8.7 Non-Homogeneous Linear Systems- Undetermined Coefficients

[@banabachung4490]

Thank you! I was stuck doing these kind of problems for hours until I saw this^^ It was very clearly explained.

[@avibank]

These kids are so lucky! Best teacher in the world.

[@arnav492]

Thank you very much. I had been struggling with this concept for a long time and couldn't find any videos that clearly described it until I came across yours; it's been extremely useful!

[@Hi_Brien]

Thanks, this is much more digestible than lecture

[@SoumilSahu]

I love you, thanks so much for this. I never really understood how to choose X_p until I watched this.

[@nhiphan4505]

Thanks so much for such clarification and easy-to-follow example

[@queenstrategy4790]

Amazing work! Really cleared up how to do this! Thank you so much

[@weareprayingforthelost]

Thank you for your work

[@La_illah_ila_allah2]

3:57 what was the step

[@luckymkupa4900]

Thank you ,you really save my life

[@Sunny452]

I couldn't get one thing. How did you find out a1 & b1 value of the particular solution? You didn't show the process. Please help me out.

[@alanh2414]

Great example. Thanks!

[@fadoobaba]

also in the last example (unsolved), if the general solution already has that form e^5t, we will have to multiply every term of our proposed particular solution by t, I think.

[@cht5086]

@mrgonzalezWHS But the thing I dont understand: base on the book advanced "engineering mathematics"sixth edition on the page 615-chapter 10-4 for this part it says if we have for example [-2e^(-t)+1 and e^(-t)-5t+7 ] the Xp will be=(a3,b3)e^(-t)+(a2,b2)t+(a1,b1) this part I understand but it says if we had instead of e^(2t) instead of e^(-t) then Xp would be =(a4,b4)te^(2t)+(a3.b3)te^(2t)+(a2.b2)t+(a1,b1). But why is that!? I dont get it.at the end of this video for your ex of e^5t says something els!?

[@cht5086]

Is that depends on our Xc and overlaps?

[@fadoobaba]

what about phase diagrams of these systems?

[@gngh8160]

why did you set ( a1 b1)= (0 0 )

[@gabrielaportillo299]

because when you take the derivative of the chosen particular matrix, you get a matrix of (0 0)

[@janaSdj]

Thanks sir. Very helpful....❤️

[@awesome_gift7839]

Thank you so much!

[@cht5086]

I am studying "advanced engineering mathematic" for the exam and it was 4 hours confused and I was trying to find out what the (A)(Xp)+F(t) should be equal to? and then I remembered on youtube I might have chance to find out the answer, then your video pops up,I watched it and I learnt that should be equal to derivative of Xp. Thank you for your very helpfull video. God Bless you guys

[@techflier7442]

Very very helpful!

[@perspicuous-tube9264]

This was so helpful.

[@KBostanoglu]

Thank you this is great 👍👌

[@aryabarman1345]

thanks a lot sir

[@MRAXELGRINDER]

GREAT

[@theabdu500]

Thank you so much

[@kizitonyaranga4275]

sir. how do we we go about this one. dx1/dt = 4x2- 3x1 +2 & dx2/dt =2x1- x2 + 2

[@fadoobaba]

Thank you!

[@mathlover663]

Thank you sir

[@8Aboudi8]

I appreciate you explaining all this but I wish you would dumb it down a bit.