Use Code: 𝐒𝐏𝐀𝐑𝐓𝐀𝐍 for Maximum Discount. 📳𝐂𝐀𝐋𝐋 𝐍𝐎𝐖: 𝟎𝟗𝟓𝟔𝟎𝟔𝟐𝟒𝟐𝟒𝟕 for Enrollment Queries 📄All Star Pro Batch 🔗applink.adda247.com/d/Allstarpro 📄NBTS PRO -Based on NTA Latest Pattern 🔗applink.adda247.com/d/NBTSPROTestseries
Pa=p0A XA+ p0bxb 92x1/5+ 31x4/5 216/5= 43.2 sir 3 chapters revise ho gye ques bhi acche se solve ho gye confidence boost ho gya sir thankyou so much sir do like the comment guys iss baar AIR lake rhenge
Best class we are very motivated with this series ..bohot helpful hai ham sabhi baccho ke liye revision ke liye aur practice bhi horhi sath hi sath ❤is baar I wish jada se jada baccho ka selection hojyega ese hi consistency se padhte rhege to ...best series sir thank you so much ❤🎉
Ans 43.2. Sabka ek life to bantahai yaar apne seat keley aur apne sir ki mehnat ke liye 😊 Like for ur mbbs seat the person who likes this will get 100 percent seat in govt medical collage so do like ur seat 🎉🎉🎉🎉
Ans 43.2mm of hg... Start loving chemistry... Tysm sir... Sir pls blank pdf bhi de diya kro in questions ki... 😊 Amazing lecture... Guys like my comment taki sir blank pdf ka msg sir tk pahuche... ❤ Tysm sir
Jisne like nhi kara usko neet ki kasam aur apni AIR KI KASAM LIKE karke jana Xa=1/5 Xb=4/5 Pt = p'aXa + P'bXb = 92×1/5 + 31×4/5 = 216÷5 Pt=43.4mm of hg
Total mole = 1+4=5 Mole fraction of heptane =Xa=1/5 Mole fraction of octane =Xa=4/5 Ps = XaP⁰a +XbP⁰b =1/5×92+4/5×31 =43.2mm of Hg Sir pls series continue rkhiega Those ajj 700 to 800 hi people the but we promise ham regular rhega Completely depends on u sir😊
Best practices session ...❤ Ans - option 3 43.2❤ Please like ❤❤ may god fullfill yor wishes and ......... Whatever you want 😁 Please like kardo warna ......... Samaj jaao 😂
Ans of the day option C - 43.5 Bhut maja aya sir practise session m sare doubts nd ques solving complt hogai thnkq so much sir 🫶🏻❤️🔥 Bhaiyo aur behno agr aaj k session fhod diya to like jrur kre...😎
Under 500 rank aayegi like kr do yrr ♥️🧿 Answer of question of the day Psolution = P1X1 + P2X2 X1 is 1/5 and X2 is 4/5 Now by putting in formula the answer we get is 43.2 mm hg Thankuuu sooo muchhhh sirrr for this amazing lecture 😊❤ Apki vajah s marks increase ho re h aur confidence bhi increase ho ra h 😢🫂❤️🩹 Thankuuu veryyy muchhh 🫶🏻
P=P•Axa + P• Bxb 92×1/5+ 31×4/5 =43.2 mm of Hg Mr PINEAPPLE 🍍 Sir revision bht acha ho raha ha I hope ki app agge bhi aise he sara syllabus revise kra de with practice session Thanking you ❤❤❤
❤thank youuu thank youu so much sirrr jiiiiiii❤❤❤ harrr barrr bacha lete ho sirr jii❤ 🎉 Ek dil hai sirr jiii kitne baar jitogeee😍😍😍😍😍😚😚😚 really realllyyyy thank youuu soo much sirr jiii you r amazing 🍍🍍🍍❤❤❤❤
Thank you sirr for amazing practice session ❤🎉💯 Ans of the day is Pt=PA°XA + PB°XB =43.2mmHg (C) Sirr aap aase hi class regularly rakhye hum aake sath end Tak rahega is neet journey me❤
Thanku sir it's means alot meri journey ko bohot asan kardiya kabhi nhi socha tha chemistry padhne mein itna maja ayega and promise I Will make you proud ❤ Love you nd bhaiya ♥️🐼
QOD ANS: optn c 43.2mm of hg JO TRUE SPARTAN ARMY HAI WO JLDI LIKE KRO🙈 TQSM FOR THE BEST PRECTICE SESSION ON 12TH PHYSICAL CHEMISTRY💖💖 confidence badh gya abh 😄 TQ for all ur efforts❣
m1 = 1 mol ,VP1= 92 mmHg m2 =4 mil, VP 2= 31mm Hg X1 = 1/5= 0.2, X2= 4/5=0.8 VP solution= V1X1 +V2X2 = 0.2 x 92 + 0.8 x 31 = 18.4 + 24.8 = 43.2 Thank you Sir for doing a lots of hard work for us. So that we can do best in our exam. 🙏🏻🙏🏻🙏🏻
JISNE LIKE KIYA USKA SELECTION HOJAYEGA❤😅 Option 3) 43.2 mm of Hg PA=P°A.XA + P°B.XB [XA=1/1+4 = 1/5];[XB=4/1+4 = 4/5] PA = 92(1/5) + 31(4/5) PA = 18.4 + 24.8 PA = 43.2 mm of Hg Amazing session sir confidence boost hogya🙏🏼❤️
11 : 11 PE MAINE WISH KRAA H SBKA AIIMS ME SELECTION HOGA JO JO LIKE KREGA IS COMMENT PE ❤️ . . xa = no. Of moles of a ÷ total no. Of moles = 1/5 xb = no. Of moles of b ÷ total no. Of moles = 4/5 Pt = (P°a)(xa) + (P°b)(xb) Pt = (92)(1/5) + (31)(4/5) = 43.2 . . THANKYOUU SO MUCH SIR FOR SUPPORTING US IN OUR JOURNEY, WE WILL BE THANKFUL TO YOUU FOR OUR WHOLE LIVES💗🙏🏻 LOTS OF LOVE FROM YOURR PINEAPPLESSS TO YOUUUUU
Sir one question hai The normal boiling point of water is 373K . Vapour pressure of water at temperature T is 19 mm Hg . If enthalpy of vapourisation is 40.67Kj/mol , then temperature T will be A. 250 K B. 291.4 K C. 230 K D. 290K Ye please aap next class me solve karva dijiye . Bhot confusing sa h .
Given:- (P°A)=92 mm of Hg ➡️ nA =1 ➡️ xA= 1/5 (P°B)= 31 mm of Hg➡️nB= 4➡️xB=4/5 Soln:- Psol = P°aXa + P°bXb ➡️ 92×1/5+31×4/5 ➡️ 18.4+24.8= 43.2 mm Hg (3) option (Ans) Thank you Sir for amazing practice session have a well go through question solving.☺️ (Like karo Neet mein under air 1000 Lana hai😉)
Home work answer Toatal = mole 1+ 4 =5 Mole fraction of heptane xA = 1/5 Mole fraction of octane xB=4/5 Ps = XA P°A + XB P°B = 1/5 ×92 + 4/5 ×31 = 43.2 mmof hg ❤❤❤❤❤❤❤❤❤ Thank you so much sir 🍍
Very nice lecture ❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤❤❤❤❤❤❤❤❤❤❤
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43.2 mm Hg is answer of the question of day .
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Ans- [43.2 mm of Hg]
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43.2 is the answer
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Is it okay if i dont read ncert after oneshots? Like aabhar and raftaar seeies
@cupcake4798 yeahh because notes of ND sir is ncert based if uh want to read then uh can ..
Pa=p0A XA+ p0bxb 92x1/5+ 31x4/5 216/5= 43.2 sir 3 chapters revise ho gye ques bhi acche se solve ho gye confidence boost ho gya sir thankyou so much sir do like the comment guys iss baar AIR lake rhenge
43.5 is correct answer
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Like the comment if you want notes, pyq, rank boosting questions of this chapter.
Id bro
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Tnx bro I got it .Nice pdf
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43.2 answer
Thank you sir for amazing session
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Best class we are very motivated with this series ..bohot helpful hai ham sabhi baccho ke liye revision ke liye aur practice bhi horhi sath hi sath ❤is baar I wish jada se jada baccho ka selection hojyega ese hi consistency se padhte rhege to ...best series sir thank you so much ❤🎉
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43.2mm of Hg
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Ans 43.2.
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Question of the day
Ans :- Vapour pressure will be 43.2g
PoAxa + PoBxb =92*1/5+31*4/5 = 18.4 + 24.8 = 43.2
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Question of the day-- 43.2mmHg
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pT = p°A.xA + p°B.xB
.... Ans. : 43.2 mmHg
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Answer-
C (43.2)
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Ans -- 43.2 mm of Hg
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Ans. 43.2mm of Hg
Thankyou sir for amazing session
43.5.....❤ jo like karega usko aiims delhi milega.... ❤
MAUJ KAAT DI NITESH BHAIYA AAPNE❤️❤️🔥🔥SAARE QUESTIONS BAN RHE HAIN
Question of the day
43.2 mmHg
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Ans- 43.2mmof Hg
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❤"Aapse seekha Aapse jana , aapko hi guru mana"❤
Thankyou so much sir for this amazing session 😊😊
And ans is 43.2mm of Hg
Thank you sir
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Ptotal = P1X1+P2X2 =92×1/5 + 31×4/5 = 43.2 mm of hg ❤️❤️😍
Thankyou sir for this amazing lecture 🎉
Answer :c option 43.2mmhg
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AMAZING PINEAPPLE SESSION SIR!!!!!!!!! ❤❤🎉🎉
Xa=1/5, Xb=4/5 = 92×1/5 + 31× 4/5 = 92/5+ 124/5 = 216/5 = 43.2 ans. It's very helpful series 🎉❤ thanks a lot dear sir 🙏
Ans. 43.2 mmHg
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Ans 43.2mm of hg...
Start loving chemistry... Tysm sir...
Sir pls blank pdf bhi de diya kro in questions ki... 😊
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Tysm sir
Jisne like nhi kara usko neet ki kasam aur apni AIR KI KASAM LIKE karke jana
Xa=1/5 Xb=4/5
Pt = p'aXa + P'bXb
= 92×1/5 + 31×4/5
= 216÷5
Pt=43.4mm of hg
Answer is option C[43.2mm of hg] Awesome session bhaiya♥
Total mole = 1+4=5
Mole fraction of heptane =Xa=1/5
Mole fraction of octane =Xa=4/5
Ps = XaP⁰a +XbP⁰b
=1/5×92+4/5×31
=43.2mm of Hg
Sir pls series continue rkhiega
Those ajj 700 to 800 hi people the but we promise ham regular rhega
Completely depends on u sir😊
Ans (c) 43.2 mm hg❤❤
Thank you sir❤
X¹ is 1/5
ײ is 4/5
P=92×1/5+31×4/5
P= 43.2 🎉🎉🎉
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Ans is option (c): 43.2 mm Hg
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Ans - option 3 43.2❤
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P= P°(A)X(A) + P°(B)X(B)
=92×1/5 + 31×4/5
=43.2mm Hg
C option
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Answer isC. 43.2 it is amazing session sir thanks for this session..it is helpful to lot of students who are dependent on TH-cam only
43.2mm of hg ... thank you so much sir for this amzing series ❤❤
hare krsna sir 43.2 ❤❤❤❤❤❤❤❤❤❤
Ans of the day option C - 43.5
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Ans option c 43.2
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Chem ab easy lg rhi h
ans= 43.2 mm of Hg
ye session dekh ke
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Answer of question of the day
Psolution = P1X1 + P2X2
X1 is 1/5 and X2 is 4/5
Now by putting in formula the answer we get is 43.2 mm hg
Thankuuu sooo muchhhh sirrr for this amazing lecture 😊❤
Apki vajah s marks increase ho re h aur confidence bhi increase ho ra h 😢🫂❤️🩹
Thankuuu veryyy muchhh 🫶🏻
43.2 mm hg ans
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Ans- 43.2 mm of hg
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Ans : 43.2 mm Hg
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P=P•Axa + P• Bxb
92×1/5+ 31×4/5
=43.2 mm of Hg
Mr PINEAPPLE 🍍
Sir revision bht acha ho raha ha
I hope ki app agge bhi aise he sara syllabus revise kra de with practice session
Thanking you ❤❤❤
Thankyou so much sir. Kaafi kuch new sikhne ko mila.
Ans (c) 43.2 mm hg ❤❤
Answer: c) =>Psolution= P°A xA + P°B xB= 92×1/5 + 31×4/5 = 43.2mmhg
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1:54:27 option (3) 43.2 mm of Hg
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43.2 mm of Hg🤩
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Ans of the day is
Pt=PA°XA + PB°XB
=43.2mmHg (C)
Sirr aap aase hi class regularly rakhye hum aake sath end Tak rahega is neet journey me❤
Thanku sir it's means alot meri journey ko bohot asan kardiya kabhi nhi socha tha chemistry padhne mein itna maja ayega and promise I Will make you proud ❤ Love you nd bhaiya ♥️🐼
QOTD: Psoln=Pa+Pb
. =Poa*Xa+Pob*Xb
. = 92*1/5+31*4/5
. =43.2 i.e. C option 43.2mm of Hg
Sir abb toh confidence supar se upar hogaya hai thanku soo oo much sirr ❤❤❤
QOD
ANS: optn c 43.2mm of hg
JO TRUE SPARTAN ARMY HAI WO JLDI LIKE KRO🙈
TQSM FOR THE BEST PRECTICE SESSION ON 12TH PHYSICAL CHEMISTRY💖💖
confidence badh gya abh 😄
TQ for all ur efforts❣
FIRST OF ALL THANK YOU SO MUCH SIR❤️✨🙌, QUESTION OF THE ANSWER IS 43.3mmhg .
m1 = 1 mol ,VP1= 92 mmHg
m2 =4 mil, VP 2= 31mm Hg
X1 = 1/5= 0.2, X2= 4/5=0.8
VP solution= V1X1 +V2X2
= 0.2 x 92 + 0.8 x 31
= 18.4 + 24.8
= 43.2
Thank you Sir for doing a lots of hard work for us. So that we can do best in our exam. 🙏🏻🙏🏻🙏🏻
Option C hai.... (43.2)
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Ans [43.2 mm of hg]
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43.2 is the answer sir
JISNE LIKE KIYA USKA SELECTION HOJAYEGA❤😅
Option 3) 43.2 mm of Hg
PA=P°A.XA + P°B.XB
[XA=1/1+4 = 1/5];[XB=4/1+4 = 4/5]
PA = 92(1/5) + 31(4/5)
PA = 18.4 + 24.8
PA = 43.2 mm of Hg
Amazing session sir confidence boost hogya🙏🏼❤️
43.2 is the answer Jo bhi ND sir ka favourite hoga wo like karenge 💫😊. Thank you for excellent practice session 💯✨❤️
Correct option is C- 43.2 mm of Hg
Sir Thankyou for the session ❤❤
Consistency is the key🗝️... Show your consistency here
👇 Good luck👍🏻
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• QUESTION OF THE DAY-
FROM: P= P°Xa + P°Xb
= 92×1/5 + 31×4/5
= 48.3 OPTION C✅
nice lecture sir it will very helpful for me for chemistry ❤❤
11 : 11 PE MAINE WISH KRAA H SBKA AIIMS ME SELECTION HOGA JO JO LIKE KREGA IS COMMENT PE ❤️
.
.
xa = no. Of moles of a ÷ total no. Of moles = 1/5
xb = no. Of moles of b ÷ total no. Of moles = 4/5
Pt = (P°a)(xa) + (P°b)(xb)
Pt = (92)(1/5) + (31)(4/5)
= 43.2
.
.
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Sir practice sessions jyada rakha kijiye bhut help ho jati h inse❤❤❤❤❤
Amazing session sir........💯❤🔥
43.2 mm Hg is answer of the question of day..
43.5 is the ANSWER...THANK U SIR 🍷🎉
PT --> 92 × 1/5 + 31 × 4/5
--> 18.4 + 24.8
--> 43.2 mm Hg
Ans 43.2 mmHg
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Any akashiyan here do like
Answer is 43.2
❤❤❤❤❤❤
43.2(Ans)
Sir one question hai
The normal boiling point of water is 373K . Vapour pressure of water at temperature T is 19 mm Hg . If enthalpy of vapourisation is 40.67Kj/mol , then temperature T will be
A. 250 K
B. 291.4 K
C. 230 K
D. 290K
Ye please aap next class me solve karva dijiye . Bhot confusing sa h .
Superb session sir😊❤Thank you for ur efforts 😊✨
Session starts at 5:20
[Ans]-43.2 mm Hg
Ans- 43.2mm of Hg (c)
Thankyou sir for the session
Given:- (P°A)=92 mm of Hg ➡️ nA =1 ➡️ xA= 1/5
(P°B)= 31 mm of Hg➡️nB= 4➡️xB=4/5
Soln:- Psol = P°aXa + P°bXb
➡️ 92×1/5+31×4/5
➡️ 18.4+24.8= 43.2 mm Hg (3) option (Ans)
Thank you Sir for amazing practice session have a well go through question solving.☺️
(Like karo Neet mein under air 1000 Lana hai😉)
Answer:- 43.2 mmHg
Sir plz solution b provide krdena aj vale question k❤❤
Jis jis ko solution b chahiye vo like kre😅😅
Thnku so much sir for session
Nyc sess❤
Ans:C 43.2 mm of Hg
Tq sir
43.2 mm of Hg is the answer. Pineapple 🍍🍍🍍
Home work answer
Toatal = mole 1+ 4 =5
Mole fraction of heptane xA = 1/5
Mole fraction of octane xB=4/5
Ps = XA P°A + XB P°B = 1/5 ×92 + 4/5 ×31 = 43.2 mmof hg ❤❤❤❤❤❤❤❤❤
Thank you so much sir 🍍
Very nice lecture ❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤❤❤❤❤❤❤❤❤❤️❤️❤❤❤❤❤❤❤❤❤❤❤
Answer to question of the day :
C) 43.2 mm of hg
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Answer: 3) 43.2 mm of Hg