Power system angular stability

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  • เผยแพร่เมื่อ 28 พ.ย. 2024

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  • @viniciuschrist2690
    @viniciuschrist2690 ปีที่แล้ว

    I really liked your video, straightforward explanation and nice analogy with the horse-spring-weight example.

  • @arch0049
    @arch0049 3 ปีที่แล้ว +3

    Thanks. I have started a career in electrical transmission (utility control). This video is a great resource in addition to my textbooks. I am definitely going to watch some more of your content.

    • @snoopingasusualisee3903
      @snoopingasusualisee3903 2 หลายเดือนก่อน

      What books do you recommend for a college student looking to break into industry 😅

    • @arch0049
      @arch0049 2 หลายเดือนก่อน

      @@snoopingasusualisee3903 EPRI Manual. It is free online. Purchasing a hard copy can be a bit of a pain. They are not cheap, and usually purchased by your employer, so it is not like there is a glut of them out there.
      Pretty standard AC Theory textbook. You can find good ones for free to check out your local library. Not much has changed in AC theory (at least at the level we use it) in like 60-70 years. So there are free .pdf's of old textbooks online you can legally download.
      If you want to spend money there are classes and online cluster packets. The NERC (federal license) exam is called Transmission Operator or Reliability Coordinator (reliability coordinator is a higher certification). Make sure any classes and packets you sign up for are tailored to those tests not the generation operator exams.
      And Bismark State College has an online 2 year program with pretty much guaranteed job placement.
      The most important thing you can do is figure out if your local transmission grid operator (typically your power company) hires people directly from the outside, with no experience and such.
      I worked for my local public transit agency as a light rail supervisor. Since the trains are electric, and run on high voltage I had relevant work experience. Many company HR departments would say that was NOT relevant.
      So do not go all in only to find out your local company or the company where you want to move will not even accept your application.
      Good luck.

  • @donberg01
    @donberg01 2 ปีที่แล้ว +1

    Love your explanations w/great graphic representations! Clear to the point tutorials! TX

  • @yxmati
    @yxmati 3 ปีที่แล้ว +2

    Hello Mr. Schett! Thank you very much for uploading the series on power systems engineering. However, as far as I can see, you've overlooked something here. The mistake you make is based on the assumtion that power line angle stability is equivalent to rotor angle stability, which it is not from my point of view.
    For an ideal power line & synchronous machine you'll have following formula:
    P = U1*U2/X*sin(theta)
    In case of a generator, U2 will be the more or less constant grid voltage & U1 the rotor voltage (assumed to be constant as well). Therefore, your calculations are correct. However, in case an electric line where U1 might be the voltage deep inside the grid (constant), there is no reason to assume that U2 is a constant in theta. Increasing theta will decrease U2, and at some tipping point U2 will decrease faster than sin(theta) increases -> power is at its maximum. The angle at which this happens is !not! 90° but a function of the load angle (solely). In order to calculate it, you'll have to find an equation U2=f(P,load angle). Therefore, it is convenient to use the equation of an ideal power line: U2 = U1*cos(beta*L)-j*I1*Zw*sin(beta*L)...Depending on which coordinate system you use, you'll get a different sign. Substitute I1 with some expression of P & load angle, this will yield a quadratic equation in U2. Solve it and you'll end up with a term U2=f(P, load angle) which can be plugged into the first equation P = U1*U2/X*sin(theta). This will yield a curve P(theta) similar to yours, but with the essential difference that theta(P_max) is around 50-60° , depending on the load angle.
    Best regards,
    Matthias Maier

    • @georgschett801
      @georgschett801  3 ปีที่แล้ว +2

      You are correct, therefore (as far as I remember...) I said in the video that for simplification reasons I assume that the voltage and the angle include the rotor angle. In reality the synchronous reactance of the generator plays a major role for both, the angle and the voltages. Therefore as you say, the maximum angle in the system will be 30 - 60 and not 90 because the additional angle between the generator terminals and the induced generator voltage has to be considered. Thanks for your valuable comments!

  • @ali198642
    @ali198642 4 ปีที่แล้ว +7

    Excellent work THANK YOU... I paid for degree and I STILL looking for information to understand!!!

    • @georgschett801
      @georgschett801  4 ปีที่แล้ว

      Thanks for your feedback. You could support by sharing the videos in your community.

  • @raul_mrtnzz_
    @raul_mrtnzz_ 18 วันที่ผ่านมา +1

    Nice video!

  • @ahmedimamovic2666
    @ahmedimamovic2666 5 ปีที่แล้ว

    Great explanation, please keep making this kind of videos.

    • @georgschett801
      @georgschett801  5 ปีที่แล้ว

      Sure, Ahmed, thanks for your feedback.

  • @MagneManet
    @MagneManet ปีที่แล้ว

    Hello Schett, great video. Just wonder if there is an intuitive way to understand why active power depends on a certain phase angle between source and load?

    • @georgschett801
      @georgschett801  ปีที่แล้ว

      Hello Magnus, thanks for the fb! I am working on such a video, will be published soon. You can think of two magnets. Both are mounted on the same axis in the middle of the magnet. As long as there is no torque applied on the magnets, they will be oriented in parallel however with N and S pole in opposite direction. One magnet is the rotor field, the other one is the field induced by the stator currents. As soon as there is a torque, the angle between the rotor and the stator field will increase. Applying torque on a rotating system is equal to provide active power. I hope this helps a bit.

    • @MagneManet
      @MagneManet ปีที่แล้ว

      @@georgschett801 Thanks, yes absolutely, cheers :)

  • @felipe_dlt
    @felipe_dlt 4 ปีที่แล้ว

    Excellent work! Regards from Argentina.

    • @georgschett801
      @georgschett801  4 ปีที่แล้ว +1

      Thanks for your kind feedback. Please share it with your connections for me to get visibility in the community. All the best!

    • @felipe_dlt
      @felipe_dlt 4 ปีที่แล้ว

      @@georgschett801 It was the first I did when a finished the video.

  • @vaibhavpatil-mj5zj
    @vaibhavpatil-mj5zj 2 ปีที่แล้ว

    Thank you sir. What is the direction of torque. Same with rotation of rotor or opposite it

    • @georgschett801
      @georgschett801  2 ปีที่แล้ว

      It depends on the power delivery: With power out, the torque has the same direction as the rotation and vice versa.

  • @dubol07
    @dubol07 4 ปีที่แล้ว

    I appreciate your video. However, regarding the formula @7:00, is V^2 the difference between the source and terminal voltage squared, or is it one of those voltages squared? If it is one of them, which one?

    • @georgschett801
      @georgschett801  4 ปีที่แล้ว

      Good question. The assumption is, that both voltages are equeal in magnitude but different in phase angle. This is the key point. The torque establishes the phase angle and when you have torque you provide real power.

    • @dubol07
      @dubol07 4 ปีที่แล้ว

      @@georgschett801 thanks for your response. So then if I understand correctly, if we took into account the voltage drop due to impedance on the transmission lines and probably source stator windings, then instead of V^2 we shall have V source multiplied by V Terminal (Vs * Vt). Is this reasoning correct?

    • @georgschett801
      @georgschett801  4 ปีที่แล้ว

      @@dubol07 Perfect!!

  • @ismailbinmail1956
    @ismailbinmail1956 4 ปีที่แล้ว +1

    sir, i want to ask one more question please. so what is exactly the rotor angle stability? i mean what angle exactly? angle between what and what? because i read and see another video and i am confused now. please help

    • @georgschett801
      @georgschett801  4 ปีที่แล้ว +1

      It is the angle between the inner induced voltage of the synchronous generator and the outer voltage you can measure at the terminal of the generator. I am not sure where your confusion comes from. You may write me a mail: georg.schett@ecsp.ch

    • @joseluisblanco8074
      @joseluisblanco8074 4 ปีที่แล้ว +1

      @@georgschett801 I think it´s a straightforward question. It may not seem that evident that the angle (in the time domain) between terminal voltage and induced e.m.f. is the same as the angle between stator and rotor magnetic fields (electrical degrees).

  • @ismailbinmail1956
    @ismailbinmail1956 4 ปีที่แล้ว

    great explanation, but sir im still confuse, please answer. in 11:37 you say that "and you can see the phase angle between the line ends are still well below 90 degrees"
    pleasee tell me which one is the phase angle, helpp

    • @georgschett801
      @georgschett801  4 ปีที่แล้ว

      you see the 3 sinusoidal voltage curves of one line end and very close by, with a slite delay the 3 other curves. The delay at the instant you are pointing to is a few miliseconds (1 or 2 ms if I remeber well). The time delay is called the phase angle (or the delay angle or angle between the phasors) between both line ends. For 90 degrees you would need a time delay of 5 ms, enough to loose stability.

    • @ismailbinmail1956
      @ismailbinmail1956 4 ปีที่แล้ว +1

      @@georgschett801 thankyou sir!

  • @SoherNasr-u3v
    @SoherNasr-u3v 5 หลายเดือนก่อน

    Please , I think there is a mistake in the last two minutes, or may be the mistake in my understanding.

    • @georgschett801
      @georgschett801  5 หลายเดือนก่อน

      OK, thanks! But I am not aware of a mistake, can you please let me know?

    • @SoherNasr-u3v
      @SoherNasr-u3v 5 หลายเดือนก่อน

      @georgschett801 First, thank you very much for your interest. at the minute of 14:12, you said ( I open the breaker, and you can see now is how much this angle between the sending end and receiving end has been decreased) ,
      you said before when adding the capacitor, the angle will decrease, so when we remove the capacitor, the angle is supposed to increase, or what?
      Or you may be mean when you open the breaker of the second line and not the breaker of the capacitor , is this right ?

    • @georgschett801
      @georgschett801  5 หลายเดือนก่อน

      @@SoherNasr-u3v I guess I see your point. When the breaker is closed, the capacitor is short circuited, i.e. not in. Only when the breaker is open, the capacitor is in. I hope this clarifies

    • @SoherNasr-u3v
      @SoherNasr-u3v 5 หลายเดือนก่อน +1

      @georgschett801
      You really added valuable information to me. Thank you very much 😊

  • @chinniahshanmugam2733
    @chinniahshanmugam2733 3 ปีที่แล้ว

    Excellent I required a little more explanation and exposure could you help me...Electrical Safety Inspector

    • @georgschett801
      @georgschett801  3 ปีที่แล้ว

      Sure, let me know your questions / suggestions. You can contact me by mail on georg.schett@ecsp.ch