anyone wondering why he had taken -180 is because the denominator is greater and tending to infinity making the expression 0 with negative sign which is tan180
So the logic used here is that.. since omega is a large value, ignore 10 and 100 so u will be left with tan^- (-(1/omega)) using the property of inverse trig tan^-1(- quantity) = 180+ tan^-(quantity) u will get 180+tan^-1(quantity) here quantity= 1/omega so it becomes 0 tan^-1(0) becomes 0 there is a - sign outside , so it will make the phase -180 deg
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anyone wondering why he had taken -180 is because the denominator is greater and tending to infinity making the expression 0 with negative sign which is tan180
When w infinity How phase angle -180? It should be -90 sir
Shi h dost-180 hi
Tan a/b=tan a-tan b
So the logic used here is that.. since omega is a large value, ignore 10 and 100 so u will be left with tan^- (-(1/omega))
using the property of inverse trig tan^-1(- quantity) = 180+ tan^-(quantity)
u will get 180+tan^-1(quantity) here quantity= 1/omega so it becomes 0
tan^-1(0) becomes 0
there is a - sign outside , so it will make the phase -180 deg
thanks 👍
Sir tan inverse of infinity is 90.. Why u have taken 180
Yaa
@@ssmbcraze4625 ye s
Phase angle -180 how it came sir
Sir how -180 it should be -90
Sir ye 180 kese aaya
-45 ana chiye