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The ratio of speed is 2:3 and time is the same so the ratio of distance will also be 2:3. So from here diff=1=100 so the distance between p and q is 200KM and speed of train A=(2/5)*(200/4 ). A=20KMPH.
Distance between P & Q x/2=(x+100)/3 So, x=200 km Now, T=D/S 4=200/(2s+3s) So, s=10 km/hr Because of speed ratio of A:B is 2:3 So, speed of train A is 2*10= 20 km/hr
Let , D = distance between P and Q , s1 = speed of train A , s2 = speed of train B In the time train A reaches Q , B covers 100 km more distance after reaching P D / s1 = ( D + 100 ) / s2 We know that -----> s1 / s2 = 2 / 3 Solving the equation we will get -------> D = 200 Now train A and B meet after 4 hours Suppose , the train A covers x km in 4 hours , so train B has to reach ( 200 - x ) km in 4 hour So, we get the equation -----> x / s1 = ( 200 - x ) / s2 = 4 Also, we know that ---> s1 / s2 = 2 / 3 Solve and Substitute we will get s1 = 20 Kmph , s2 = 30 Kmph If anybody have any better approach please share 🙏🏻 !
@@Catloverassam He exclaimed that even when the actual value of the distance/train's length isn't given on the question, we can arrive at the least possible length (using ratio and LCM), when the question states that both the train are of equal lengths. Great lecture!
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Sir Maine apka channel 1 week phele start Kiya or muje maths simplification ki pdf chahiye thi but muje mil ni rahi h govt. Adda par
The ratio of speed is 2:3 and time is the same so the ratio of distance will also be 2:3. So from here diff=1=100 so the distance between p and q is 200KM and speed of train A=(2/5)*(200/4 ). A=20KMPH.
aapka solution way accha lga bhaiya thanks 🙏🏻🙏🏻🙏🏻
Again explain plz
I'm new here
Bruh
2/5 kese aya?
Distance between trains a and b is 200km
S1+S2 =200/4 = 50 km/h
Given, Speed ratio =2:3
Speed of train A = 20 km /h
Bhai sab kya kamaal kyaa paddhati hoon aap 🙏🙏 hat off bro
Distance between P & Q
x/2=(x+100)/3
So, x=200 km
Now, T=D/S
4=200/(2s+3s)
So, s=10 km/hr
Because of speed ratio of A:B is 2:3
So, speed of train A is 2*10= 20 km/hr
Thanks for the session sir.
Ans for last ques is 20km/h
Dist bt P and Q is 200km
Speed of trains is 20 and 30 km/h.
sry can you explain in detail?
watched today.... best video ever
thank you sir.
Hw questions:-
Both train are in opposite directions so
S1+S2
=100+100
=200
Time =4 hr
Distance=200/4=50
Ratio=2:3
i.e=2/5×50
=20
Quality Education ❤❤
Thank u very much sir ji. Superb teaching
Your Awesome Sir !!!!!
Let , D = distance between P and Q , s1 = speed of train A , s2 = speed of train B
In the time train A reaches Q , B covers 100 km more distance after reaching P
D / s1 = ( D + 100 ) / s2
We know that -----> s1 / s2 = 2 / 3
Solving the equation we will get -------> D = 200
Now train A and B meet after 4 hours
Suppose , the train A covers x km in 4 hours , so train B has to reach ( 200 - x ) km in 4 hour
So, we get the equation -----> x / s1 = ( 200 - x ) / s2 = 4
Also, we know that ---> s1 / s2 = 2 / 3
Solve and Substitute we will get s1 = 20 Kmph , s2 = 30 Kmph
If anybody have any better approach please share 🙏🏻 !
Abe laude Bengali 20km/h is the answer
Thanks a lot sir
Sir ap jo bhi chapter pdhaya kijiye usually basic wala b bta diya kre pls sr ye hmari request h pls
Question No 7.
Option .B. 20 km/hr 🙏
❤❤
Thank you ❤️
23:16
👍👍👍👍
Sir plzz make h playlist
Sir
I bought IBPS Clerk maths batch few months ago,
All the concepts are cleared,
But this batch content is the same for that batch sir..???
@28:00 you have used distance only to calculate speed as 3 and 2.. how without distance you could solve?
@@Catloverassam He exclaimed that even when the actual value of the distance/train's length isn't given on the question, we can arrive at the least possible length (using ratio and LCM), when the question states that both the train are of equal lengths.
Great lecture!
hw ans 20.
Home work question 20 ✓✓
20 km/hr
40
18S
👍
ans-20kmph
Homework answer
20 km /h
Cross 😂😂👍
Answer is 20 km
Pyaar kre 🤣🤣🤣
Ans- 20km/h
20 km/h
Like
Add this to playlist it is not there in the playlist
18
20km /h
Sir mera naam avi