Advanced Functions 7.6 Solving Quadratic Trigonometric Equations

Using factoring, substitutions of identities to get your equation in terms of one sine function we solve quadratic trig equations. Make sure that you always check the domain. Sometimes a solution that you get may be inadmissible because of the domain restriction.

[@diyonfernando5667]

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[@mshavrotscanadianuniversit6234]

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[@malik2xs]

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[@mshavrotscanadianuniversit6234]

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[@shinypearls5959]

Loved this video, helped me a lot, thank you 💕💕

[@tanya4706]

1:21 - doesn’t sin of 1/2 have a solution of pie - pie/6? from the 2nd quadrant

[@mshavrot_math]

You need to check the domain. In this case it is between -pi and 0

[@tanya4706]

@@mshavrot_mathin the 2nd quadrant, wouldn’t you still be able to solve it by changing pie into the negative pie?

[@mshavrot_math]

Definitely not. Look at the sketch that I drew to illustrate that there is no solution

[@saims.2402]

When you were doing question 8c, you wrote one of the x values as around 0.096, when my calculator said around 0.96, is that correct, and to find the value of x in cos x = 1/ root 3, you take the inverse cos of 1/ root 3 right?

[@mshavrot_math]

You are absolutely right about both.
It should have been 0.9553 and then the second answer is 2pi minus 0.9553 which is correct in the solution. Thanks for your correction.

[@metehanefealtug9210]

I hate math

[@mshavrotscanadianuniversit6234]

Hate is a strong word! Maybe immensely dislike??