At 13m14s, dealing with the potential 67 UR in the central vertical chute, ousting 67 from cell r1c4, you realise that the cell is a 15 and conclude: that won't help. This is quite an extraordinary statement: knowing a cell is a bi-value cell is always a powerful restriction. At that stage, easy finish using another UR, your specialty: 19 pair down in the lower row of block 9.; a 11 in the matching position in the lower row of block 6; the 9s cannot join the 1s there under pain of a UR. Hence 9 in r6c6, 5 above that 9, puzzle done. I was slow doing it, albeit no real difficulty: 16 minutes notation free.
At 13m14s, dealing with the potential 67 UR in the central vertical chute, ousting 67 from cell r1c4, you realise that the cell is a 15 and conclude: that won't help. This is quite an extraordinary statement: knowing a cell is a bi-value cell is always a powerful restriction.
At that stage, easy finish using another UR, your specialty: 19 pair down in the lower row of block 9.; a 11 in the matching position in the lower row of block 6; the 9s cannot join the 1s there under pain of a UR. Hence 9 in r6c6, 5 above that 9, puzzle done. I was slow doing it, albeit no real difficulty: 16 minutes notation free.