I am really enjoying your video series and it's given me lots of ideas -- thank you! The only thing I have to give back is that for the mid-position derivation, applying Millman's theorem at the inverting and non-inverting terminals, then equating those expressions, leads directly to v_out = v_in symbolically.
I am really enjoying your video series and it's given me lots of ideas -- thank you! The only thing I have to give back is that for the mid-position derivation, applying Millman's theorem at the inverting and non-inverting terminals, then equating those expressions, leads directly to v_out = v_in symbolically.
That's a great idea! Thanks.
Great ideo as always! thanks!
Thanks.
perfect video!
Thank you!