Thanks for your very kind comments. My videos are intended to cover the ground for AS and A2 level of the Edexcel, AQA and OCR syllabus. Alas, I wasn't able to distinguish between the material needed for AS and that needed for A2. However, all the AS material ought to be there.
ive been with khanacademy for awhile now but you make it even easier. you dont go off topic and you dont leave us wondering why something works the way it does. and you dont spend too much time explaining something. thanks please continue videos for as long as possible you help a lot of people
i agree. although i respect khan academy, i'm never able to learn from his videos. it seems like he stumbles and stutters a lot, and i just have a hard time looking at his harsh graphical aids.
soh cah toa is the funniest thing ive seen since the right hand rule, when i lifted my eyes off a test in magnetism and saw the whole class starring into their hands and making different shapes with it. once again, great video, thank you very much!
Thank you very much! You're the best physics course videos out there, you are clear with your explanations, don't go off tangent and actually tell us _how_ something works so we can have a chance at understanding the logic behind something, instead of just "here's the name for this new concept, now use it". Would gladly donate for your work!
I never did physics at A level because i wasn't interested enough at the time, but here I am learning it now, so thank you very much for making it more compelling and understandable.
Indeed. I am no snooker player but I understand that if the cue ball is aimed other than at the centre of the other ball (ie slightly to the side) then the effect I have drawn would arise.
The basic answer is that you must have the enough energy in the form of kinetic energy in a collision between two particles to account for at least the rest of mass energy of the created particles. Any surplus kinetic energy of the incoming particles will contribute to the kinetic energy of the creative particles. Much will depend on whether the incoming particles annihilate or whether there is simply additional particle creation.
The point is that two particles travelling in opposite directions can, in something like the large hadron collider, each be travelling at a speed very close to c. This makes the energy of the collision very high and much higher than can be obtained by moving particles hitting a stationary target.
II am not socially aware of the syllabus for me to give you any meaningful advice. I try to cover material for a range of different exam boards. I hope that my videos would be helpful in final revision and I wish you all the best in your exams.
Well in practice very few elastic collisions take place because this suggests that kinetic energy is completely conserved, whereas any kind of collision is likely to give rise to sound, heat, light energy. But you can have elastic collisions at particle physics level.
I realise the formulae look pretty horrid. But as I tried to explain in the video, in an exam you would usually be given information about several of the unknowns and you would be asked to calculate the remaining unknown.
19:11 If I saw those two formulas in GCSE, I would have straight up gotten a heart attack. It's mad to think how much your knowledge can improve in less than a year.
Thanks a lot, this helped me a freaking lot. i have my exams tom and this I was confused with but now i understand this ! thanx for posting this , u saved my ass
@12:07 Initially, there is energy only in x component (y=0 and x=mv1), AND after collision, the sum of both x components ARE EQUAL to total initial energy; wouldn’t that leave no energy left for y-components..? As a snooker fan, I would strongly presume, that Ronnie would scorn these kind of developements, with a long session of nail biting, and eventually skip the whole tournament.
i just can't without commenting on this blessed video u see i 'm watching this video in 2020 (i mean after sooo many yrs) and still it's effective i srsly can't understand a shit when our physics sir teaches and this video............just saved my ASS!!!!!!!
At 4:47 when he writes the incorrect equation, is that just an improper way to write the equation, or even if you plug the numbers in it wouldn’t work?
I recommend taking a look into Feynmann diagrams and the equation 'E=MC2' which covers the behaviour of young sub-atomic particles such as when particles decay more partcles arrive and how energy and particle matter can interact relative too motion (Usually C)
give this man a nobel peace prize for his contribution to A level physics !!! . by the way sir Can you show us how to solve the unknowns using simulataneous equations
Intuitively, in the first example, why there's an angle between the two particles while the first particle travels straight to the second particle that is static. Isn't the consequence of the collision is also straight? Or it's an 'assumption' to have this consequence that there's an angle between the particles?
so,if we given that the collision is elastic ,do we take the velocities as they are or do we have to resolve their components before we use kinetic energy formula ?
Where does the formula for momentum p=mv come from? Is there any derivation or logic to prove this relation? And what is the physical meaning of momentum?
Concerning the two balls colliding along the x axis( Horizontally) I would have thought that the outcome would be horizontal: Or in snooker jargon the fist ball would "follow through"so that both would end up in the pocket.
Hello! Great video, but I wanted to ask when you're calculating the momentum of the y-dimension, isn't the negative direction already inside the velocity, rather than out of it? I thought that the formula could be always written with pluses, and you took care of the minuses when calculating the velocity. Thank you so much for sharing your wealth of knowledge!
Correct, you can write it with pluses if you are consistent with your angles. In the video alpha (~40°) and beta (~30°) are measured to the same axis but in different directions. This error is undone by later manually adding or subtracting by hand. If you measure all angles in the same direction (e.g. alpha=40° and beta=-30° or 330°), you convey the direction-information to the formula where sin(beta) now has the same magnitude but negative sign. Hence you can just add all terms, no manual decisions necessary.
parv bakshi Never seen such a good teacher. He teached in kings college in the past so no wonder for his competence level and such an entousiasm !! let s make a collect for him . He deserves that largely !!
I think I have just figured out my own question. Is it because of the change from cos to sine? If you were to use the angle between the direction of the ball with respect to the y-axis would the equations be x=V2cosA and y=V2cos(90-A)? Which would be slightly more work and therefore pointless? So it is easier to work out y=V2sinA over y=V2cos(90-A). Am I making any sense at all?
My question is that when Considering particle collisions how does the Energy Needed to create new particles relate to the KE, for example a particle Aimed at a target, and a particle Colliding with with another particle moving in the opposite direction.
When in the y-direction both balls have ZERO momentum before the collision (as in the video), how can they have an angle bigger than ZERO after the collision (as in the video too!)???
Sjaak van Dijk I was trying to represent the situation in, say, snooker where the cue ball is hit with the cue such that it hits the other ball slightly off centre. In those circumstances the two balls will move off in different directions.
Hi, this may be a silly question but I am confused as to why the angles for the direction of the "ball" with respect to the x-axis and then with the same ball with respect to the y-axis are the same. For example, in the simplified example at 9:13, why is x=V2cosA and y=V2cosA. Why is it not x=V2cosA and y=V2sin(90-A) as (90-A) would be the angle from your drawn line to the y-axis. Hope this makes sense.
yo doc .. why is the M1V1sin(gamma) negative at the last part.. shouldn't you put a modulus in the left hand side of the y component ( again I'm talking about the last example) ... so that the one having the smaller magnitude will be subtracted from the one having the bigger magnitude ????
Hello Doc. Another efficient video on a classical subject. So thanks again ! There is anyway something to be precised. In your first example (one snnoker ball at velocity v hitting another ball at rest), if the hitting ball is hitting the rest ball just in its center, the two balls will go in the same direction (alpha=beta=0). To get the situation you described in the scheme, the hitting ball should hit the second ball at the different point than the center of its section. Do you agree ?
So. Four post-impact unknowns and (for elastic collisions) three equations. How would we predict the complete post-impact calculation? That is, to calculate all four unknowns.
sir,thank u very much for these videos,it helped a lot,but i wanna say that plz add videos for experimental analysis of A-level physics.i m quite weak in experimental co-ordinations.
I have a question, I am an aspiring physicist and I wish to learn everything I can about all branches of physics and I want to know, in what is the proper order to learn in your video playlists, from start to finish? Like which ones should I begin with and which ones should I conclude? I imagine I should start with classical mechanics and the final should be nuclear physics but what about between that? Thank you professor.
+lrobertiii My videos are organised into playlists and in each playlists the videos are in the order I recommend for watching. As to the order of playlists, I would start with GCSE, then A Level, then any order you like for the uni level material except I would watch the Quantum Mechanics playlist before you watch the particle physics playlist.
100 000 views and only 800 likes i think that this man didnt put this videos because he wanted to have a lot of likes and be famous but if he is glad to spend his free time to make this VERY helpful videos we should give him likes and help his chanell grow and maybe he can even take some money from yt. Like its the less think we can do because we are able to look VERY helpful videos for free.
i notice that you dont have a video for SI base unit and vectors. i know its a really basic part of physics but i still wish there's a video on it. physics have never been my strong point so every little bit counts i guess?
I love you sir. I'm going to do my AS level exams this May/June and I'm currently studying the A level portions in my school, and this has helped me a lot. However, do you have any videos that are specifically meant for the AS level curriculum?
I hope so. As a revision tool. The videos are intended to cover a range of different syllabuses including CIE. but I continue to add to them as people point out aspects which are missing.
Ello mates, my name is Dr. Physics, and I like to sip tea with my mum while eating British crumpets.(insert accent while reading). Just kidding Dr. I love your videos, thanks for the big help.
Why not use the convention of u= initial velocity? That's the only part of the video that confused me in this case, I found the rest extremely helpful for revising for my test.
Hi, I was wondering how you managed to get such a clear video of 21 minutes into a file of only 55mb. Can you tell me what camera and software you use to make your videos and perhaps what resolution and frame rates you use. It would be really useful. Thanks
I'm not familiar with the details of each syllabus - but my videos are intended to cover the syllabus of OCR, AQA, Edexcel and CIE tho not all courses need all the material in my videos.
![ILLSLICK X YOUNGOHM - We're The same [Official Video]](http://i.ytimg.com/vi/yUJNkobYR0E/mqdefault.jpg)
Thanks for your very kind comments. My videos are intended to cover the ground for AS and A2 level of the Edexcel, AQA and OCR syllabus. Alas, I wasn't able to distinguish between the material needed for AS and that needed for A2. However, all the AS material ought to be there.
your students should be proud to have a brilliant lecture like you .you know what you are doing, you derseve a unique noble price
*Nobel prize
@@The112Windows everything comes at a price.
In Korean, saying Soh Cah Toa sounds like "A cow is vomiting", so it's quite easy and amusing to remember the trig functions. xD
😂😂
In english it sounds like succ a toe
It took a while to find the correct video on TH-cam out of all the mess and I have to say this is it! THANK YOU!
This guy is a living legend
You make the most difficult and confusing chapters in Physics so easy to learn, it's honestly a talent
Just to be clear, the A level videos are in the playlist on A level physics. There are other playlists which are for higher level (usually degree).
Your videos are really helpful for Mechanics in Mathematics as well :P
+AlchemistOfNirnroot Thanks. Glad they are of help.
Where the collision is elastic that means that both momentum and kinetic energy are conserved.
you have balls going in and balls going out. - DrPhysicsA
Balls come in, balls come out. You can't explain that.
You’ve got balls coming in, and balls going out - (DrPhysicsA) Correctly corrected by me, pointing out the mistake of Karbonics
i recommended this course to all my friends who have school-age kids. Bravo!
+Silly Sad Many thanks.
ive been with khanacademy for awhile now but you make it even easier. you dont go off topic and you dont leave us wondering why something works the way it does. and you dont spend too much time explaining something. thanks please continue videos for as long as possible you help a lot of people
i agree. although i respect khan academy, i'm never able to learn from his videos. it seems like he stumbles and stutters a lot, and i just have a hard time looking at his harsh graphical aids.
cjp21211 I think he's helpful for math but not chemistry & physics
He's helpful for Chemistry but there is Matt Anderson and this guy who's made physics easier
Wow, this tutorial really is spoon feeding me just magnificently.
your videos are great. i can understand this easily!! tq so much. i recommended this course to all my friends . my exams also went well...tq!
soh cah toa is the funniest thing ive seen since the right hand rule, when i lifted my eyes off a test in magnetism and saw the whole class starring into their hands and making different shapes with it.
once again, great video, thank you very much!
Thank you very much! You're the best physics course videos out there, you are clear with your explanations, don't go off tangent and actually tell us _how_ something works so we can have a chance at understanding the logic behind something, instead of just "here's the name for this new concept, now use it". Would gladly donate for your work!
I never did physics at A level because i wasn't interested enough at the time, but here I am learning it now, so thank you very much for making it more compelling and understandable.
Indeed. I am no snooker player but I understand that if the cue ball is aimed other than at the centre of the other ball (ie slightly to the side) then the effect I have drawn would arise.
The basic answer is that you must have the enough energy in the form of kinetic energy in a collision between two particles to account for at least the rest of mass energy of the created particles. Any surplus kinetic energy of the incoming particles will contribute to the kinetic energy of the creative particles. Much will depend on whether the incoming particles annihilate or whether there is simply additional particle creation.
I was absent for the first 3 days and i missed out on this in class so i owe you m8😁
The point is that two particles travelling in opposite directions can, in something like the large hadron collider, each be travelling at a speed very close to c. This makes the energy of the collision very high and much higher than can be obtained by moving particles hitting a stationary target.
II am not socially aware of the syllabus for me to give you any meaningful advice. I try to cover material for a range of different exam boards. I hope that my videos would be helpful in final revision and I wish you all the best in your exams.
Found this while doing a last minute cram session before my exam, helped a lot. Thanks!
Well in practice very few elastic collisions take place because this suggests that kinetic energy is completely conserved, whereas any kind of collision is likely to give rise to sound, heat, light energy. But you can have elastic collisions at particle physics level.
You are welcome. Hope it helps.
It is by far one of the best explanation of momentum in 2D. Thanks!
I realise the formulae look pretty horrid. But as I tried to explain in the video, in an exam you would usually be given information about several of the unknowns and you would be asked to calculate the remaining unknown.
OMG!! I requested for this video in circular motions and I never thought that you would really make it!! THank you so much!!
This tutorial is well thought and presented.
Its a combination of AS and A2 covering the syllabus of Edexcel, AQA and OCR with some CIE as well.
Thank you so much for explaining the trig SOH CAH TOA part. That helped so much.
A big thank you from a student in Canada! :)
before watching the video= "no idea what this topic is"
after watching the video"= solving the questions with him without mistakes
19:11 If I saw those two formulas in GCSE, I would have straight up gotten a heart attack.
It's mad to think how much your knowledge can improve in less than a year.
tigan
Even if i have much to learn for my exams, i can keep my cool because i know your videos will help :D
You are a great teacher. It is actually easy to understand now.
Thanks a lot, this helped me a freaking lot. i have my exams tom and this I was confused with but now i understand this ! thanx for posting this , u saved my ass
I hope the exam goes/went well.
@12:07
Initially, there is energy only in x component (y=0 and x=mv1), AND after collision, the sum of both x components ARE EQUAL to total initial energy; wouldn’t that leave no energy left for y-components..?
As a snooker fan, I would strongly presume, that Ronnie would scorn these kind of developements, with a long session of nail biting, and eventually skip the whole tournament.
omg your videos are soooooo helpful!! i love all of them.....Thank you so much for making them.
i just can't without commenting on this blessed video
u see i 'm watching this video in 2020 (i mean after sooo many yrs) and still it's effective
i srsly can't understand a shit when our physics sir teaches
and this video............just saved my ASS!!!!!!!
Thanks to your videos I managed to get an A in AS physics :P now im going to do the same for A2 :)
At 4:47 when he writes the incorrect equation, is that just an improper way to write the equation, or even if you plug the numbers in it wouldn’t work?
I recommend taking a look into Feynmann diagrams and the equation
'E=MC2' which covers the behaviour of young sub-atomic particles such as when particles decay more partcles arrive and how energy and particle matter can interact relative too motion (Usually C)
give this man a nobel peace prize for his contribution to A level physics !!! . by the way sir Can you show us how to solve the unknowns using simulataneous equations
Excellent explanation. Thank you for taking the time to make this video.
great explanation! Thank you very much :))
you deserve wayyyy moreeeee subscribers.
Intuitively, in the first example, why there's an angle between the two particles while the first particle travels straight to the second particle that is static. Isn't the consequence of the collision is also straight?
Or it's an 'assumption' to have this consequence that there's an angle between the particles?
At 9:13 the video says x=V2cosA and y=V2sinA.
Sin(90-A) = CosA
I think you answered your question in your subsequent comment below.
Thank u sir alot. You helped me to understand the chapter which i never understood in my class.
Bro this video is amazing dude. I now understand it, for real thank you very much man.
I love this channel, so glad I discovered it, is a great complement for my studies!
this guy is awesome at teaching
You can't calculate all the unknowns. In an exam question you would generally be given some of the information and asked to calculate the rest.
I get the idea about it now!:D Thanks Dr :) Thanks a bunch for theses videos btw, inshallah because of these I'll get a B in Physics!:D
so,if we given that the collision is elastic ,do we take the velocities as they are or do we have to resolve their components before we use kinetic energy formula ?
Where does the formula for momentum p=mv come from? Is there any derivation or logic to prove this relation? And what is the physical meaning of momentum?
had to create a Google account and sign in just to tell you how amazing you were.
Congratulations. Well done. Go for it.
best lecture on 2D Momentum
Keep it up sir! I really love ur video!
Concerning the two balls colliding along the x axis( Horizontally) I would have thought that the outcome would be horizontal: Or in snooker jargon the fist ball would "follow through"so that both would end up in the pocket.
excellent explanation! Thanks
Very kind of you to say so.
Hello! Great video, but I wanted to ask when you're calculating the momentum of the y-dimension, isn't the negative direction already inside the velocity, rather than out of it? I thought that the formula could be always written with pluses, and you took care of the minuses when calculating the velocity. Thank you so much for sharing your wealth of knowledge!
Correct, you can write it with pluses if you are consistent with your angles. In the video alpha (~40°) and beta (~30°) are measured to the same axis but in different directions. This error is undone by later manually adding or subtracting by hand. If you measure all angles in the same direction (e.g. alpha=40° and beta=-30° or 330°), you convey the direction-information to the formula where sin(beta) now has the same magnitude but negative sign. Hence you can just add all terms, no manual decisions necessary.
simply the best :)
Who else thinks this man deserves money for his wonderful content ?
parv bakshi You are right, he deserves a lot of money for sure !!very clear and cut expained. all logic !
parv bakshi
Never seen such a good teacher. He teached in kings college in the past so no wonder for his competence level and such an entousiasm !! let s make a collect for him . He deserves that largely !!
can these vids be used for OCR ?
I think I have just figured out my own question. Is it because of the change from cos to sine?
If you were to use the angle between the direction of the ball with respect to the y-axis would the equations be x=V2cosA and y=V2cos(90-A)? Which would be slightly more work and therefore pointless? So it is easier to work out y=V2sinA over y=V2cos(90-A).
Am I making any sense at all?
My question is that when Considering particle collisions how does the Energy Needed to create new particles relate to the KE, for example a particle Aimed at a target, and a particle Colliding with with another particle moving in the opposite direction.
When in the y-direction both balls have ZERO momentum before the collision (as in the video), how can they have an angle bigger than ZERO after the collision (as in the video too!)???
Pretty much just because the drawing is inaccurate.
At what time in video does this arise?
DrPhysicsA Given the drawing I was waiting for a remark about alpha and beta (at 13.44). I think they are zero in this case. It confused me a bit.
Sjaak van Dijk I was trying to represent the situation in, say, snooker where the cue ball is hit with the cue such that it hits the other ball slightly off centre. In those circumstances the two balls will move off in different directions.
DrPhysicsA I understand. So you must agree with me that in that case the value of Y (before the collision) can't be ZERO for both balls.
This is perfect. Thank you, sir.
thank you so muchh
Hi, this may be a silly question but I am confused as to why the angles for the direction of the "ball" with respect to the x-axis and then with the same ball with respect to the y-axis are the same. For example, in the simplified example at 9:13, why is x=V2cosA and y=V2cosA. Why is it not x=V2cosA and y=V2sin(90-A) as (90-A) would be the angle from your drawn line to the y-axis. Hope this makes sense.
sir do your lectures cover Physics AS 9702 CAIE syllabus??
Would it not make more sense to label momentum before in terms of mu and momentum after as mv
Can you give some examples of elastic collision
I knew this isn't included in the a level syllabus, but needed help for the SAT II, does any of your videos cover the topic
"angular momentum" ?
yo doc .. why is the M1V1sin(gamma) negative at the last part.. shouldn't you put a modulus in the left hand side of the y component ( again I'm talking about the last example) ... so that the one having the smaller magnitude will be subtracted from the one having the bigger magnitude ????
+sushant karki Its really a question of sign convention. You can use any convention as long as you are consistent.
Im loving your videos!
great explanation, thank you very much!
Hello Doc. Another efficient video on a classical subject. So thanks again !
There is anyway something to be precised.
In your first example (one snnoker ball at velocity v hitting another ball at rest), if the hitting ball is hitting the rest ball just in its center, the two balls will go in the same direction (alpha=beta=0). To get the situation you described in the scheme, the hitting ball should hit the second ball at the different point than the center of its section.
Do you agree ?
So. Four post-impact unknowns and (for elastic collisions) three equations. How would we predict the complete post-impact calculation? That is, to calculate all four unknowns.
What if the collision is elastic and its given the elastic force of the bodies. How to calculate their final velocity?
sir,thank u very much for these videos,it helped a lot,but i wanna say that plz add videos for experimental analysis of A-level physics.i m quite weak in experimental co-ordinations.
I have a question, I am an aspiring physicist and I wish to learn everything I can about all branches of physics and I want to know, in what is the proper order to learn in your video playlists, from start to finish? Like which ones should I begin with and which ones should I conclude? I imagine I should start with classical mechanics and the final should be nuclear physics but what about between that?
Thank you professor.
+lrobertiii My videos are organised into playlists and in each playlists the videos are in the order I recommend for watching. As to the order of playlists, I would start with GCSE, then A Level, then any order you like for the uni level material except I would watch the Quantum Mechanics playlist before you watch the particle physics playlist.
hi Sir i really like this description.
100 000 views and only 800 likes i think that this man didnt put this videos because he wanted to have a lot of likes and be famous but if he is glad to spend his free time to make this VERY helpful videos we should give him likes and help his chanell grow and maybe he can even take some money from yt. Like its the less think we can do because we are able to look VERY helpful videos for free.
awesome vry hlpfullll
i notice that you dont have a video for SI base unit and vectors. i know its a really basic part of physics but i still wish there's a video on it. physics have never been my strong point so every little bit counts i guess?
bro keep on making such helpful video's
I love you sir. I'm going to do my AS level exams this May/June and I'm currently studying the A level portions in my school, and this has helped me a lot.
However, do you have any videos that are specifically meant for the AS level curriculum?
Instead of v1, v2, v3, v4? Yes good idea. But as long as you stick to whatever convention you choose its OK.
Great Video!
Hi Doc, will your content suffice for AS Physics Cie? Thank you for the videos.
I hope so. As a revision tool. The videos are intended to cover a range of different syllabuses including CIE. but I continue to add to them as people point out aspects which are missing.
Thanks, either way you're the best person i know who can help me for my exams. Appreciate your work.
Ello mates, my name is Dr. Physics, and I like to sip tea with my mum while eating British crumpets.(insert accent while reading).
Just kidding Dr. I love your videos, thanks for the big help.
Sorry I'm an American, we are jerks.
Why not use the convention of u= initial velocity? That's the only part of the video that confused me in this case, I found the rest extremely helpful for revising for my test.
Hello! Can I know if this is for H3 or H2 or H1 a level physics syllabus
Hi, I was wondering how you managed to get such a clear video of 21 minutes into a file of only 55mb. Can you tell me what camera and software you use to make your videos and perhaps what resolution and frame rates you use. It would be really useful. Thanks
I do not have any particular special equipment. I use a Panasonic SD RS 26 camera and I mix down the video on iMovie on a MacBook.
why is it conserved? can someone explain
Is it for Edexcel Unit 4?
Pls Answer
I'm not familiar with the details of each syllabus - but my videos are intended to cover the syllabus of OCR, AQA, Edexcel and CIE tho not all courses need all the material in my videos.