 = 8.647058824
then shift fraction key
8 (11/17) here numerator is the answer => 11