Recursion smjh nhi aaya tha..toh shradha didi ki dekhne k baad code with h arry pr dekha vha bhi nhi aaya phir codebios pr dekha,, phir dobara yhi aagyi,.. or ab perfect smjh aagya... you are best didi ❤
32:50 def check_num(n): if n%2 == 0: print("this is an even number") if n%2 != 0: print("this is an odd number") n = int(input("enter num: ")) check_num(n)
32:41 cal_fact(81) def cal_evod(num): if(num%2==0): print("the remainder is",num%2,",","THIS IS AN EVEN NUMBER !") else: print("the remainder is",num%2,",","THE NUMBER IS ODD !") cal_evod(84)
32:40 def chkodd_even(n): if n%2 == 0: return "EVEN" else: return "ODD" n = int(input("Enter a number:")) print(chkodd_even(n)) INPUT: Enter a number:5 OUTPUT: ODD
55:00 n=int(input("Enter Number To Calculate First N Natural Nos= ")) def calsum(n): if n==0: return 0 else: return n + calsum(n-1) sum=calsum(n) print("Sum of First",n,"Natural Numbers = ",sum)
14:32 def calc(a,b,c): sum = a+b+c avr = sum/3 print(avr) calc(int(input("enter a first value")),int(input("enter a secound value")),int(input("enter a thred value")))
55:00 # sum of first n natural number using recursion n = int(input("Enter a number ")) def sum1(n): if (n ==0): return 0 return n + sum1(n-1) print(sum1(n)) # write a recursion function to print all elements in list list =[53,88,43,77,12,88,33] def fun(list, n): if (n == len(list)): return print(list[n], end= " ") fun(list, (n+1)) fun(list, 0)
Please continue this series of tutorials with SQL (MySQL) so that projects using database can be created. This will be useful as it will use some dataset libraries like Numpy or Matplotlib and projects can be made.
@@Jeevan-gj6wj if you call the function by assigning its value to a variable. then it stores the final output of the function. basically if u print() then the value will be directy gets printed. if you want to use the output further u should return it
Hi Shrahda, The way you teach is really helpful . Thanks a lot . One thing i just wanted to say that factorial of any num is not like 1*2*3*...*num ,it should be num*....*3*2*1 . I know both will give same result but logic will get changed and i believe correct logic does matter even though both logics are giving same result .My intention was not to crrect you as you know many things better than me, here i just wanted to provide my opinion . Thank you....😊
You can do the same by this method also: def oddeven(): num=int(input("Enter the number:")) if num%2==0: print("THIS IS AN EVEN NUMBER") else: print("THIS IS AN ODD NUMBER") oddeven() good work anyway
i am following you since last 4 years. You deserve Bharat Ratna for your free contents. which is infinite times useful than any paid content available in india..
key topic with time stamp :----> 00:01 Functions in Python are blocks of code that can be reused. 02:02 Functions reduce redundant code and improve reusability. 06:12 Understanding function calls and parameters in Python. 08:09 Using functions reduces redundancy and makes code more efficient. 12:13 Functions in Python can be created with or without parameters and return values. 14:17 Functions offer a way to encapsulate code for reuse. 18:06 Understanding built-in and user-defined functions in Python. 19:58 Understanding default parameter values in Python functions 24:04 Creating functions to print lists with proper formatting 26:09 Understanding functions and recursion in Python 30:35 Introduction to functions and recursion in Python 32:36 Recursion in Python 36:10 Recursion is used to print numbers in a function call 37:55 Explaining recursion in Python with a specific example 41:39 Understanding the call stack in Python. 43:29 Recursion creates layers of function calls 46:59 Understanding the concept of recursion and factorial in Python. 49:04 Understanding recursion and its application in programming 52:51 Understanding recursion through the factorial function 54:40 Understanding recursion and writing recursive functions in Python. 58:29 Understanding recursion in Python 1:00:41 Understanding recursion in Python thanks
def check_even_odd(): num = int(input("Enter a number: ")) if num % 2 == 0: return "Even" else: return "Odd" result = check_even_odd() print(f"The number is {result}.")
I literally learnt this entire series in one day! simple straightforward. also my previous coding exp. of C++ java and c# helped, but python is so simplistic as compared to them! no need for semicolons also :P ; bas real project me impliment karna hai aur bekar logo k saath kam karne na mile bas yahi dua h.
# write a recursive function to calc the sum of first n natural numbers. n = int(input("enter the value of n:")) def sum(n): if(n==0): return n else: return n + sum(n-1) print(sum(n))
Tried this pattern printing out (Call Stack) def show(n) : if n == 0 : return while n >= 0: print('*' * n) break show(n-1) if n == 1 : pass else : print('*' * n) show(10)
i liked......... you sow that line of great swami vivekanand ji . It is very beautiful way to encourage to student that seeing your python lecture...... if some student seen title and they thought it is difficult of chapter 6 that lines you sown on screen it make inspire ............. your teaching style is very cool apna collage..😇
@@Jeevan-gj6wj Good question. In that case, it wasn't necessary to use "return" because we were directly printing the average. However, it's generally a good practice to use "return" in programming. If you're returning a value, store it in a variable and then print it..
HOMEWORK QUESTION # WAF such that if your input is odd it will print odd and if the input is even then it print even def num(a): if(a%2==0): print("even") else: print("odd") num(2)
# write a recusrive function to print all the elements in a list. r = int(input("enter the size of the list:")) i = 0 def print_list(l,i): if (i>=r): return else: print(l[i]) print_list(l,i+1) l = [] for t in range(r): o = input("enter the elements:") l.append(o) print_list(l,i)
# WAF to print the elements of a list in a single line(list is the parameter) numbers = [2,3,4,5,641,2,3,4,5,6,78] def single_line(list): for items in range(len(list)): print(list[items], end = " ")
Hello all This one the best python basic lecture you will ever get, In the entire video she never asked for subscribe or like. Let’s encourage her to do more courses like this and help crores of students and learner’s. Keep up the good work Shraddha and keep on helping people.
print("please enter any number ") n=int(input()) def eorodd(n): if(n%2==0): print(n,"is an even number") else: print(n,"is an odd number") return eorodd(n)
Hi Shradha, Thank you for the series, its really helpful, the words spelled from your voice, is effective to place in our mind, but yes we have to do lots of practice. 2ndly Can you create a vision or direction towards IT-Admin switching to DevOps platform , for them how you will take the python as a scripting language, as a DevOps Admin, not like a developer/coder. Please create a video series on this.case studies or scenario based tutorials please, so the we can clear the basic concepts which is used in day to day life in companies (playing With AWS,Docker,K8 and a lot, for Automation). Waiting for it.
def odd_or_even(num): if num % 2 == 0: print(f"{num} is even") else: print(f"{num} is odd") odd_or_even(7) in this code we can take the number by input keyword and can place it in the place of num in the function. like num = int(input("Please enter the number: ") and then can write function as written above. This time we need not to call function again.
def num_even_or_odd (Num): if Num %2 == 0: print ("even number") else: print ("odd number") Num = int(input("type a number - ")) print (num_even_or_odd(Num))
32:40 homework problem num=int(input("enter your number-")) def odd_even(n): if n%2==0: state="even" else: state="odd" return(state) print(odd_even(num))
"Thank you so much for your detailed explanation-it really helped me on my Python journey. Please keep making more Python videos in the future. You're amazing!"
![[Live] : ONE 169 วันนี้!! "อนาโตลี vs อูมาร์"](http://i.ytimg.com/vi/IK3YZVWuFJg/mqdefault.jpg)
32:55
n = int(input("enter your num:"))
def odd_or_even(n):
if(n%2 == 0):
print("EVEN")
else:
print("ODD")
odd_or_even(n)
Great bro 👍
def input_num():
num1 = int(input("Enter any one number"))
if num1 % 2 == 0:
print("even")
else:
print("odd")
input_num()
your code is showing an error
def odd_even():
n = int(input("enter number:"))
if n%2 == 0:
print("EVEN")
else:
print("ODD")
odd_even()
n= int(input("Please Enter a number: "))
def checker(a):
if a % 2 == 0:
print("EVEN")
else: print("ODD")
checker(n)
The best teacher i have ever seen. Ap bohot logon ki dua lerahi ho didi
Please ma'am after completing this series please go with Flask or Django series Please❤
free me itna sab kuch nahi milega
@@CodeNinja18 Bhai Sab Milega , Aap Maam ko Shyad Jante Nahi ho.......
❤
❤
❤
Everyone mail Apna College to complete the Python series all topics in deep & start DSA with Python 🙏🏻
Yeh 😮
Abhi ke liye kuch acha playlist available hai kya dsa in python ?
yes please
Yes please
th-cam.com/video/pkYVOmU3MgA/w-d-xo.html@@priyansumohanty3875
Homework:
def check_odd_even(n):
if(n%2==0):
print(n,"is EVEN")
else:
print(n,'is ODD')
n=int(input("Enter the number:"))
check_odd_even(n)
def num(a):
if(a %2== 0):
print("This is even",a)
else:
print("This is odd",a)
num(10)
input lena tha user se
def even_odd(num):
if (num % 2 == 0):
print("Even")
else:
print("odd")
even_odd(int(input("Enter No:")))
Wrong h
32:45
def func(a):
if(a%2 == 0):
print("EVEN")
else:
print("ODD")
n = int(input("please enter a number : "))
func(n)
32:33
def even_odd(number):
if number%2==0:
print("even")
else:
if number%2!=0:
print("odd")
even_odd(9)
Output:-
Odd
Awesome
Recursion smjh nhi aaya tha..toh shradha didi ki dekhne k baad code with h arry pr dekha vha bhi nhi aaya phir codebios pr dekha,, phir dobara yhi aagyi,.. or ab perfect smjh aagya... you are best didi ❤
same 😭
32:50
def check_num(n):
if n%2 == 0:
print("this is an even number")
if n%2 != 0:
print("this is an odd number")
n = int(input("enter num: "))
check_num(n)
Wrong h
32:41 cal_fact(81)
def cal_evod(num):
if(num%2==0):
print("the remainder is",num%2,",","THIS IS AN EVEN NUMBER !")
else:
print("the remainder is",num%2,",","THE NUMBER IS ODD !")
cal_evod(84)
32:40
def chkodd_even(n):
if n%2 == 0:
return "EVEN"
else:
return "ODD"
n = int(input("Enter a number:"))
print(chkodd_even(n))
INPUT: Enter a number:5
OUTPUT: ODD
32:30 hw
def finder(n):
if(n%2==0):
print("even")
else:
print("odd")
finder(int(input("enter the number : ")))
Def finder()
X =(int(input("entered no. ="))
If(X%2==0):
print("even")
else:
print("odd")
It's an easy method😌
@@ArjunKr-q3o it will work
@@ArjunKr-q3o I think u have understand the question.....Ma'am have told to use an input program.....pls rewatch the question
@@potnuruchaitanya8496 he used it at func call..
n = int(input("Enter : "))
def odd_even():
if n % 2 == 0:
print("EVEN")
else:
print("ODD")
odd_even()
55:00
n=int(input("Enter Number To Calculate First N Natural Nos= "))
def calsum(n):
if n==0:
return 0
else:
return n + calsum(n-1)
sum=calsum(n)
print("Sum of First",n,"Natural Numbers = ",sum)
32:55
def inp_odd_even (n):
if n%2 == 0:
print("Even")
else:
print("Odd")
n=int(input("Enter a no to check it is odd or even= "))
inp_odd_even (n)
32:40
n = 1
def odd_even(n):
if n % 2 == 0:
print('Number is Even')
else:
print('Number is odd')
odd_even(5)
odd_even(6)
def fun(a):
if(a%2==0):
print("GIVEN NUMBER IS EVEN")
elif(a%2 != 0):
print("GIVEN NUMBER IS ODD")
fun(int(input("ENTER A NATURAL NUMBER : ")))
num = int(input('Enter number: '))
def checkNum(i):
if(i%2 == 0):
print('Even Number')
else:
print('Odd number')
checkNum(num)
57:36
I made a basic self question to practise by self for odd/even with recursion
def eve(n):
if(n==0):
return True
elif (n==1):
return False
else:
return eve(n-2)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
def od(n):
if(n==0):
return False
elif(n==1):
return True
else:
return od(n-2)
57:20
n=int(input("enter number"))
def calc(n):
if(n==0):
return n
else:
return calc(n-1)+n
print(calc(n))
this will also do the job
Home Work:
def number(n):
if(n%2==0):
print("even")
else:
print("odd")
return n
number(9)
number(4)
well tried.🎉
mad said, you have to take input from user
@@siamkhan3682n = int(input("Enter a any number"))
def even_odd(n):
if n%2==0:
print("Even")
else:
print("Odd")
even_odd(n)
14:32
def calc(a,b,c):
sum = a+b+c
avr = sum/3
print(avr)
calc(int(input("enter a first value")),int(input("enter a secound value")),int(input("enter a thred value")))
32:55
def even_odd(num):
if num%2==0 :
print("even")
else:
print("odd")
even_odd(66)
55:00
# sum of first n natural number using recursion
n = int(input("Enter a number "))
def sum1(n):
if (n ==0):
return 0
return n + sum1(n-1)
print(sum1(n))
# write a recursion function to print all elements in list
list =[53,88,43,77,12,88,33]
def fun(list, n):
if (n == len(list)):
return
print(list[n], end= " ")
fun(list, (n+1))
fun(list, 0)
use for instead of if
def even_or_odd(num):
if num==0:
print("not even aur not odd")
elif num%2==0:
print("even number")
else:
print("odd number")
num=int(input("enter a number:"))
even_or_odd(num)
Print("Thankyou didi") 32:23
I love your code
Home work question answer
def odd_even(n):
if(n%2==0):
print("EVEN")
else:
print("ODD")
odd_even(45)
use input function
Please continue this series of tutorials with SQL (MySQL) so that projects using database can be created. This will be useful as it will use some dataset libraries like Numpy or Matplotlib and projects can be made.
58:31 alternate solution
def print_list_elements(lst):
if not lst:
return
print(lst[0],end = ' ')
print_list_elements(lst[1:])
print_list_elements([1,3,4,5,3,5,6,8])
32:30
def cal_num(number):
if(number%2 == 0 ):
print("its a even number")
else:
print("its a odd number")
cal_num(int(input("put your number: ")))
Home work :
n=int(input("Enter the number:"))
def eo(n):
if(n%2!=0):
print("ODD")
elif(n%2==0):
print("EVEN")
eo(n)
32:40 def num_check(number):
if(number%2==0):
print("Even")
else:
print("Odd")
num_check(13)
can anyone explain me what is the use of "return" code at 13:50
@@Jeevan-gj6wj if you call the function by assigning its value to a variable. then it stores the final output of the function.
basically if u print() then the value will be directy gets printed.
if you want to use the output further u should return it
Homework at 32:20,
n = int(input("Enter the value: "))
def odd_even(n):
if(n % 2 != 0):
print("ODD")
else:
print("EVEN")
odd_even(n)
Home work : = 32:30
def num (a):
if a % 2==0:
print("Even")
else:
print("Odd")
num(int(input("Enter your number :")))😊😊
Hi Shrahda,
The way you teach is really helpful . Thanks a lot . One thing i just wanted to say that factorial of any num is not like 1*2*3*...*num ,it should be num*....*3*2*1 . I know both will give same result but logic will get changed and i believe correct logic does matter even though both logics are giving same result .My intention was not to crrect you as you know many things better than me, here i just wanted to provide my opinion . Thank you....😊
num=int(input("Enter the number:"))
def oddeven(num):
if num%2==0:
print("THIS IS AN EVEN NUMBER")
else:
print("THIS IS AN ODD NUMBER")
oddeven(num)
You can do the same by this method also:
def oddeven():
num=int(input("Enter the number:"))
if num%2==0:
print("THIS IS AN EVEN NUMBER")
else:
print("THIS IS AN ODD NUMBER")
oddeven()
good work anyway
32:49
My Solution Code
userinput = int(input("Enter Your Number
"))
def oddevenchecker(thisnumber):
myvalue = thisnumber
if(myvalue%2 == 0):
print('Even Number')
elif(myvalue%2 == 1):
print('Odd Number')
oddevenchecker(userinput)
i am following you since last 4 years. You deserve Bharat Ratna for your free contents. which is infinite times useful than any paid content available in india..
x = int(input("enter any number:"))
def odd_even(x):
if x%2==0:
print("EVEN")
else:
print("ODD")
odd_even(x)
My work
we want DSA in python
Hammm yarrrr
Dude do it with java . It's much better
Yes mam we want
@@plazatotalmemeing9071ok.
Hey , do you know any other languages?
Can you tell me what I should learn next after learning PYTHON?
Yes we want
n=int(input('enter the num:'))
def fact_(n):
b=1
if(n
def find_odd_even(a):
if(a%2 == 0):
print("even number")
else:
print("odd number")
find_odd_even(2)
key topic with time stamp :---->
00:01 Functions in Python are blocks of code that can be reused.
02:02 Functions reduce redundant code and improve reusability.
06:12 Understanding function calls and parameters in Python.
08:09 Using functions reduces redundancy and makes code more efficient.
12:13 Functions in Python can be created with or without parameters and return values.
14:17 Functions offer a way to encapsulate code for reuse.
18:06 Understanding built-in and user-defined functions in Python.
19:58 Understanding default parameter values in Python functions
24:04 Creating functions to print lists with proper formatting
26:09 Understanding functions and recursion in Python
30:35 Introduction to functions and recursion in Python
32:36 Recursion in Python
36:10 Recursion is used to print numbers in a function call
37:55 Explaining recursion in Python with a specific example
41:39 Understanding the call stack in Python.
43:29 Recursion creates layers of function calls
46:59 Understanding the concept of recursion and factorial in Python.
49:04 Understanding recursion and its application in programming
52:51 Understanding recursion through the factorial function
54:40 Understanding recursion and writing recursive functions in Python.
58:29 Understanding recursion in Python
1:00:41 Understanding recursion in Python
thanks
HW ---->
def check():
no = int(input("Enter a no:"))
if no%2==0:
print("EVEN")
else:
print("ODD")
check()
An outstanding learning platform. Well done, Ma'am.
23:59 def length_list(list):
print(len(list))
for i in list:
print(i,end=' ')
length_list([2,3,4]) #ques1 and ques2
32:39
n1=int(input("enter number"))
def identifier(n):
rem=n%2
if(rem!=0):
print(n, "is ODD")
else:
print(n,"is EVEN" )
identifier(n1)
num = int(input("Odd or Even num: "))
def oddEven(a):
if a%2==0:
return("Even")
else:
return("Odd")
print(oddEven(num))
Done❤❤
✅
def checker ():
a = int(input("enter the number to check :"))
if a %2 == 0:
print(a,"is a even number")
else:
print(a , "is an odd number")
checker()
def even_odd(n):
if n %2==0:
print("even")
else :
print("odd")
n = int(input("enter a number:"))
even_odd(n)
def fact(a):
val=1
for o in range(1,a+1):
val*=o
print(val)
fact(9)
def check_even_odd():
num = int(input("Enter a number: "))
if num % 2 == 0:
return "Even"
else:
return "Odd"
result = check_even_odd()
print(f"The number is {result}.")
homework question.
def check(n):
if n%2==0:
print("even")
else:
print("odd")
check(6)
the output will be "even".
def num(a):
a = int(input("Enter a number: "))
if (a %2 == 0):
print("EVEN",a)
else:
print("ODD",a)
num(4)
32:44
def odd_even(n):
if n%2==0:
print("EVEN")
else:
print("ODD")
odd_even(10)
def cal_numType():
num= int(input("Entere a num: "))
if(num % 2 == 0):
print("even")
else:
print("odd")
cal_numType()
I literally learnt this entire series in one day!
simple straightforward.
also my previous coding exp. of C++ java and c# helped, but python is so simplistic as compared to them! no need for semicolons also :P ;
bas real project me impliment karna hai aur bekar logo k saath kam karne na mile bas yahi dua h.
# Recursion Function
def show(n): # n==7 # n==6
if n == 0: # 7==0 false # 6==0 false
return
print(n) # 7 # 6
show(n-1) # 7-1 # 6-1 etc.
show(7) # Calling
32:55
def oddeven(value):
n=value
if(n%2==0):
print("Even")
else:
print("Odd")
oddeven(5)
30:20
def even_odd(num):
if (num % 2 == 0):
print("Even")
else:
print("odd")
even_odd(int(input("Enter No:")))
# write a recursive function to calc the sum of first n natural numbers.
n = int(input("enter the value of n:"))
def sum(n):
if(n==0):
return n
else:
return n + sum(n-1)
print(sum(n))
Tried this pattern printing out (Call Stack)
def show(n) :
if n == 0 :
return
while n >= 0:
print('*' * n)
break
show(n-1)
if n == 1 :
pass
else :
print('*' * n)
show(10)
def odd_even(n):
if n%2==0:
return "EVEN"
else:
return "ODD"
n=int(input("enter the value of n: "))
print("number is : ",odd_even(n))
def calc_num(n):
if n%2==0:
print("EVEN")
else:
print("ODD")
calc_num(8)
#home work
def a(a,b=0):
if (a%2==0):
print("even")
else:
print("odd")
That Call Stack Analogy was enormously helpful to grasp the Recursion concept...thanks a lot mam❤
Really awesome this function But This video make me easy to learn recursion in python
th-cam.com/video/JzoAowI_9pU/w-d-xo.html
def number_chk(a):
calc = a % 2
if(calc == 0):
print("Even")
else:
print("Odd")
number_chk(int(input()))
😊
I also wrote the same thing but getting error
@@AnkitKumar-vy6tq
def number_chk():
a = int(input('Enter number to check >'))
calc = a % 2
if(calc == 0):
print("Even")
else:
print("Odd")
number_chk()
*corrected
you can add more lines to avoid getting errors like using if else for input to be int and not any other value.@@AnkitKumar-vy6tq
code for hw question.
def evaluate_num(n):
if n%2==0:
print("entered digit is even.")
else:
print("entered digit is odd.")
evaluate_num(76)
11:49
We can do with " for " also like:
for i in range (5):
Print ("hello")
Boom
Homework:
def odd_or_even(number):
if number % 2 == 0:
return "even"
else:
return "odd"
32:44
def checker():
a = int(input("enter number : "))
if(a%2==0):
print("EVEN.")
else:
print("ODD.")
checker() #calling the function.
i liked......... you sow that line of great swami vivekanand ji . It is very beautiful way to encourage to student that seeing your python lecture...... if some student seen title and they thought it is difficult of chapter 6 that lines you sown on screen it make inspire ............. your teaching style is very cool apna collage..😇
Not a single person in subcontinent explains Python language like Mark Myers do but you are definitely made your mark. Fan from Pakistan
can anyone explain me what is the use of "return" code at 13:50
@@Jeevan-gj6wj Good question. In that case, it wasn't necessary to use "return" because we were directly printing the average. However, it's generally a good practice to use "return" in programming. If you're returning a value, store it in a variable and then print it..
@@shashank_1874 did she explained advance python?
def int_num(a):
if a % 2 == 0:
print("EVEN")
else:
print("ODD")
# Example usage
int_num(3) # Output: ODD
int_num(5) # Output: ODD
int_num(4) # Output: EVEN
def check_even_odd():
number = int(input("Enter a number: "))
if number % 2 == 0:
print("EVEN")
else:
print("ODD")
# Example usage:
check_even_odd()
a = input("the number is : ")
a = int(a)
def cal(e):
if e%2 == 0:
print (e, " is even number")
else:
print (e, " is odd number")
cal(a)
def even_or_odd(n=int( input('Enter you number please: '))):
if n%2==0:
print(n,'is even number')
else:
print(n,'is odd number')
def finder(a):
if(a%2==0):
print(a,"is even number")
else:
print(a,"is odd num")
def num(n):
if n%2==0:
print("EVEN")
else:
print("ODD")
num(10)
HOMEWORK QUESTION
# WAF such that if your input is odd it will print odd and if the input is even then it print even
def num(a):
if(a%2==0):
print("even")
else:
print("odd")
num(2)
H.W Q :-
def odd_even(n):
if n%2==0:
print("even")
else:
print("odd")
return print()
odd_even(9
# write a recusrive function to print all the elements in a list.
r = int(input("enter the size of the list:"))
i = 0
def print_list(l,i):
if (i>=r):
return
else:
print(l[i])
print_list(l,i+1)
l = []
for t in range(r):
o = input("enter the elements:")
l.append(o)
print_list(l,i)
# WAF to print the elements of a list in a single line(list is the parameter)
numbers = [2,3,4,5,641,2,3,4,5,6,78]
def single_line(list):
for items in range(len(list)):
print(list[items], end = " ")
single_line(numbers)
Def check(n):
If (n%2==0):
print ("Even")
else:
print("Odd")
return check (n)
i=int(input("enter a number")
check(i)
def swap(x, y):
temp = x
x = y
y = temp
# Driver code
x = 2
y = 3
swap(x, y)
print(x)
print(y)
Ma'am please also cover the projects throughout this python series as you did for JavaScript series
Hello all
This one the best python basic lecture you will ever get,
In the entire video she never asked for subscribe or like.
Let’s encourage her to do more courses like this and help crores of students and learner’s. Keep up the good work Shraddha and keep on helping people.
print("please enter any number ")
n=int(input())
def eorodd(n):
if(n%2==0):
print(n,"is an even number")
else:
print(n,"is an odd number")
return
eorodd(n)
THANK YOU FOR THIS GOLDEN SERIES! ALWAYS WILL BE BLESSED FOR YOUR TEACHING SUPER GRATEFUL GOD BLESS YOU
Hi Shradha, Thank you for the series, its really helpful, the words spelled from your voice, is effective to place in our mind, but yes we have to do lots of practice. 2ndly Can you create a vision or direction towards IT-Admin switching to DevOps platform , for them how you will take the python as a scripting language, as a DevOps Admin, not like a developer/coder. Please create a video series on this.case studies or scenario based tutorials please, so the we can clear the basic concepts which is used in day to day life in companies (playing With AWS,Docker,K8 and a lot, for Automation). Waiting for it.
def even_odd(n):
if n % 2 == 0:
print("Even number")
else:
print("odd number")
even_odd(7)
Output is :odd number
def good(n):
if(n%2==0):
print("ODD")
else:
print("EVEN")
32:45
homework problem answer
a = int(input("Enter your number"))
def num(a) :
if (a%2 == 0):
print("EVEN")
else :
print("ODD")
num(a)
def odd_or_even(num):
if num % 2 == 0:
print(f"{num} is even")
else:
print(f"{num} is odd")
odd_or_even(7)
in this code we can take the number by input keyword and can place it in the place of num in the function.
like
num = int(input("Please enter the number: ")
and then can write function as written above. This time we need not to call function again.
👍
def num_even_or_odd (Num):
if Num %2 == 0:
print ("even number")
else:
print ("odd number")
Num = int(input("type a number - "))
print (num_even_or_odd(Num))
def number_output(n):
if (n % 2)==0:
print(f"{n} is Even Number")
else:
print(f"{n} is odd Number")
32:40 homework problem
num=int(input("enter your number-"))
def odd_even(n):
if n%2==0:
state="even"
else:
state="odd"
return(state)
print(odd_even(num))
"Thank you so much for your detailed explanation-it really helped me on my Python journey. Please keep making more Python videos in the future. You're amazing!"
n=int(input('enter num:'))
def fun(n):
if(n%2==0):
print('even')
else:
print('odd')
fun(n)
def num(a):
if a%2==0:
print(a,"is an even number")
else:
print(a,"is an odd number")
Homework answer
def check(num):
if(num%2==0):
print("Even")
else:
print("Odd")
n=int(input("Enter a number : "))
check(n)
best answer thanks