If i may add a bit to this, you don't flip the configuration from R to S or S to R because it's a Fischer projection. Instead, you flip it because you have a H on the horizontal plane indicating that you have an H molecule on a wedge when it should be on a dash.
Thank you for the video! You’ve just saved me from one night miracle✨🥺 I think the last stereoisomer is CH3 I I Br ---- H I I H ---- Cl I I CH3 2R,3R Molecule (D) would be a diasterioisomer to molecule (A) as Br still R Pls answer if I get it right.
From my understanding and what he hinted at in the video (from 18:40-18:59) I think the last stereoisomer (D) is actually CH3 I I Cl ---- H I I H ---- Br I I CH3 Stereoisomer D and A would be diastereomers to each other because the top stereocenter is flipped and the bottom stereocenter remains the same so they are not exact mirror images of each other but they also do not have a line of symmetry.
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If i may add a bit to this, you don't flip the configuration from R to S or S to R because it's a Fischer projection. Instead, you flip it because you have a H on the horizontal plane indicating that you have an H molecule on a wedge when it should be on a dash.
really helpful for my exam. thanks a dozen
Thanks prof
THNKSSSSS SIR
Thank you for the video! You’ve just saved me from one night miracle✨🥺
I think the last stereoisomer is
CH3
I
I
Br ---- H
I
I
H ---- Cl
I
I
CH3
2R,3R
Molecule (D) would be a diasterioisomer to molecule (A) as Br still R
Pls answer if I get it right.
From my understanding and what he hinted at in the video (from 18:40-18:59) I think the last stereoisomer (D) is actually
CH3
I
I
Cl ---- H
I
I
H ---- Br
I
I
CH3
Stereoisomer D and A would be diastereomers to each other because the top stereocenter is flipped and the bottom stereocenter remains the same so they are not exact mirror images of each other but they also do not have a line of symmetry.