Problem on Principle of superposition |Simple Stresses & Strains | Strength of Materials | MOM | MOS

[@vedantpatel7754]

You are god for me sir
kal exam hai apaki kripa se mai pass ho jaunga

[@kerenkanzemwarabu]

This is really amazing so easy to understand thumbs up Sir 👍

[@Beautifulsoul-k8g]

How can i thank you sir!
Until now, even after watching thousands of videos, I didn't understand, but your video made me understand just in 17minutes, so thank you very much sir from Nepal🇳🇵

[@SampurnaEngg]

Glad to hear that

[@NamusabiCatherine]

Thanks for the best work done
Quick and easy

[@THANUSHR-mk6yb]

Excellent explanation 😮🎉🎉

[@sleazyR5573]

Will this process work in the case case of fixed ends??

[@SampurnaEngg]

No,it won't work.

[@c-116ujjurilavanya6]

Chala bada explain chesaruu sirrr thank you so much ❤

[@SampurnaEngg]

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[@enjoyyourtripwithnature8151]

Good explanation....

[@dramoyoedward9229]

Thanks alot for the wonderful explanation

[@pravinpatil-t1k]

th-cam.com/video/3K9SLiftDPE/w-d-xo.html

[@kiran3118]

Thank you so much for your help sir ❤

[@deepakdagar591]

Thanks for the nice explanation 😊

[@chandachouhan9560]

Thank you so much 🥰 sir

[@SampurnaEngg]

Most welcome

[@kingsleyscepter7558]

This really helped me

[@shahanaskk2117]

Thanks gulu👍

[@Biranchiofficial-bp8sc]

Thank you so much sir ❤❤

[@babarrind6757]

Really good sir ❤️

[@SrushtiShinge]

Sir one doubt : length is 4.5m but why are you take 1500mm.🤔

[@SampurnaEngg]

I have taken the length of AB, BC, CD each as 1500mm.

[@ikennaagu568]

Please I'm not still clear on this. This particular question is from exercise 2.2 of Rajput strength of materials but in the text book the lengths are not evenly distributed like how it is in this video. Is it that we can make it evenly distributed ourselves when solving or what?

[@ikennaagu568]

*2.12

[@SampurnaEngg]

You can take the respective length for the respective section.
Like (PL/AE) where L is the length of the respective section.

[@rahulmadane8807]

Sir I have question value of B is-70 kN it means we taken compressive force but apne to out side direction dikhayi hai

[@SampurnaEngg]

We have taken a sign conversation -ve means going towards the left & +ve means going towards the right.

[@souravjena4982]

Sir compression stress me -ve hoga

[@SampurnaEngg]

Didn't got your point.

[@fieryscout2110]

Yes in compression your P becomes -ve but as in the given sum each part having tensile force acting on it thus the values are +ve

[@shivadeore146]

Sir how area is pi/4 *25'2

[@siddumoosewala2160]

Thank you so much sir for clearing the concept

[@pravinpatil-t1k]

th-cam.com/video/3K9SLiftDPE/w-d-xo.html

[@dheerajdexterous8929]

Thank you Sir..🥰

[@ferdousalam1366]

Sir, pls give Ans
A Steel bar long 1m ang 20mmx20mm is cross section is subjected to a tensile force 40Kn. Determine the elongation of the rod. If the modules of elasticity of the rod 200GPA

[@ranjan7089]

0.5 mm

[@nanasochaugule817]

0.5

[@sumanthnenavath]

Thank you sir 😚

[@hardiksolanki831]

Giga means 10^9 ? Why sir take as 10^3 ?

[@SampurnaEngg]

Yes.
But if it's GPA then we have to convert it into N/mm2.
So, We multiply it by 10^3.

[@pravinpatil-t1k]

th-cam.com/video/3K9SLiftDPE/w-d-xo.html

[@bangalkids9596]

Portion BC has comprehensive force of 50 kn .. please clear it

[@bhagwaa__01]

No u r wrong it is not comprehensive kindly note the original question

[@BarelyEditing57]

Yes you r correct

[@amandogra777]

Very esay iam iit mandi student from hp

[@ranjan7089]

Tnx sir

[@collinsokello-2613]

How does that force 60 comes from

[@chuchuscast]

Equal and opposite force at the beginning

[@Yourfather781]

Sir my calculations is going always wrong plz guide

[@SampurnaEngg]

Where you are going wrong, kindly let us know.

[@anushav550]

Thank u sir

[@SampurnaEngg]

Welcome

[@allinformation.3a854]

🙏

[@dineshpund9135]

∆LBC is wrong answer

[@oscarabdallah1883]

Bro unajua

[@ANKITMAHALA-q6d]

one gpa = 1000000000

[@AbdulAzizAmoah]

Please I can't see the handwriting well oo 😞😢

[@dilharachathuranga3389]

Thank you sir

[@omegaarcex2527]

thank u sir

[@SampurnaEngg]

Follow the Sampurna Engineering TH-cam channel on WhatsApp: whatsapp.com/channel/0029VaALnef7dmehZn80DV11