VCE Specialist Maths HARDEST Questions - Calculus

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  • เผยแพร่เมื่อ 29 ม.ค. 2025

ความคิดเห็น • 3

  • @hardstuck6200
    @hardstuck6200 ปีที่แล้ว

    at 4:42, shouldn't arccos(1) = 0?
    thus leaving us with pi(0--pi) = pi(pi) = pi^2, as opposed to 2pi^2?

    • @MathsWithMrLim
      @MathsWithMrLim  ปีที่แล้ว +2

      You are correct hardstuck! The answer of 2pi^2 is correct, but i have 2 errors in the method.
      There is an x missing in the square bracket, which should have been x.arcos(x/2) (from part a.).
      Then error with arcos(1) you mentioned. These errors happen to cancel to give the correct answer.

    • @hardstuck6200
      @hardstuck6200 ปีที่แล้ว

      ​@@MathsWithMrLim yep, I see that now. thanks for all the videos you guys do!