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Nice 👍
U r doing great job sir. Keep it up❤❤❤
Thank you sir ❤
A+d = 1st mean
Dai yo (1.c) maa bujinaa k maile 7:46 😢😅
If a, b and c are AP then we can write b-a= c-b use this concept
Dai opt ko trignometry padhaunu na
पढाईसकेको छु, सबै Trigonometry 9 र 10 दुबैको, playlist मा गएर चेक गर्नुस ।
1.c) Answer: k, k²+1 and k+6 are in A.PSo, k²+1 = k+k+6/2. {A.M=a+b/2}2(k²+1) = 2k+62k²+2 = 2k+62k² - 2k -4 =02(k² -k -2 ) =0k² - k -2 =0/2k² - k(2 -1) - 2 =0k² - 2k + k -2 = 0k(k -2)+1(k -2)=0(k+1) (k-1)=0Either, Or,k+1=0. k -2=0k= -1. k= 2 Therefore,the value of k is -1,2
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Nice 👍
U r doing great job sir. Keep it up❤❤❤
Thank you sir ❤
A+d = 1st mean
Dai yo (1.c) maa bujinaa k maile 7:46 😢😅
If a, b and c are AP then we can write b-a= c-b use this concept
Dai opt ko trignometry padhaunu na
पढाईसकेको छु, सबै Trigonometry 9 र 10 दुबैको, playlist मा गएर चेक गर्नुस ।
1.c)
Answer:
k, k²+1 and k+6 are in A.P
So,
k²+1 = k+k+6/2. {A.M=a+b/2}
2(k²+1) = 2k+6
2k²+2 = 2k+6
2k² - 2k -4 =0
2(k² -k -2 ) =0
k² - k -2 =0/2
k² - k(2 -1) - 2 =0
k² - 2k + k -2 = 0
k(k -2)+1(k -2)=0
(k+1) (k-1)=0
Either, Or,
k+1=0. k -2=0
k= -1. k= 2
Therefore,the value of k is -1,2
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