Valence Bond Theory | VBT | Class 12 | Coordination Compounds | ISC / CBSE |
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- เผยแพร่เมื่อ 24 ก.ย. 2024
- Class 12 | ISC | CBSE | Chemistry | valence bond theory VBT | in just 15 minutes | do any question in just a minute | chapter-Coordination Compounds
In this video you’ll be able to understand the reactions of carbonyl compounds with
Valence bond theory and it’s questions
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[Fe(CN)6]-4
Hybridization = d2sp3
M.M = 0
M.B = Diamagnetic
Spin = Low
Geometry = Octahedral
Hyb. d2sp3
Mm. 0
MB. Dia magnetic
Spin. Low
Geo. Octahedral
Low d😅
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[Fe(CN)6 ]-⁴
Hybrid=d²sp³
Geometry=Octa hedral
MB =Diamagnetic
MM =0
SPM=. LOW
NICE EXPLANATION MAM
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D2sp3, diamagnetic, mag moment 0 , octahedral
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hybridisation=d2sp3
shape=octahedral
magnetic nature=diamagnetic
magnetic moment=0
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Mam nicl4 wale que ma low spin aayga
Life saver
Hybridization - d2sp3
MM - 0
Mag. Behaviour - diamagnetic
Geometry - octahedral
Ma'am is this correct..?
Also Thank you so much❤❤🤗
Also ma'am 1doubt
Hm log ye maan k chl skte h ki if the ligand Is strong to vo pairing krwayega nd hybridization will b d2sp3 agr paper m show krne k liye na ho...?
hey how do you know what all the strong and weak ligands are
@@Proxz at 2:47 time stamp ma'am told abt strong and weak ligands nd how we can recognise them:)
@@kanak_rai1737 x-6=-4
@@kanak_rai1737 u hv to calculate the oxidation no.
[Fe(CN)6] ^-4
Here we hv to find Fe's oxidn no.
Nd CN is a negative charge ligand
So, the solving eq will b
X+(-1)6 = -4
-4 is the whole oxidn no. Of the complex nd we hv to put it in equals IF IT IS GIVEN...otherwise it's 0
Here the oxidn no. Is +2
Hope ur doubt is cleared now
Correct ✅
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Hybridization= d²sp³
M.m =o
Octahedral
Diamanteic
Low spin ....
Best teaching style ❤😊
Hybridization=d2sp3
Geometry=octahedral
Magnetic moment=0
Magnetic Behaviour=Diamagnetic
Spin=low
Homework answer is d²sp³ diamagnetic , low spin octahedral.
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Answer for the hw question --> hybridisation : d2sp3 , spin : low , magnetic moment : 0 , magnetic behaviour : diamagnetic , geometry : octahedral .
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