One more student gave this way to prove the intro problem: s^4+c^2=c^4+s^2 She used homogeneity: s^4+c^2(s^2+c^2)=s^4+c^4+c^2s^2=c^4+s^2(s^2+c^2)=c^4+s^2. Its like shifting the 1. How elegant this solution is really! 📖To buy the paid courses of Problem Solving Courses of Calculus you can whatsapp me at 7535818547(no calls) 🔥THE 8 SOURCES YOU JUST CANNOT MISS: 1⃣ The Unbeatable Maths Course(Theory storywise+ ALL PYQs Typewise)= th-cam.com/play/PL2dPD7oDhSn9sWNfHbD8_VAs4as19rD6J.html&feature=shared 2⃣ Solve BLACK BOOK/SAMEER BANSAL EASILY! My Zero to ULTRA ADVANCED Maths Courses: www.youtube.com/@MathsUnpluggedIndia 3⃣ ALL QUESTIONS IN ADVANCED COME FROM THIS : CALCULUS PROBLEM SOLVING EXCLUSIVE COURSES : th-cam.com/play/PL2dPD7oDhSn9eObmrHoL3z49OBAAZbuiC.html&feature=shared 4⃣My Zero to Ultra Advanced Handwritten Notes/Sheet Link: drive.google.com/drive/folders/1TEIdSlr5fLnDA6y9tyyvUgvXxPyo8XDc?usp=sharing 5⃣ If you are in mess(just cant do what you planned to)/existential crisis/brutal pains in life, you need to first understand yourself , your life, this world , this existence, hence for you: th-cam.com/play/PL8W_3lFy-6-WMRoOTcEPTWDxuWbsqBbd9.html&feature=shared 6⃣Eye Opener Series: th-cam.com/play/PL2dPD7oDhSn-mTqPxhryoyzoSi3DkelXV.html 7⃣PSIM Series(Exactly how idea strikes in tough math problems): th-cam.com/play/PL2dPD7oDhSn_lH-jOlSdChSWYeEfBxcUH.html&feature=shared 8⃣Checkout and subscribe my other 2 channels: @lifeunpluggedofficial & @existenceunpluggedofficial 🧍♂Socials: 👉Telegram channel: t.me/mathsunpluggedchannel 👉Telegram Group: t.me/mathsunpluggedofficial
bhai one request from my side please upload a lecture on straight line and more on 11th class topics🙏🙏.U are literally the best guy for teaching maths u take every topic in depth making me understand it ,i really appreciate all ur work.Someday i would love to meet u in person
Sir app pls pls crash course continue kardo pls i along with many students find u and only u as the best and ideal teacher for maths , jee mains 4 mahine baaki haai aadha syllabus baaki haai maths thoda bhaut strong hua due to u but pls continue the series everyone is looking onto it and personally i pray for ur life to be back to normal
17:14 Done with LCM and manipulation. Take [1/abx] common on both sides them out whole equation with come in form of 1/ab + 1/bx + 1/xa = ab+bx+xa Now by cross multiplication simplify. Then it will be in form of [a+b]/x + x[1/a+1/b]=-[ a/b + b/a +2] Now multiply both by ab in order to form equations in form of a+b and . Then you will see the sqaure of a+b on one side simplify .. and thus you will get the answer X= -a .... X= -b
bhaiya thank you 30 min ke andar video banane ke liye i try to stay away from youtube and internet overall except watching some youtubers you are one of them toh pls try krna ayese hi banao (im a dropper) 2025 jee
Took the method 1 of solving taking long one and reducing it to reach RHS.... when you told about the dissimilarity I put cot8x as Tan half angle formula and then solved first expression as I did it I realised it cut the previous term and it was the Eureka moment for me where it hit then I just did it again and again untill reaching cotx=cotx Ik it is long approch and it has shorter and better approch either by method 4 or 5.....waiting for bhaiyas way of solving Ps-it was very helpfull I will be sleeping proudy
bhagwaan ki daya se mujhse 1st try me ban to gya but jinse nhi hua unke liye bhai ne bilkul shi hint diya hai jo symmetery ko break kr rha hai uske around kuch socho.
Bhayya mai batau apka content itna achha hone ke bavjut be bohot jyada logon ke pass kyon nahi pahuchta Kyonki Apka content bohot hi accha hai and Student usko share or suggest nahi karte kyoki unhi lagata hai ki itni ache learning mai mere pass hi rakhu fir vo dosto ko batate nahi apke baare main Main be ase hi kiya
How are you sir?! actually i am not a science student neither do i have maths in my 12th subjects. I study maths just for enjoyment.. Tbh i came to know about you just a few months ago when one of my good friend who is preparing for jee told me about you... I watched some of your videos from playlist 'chapter 1' and that 4 hour long video (apparently your most viewed one) And those were really mind blowing.!!! i totally loved them.. I checked out your description and checked the books you have suggested for maths enthusiasts!! I stumbled upon the most lovely teacher in my entire life Mr Paul Lockhart.. His books are so good i mean just mindblowing.. I had a very good time reading his books and i really want to thank you a lot for recommending those books.. But now i have completed all three of this books.. I really request you to please do suggest me some nice books please?? i mean is there any teacher as lovely as him ? please suggest me shit ton of books from some writers like him... Maybe about trigno (other than that eli maor one) , Calculus , number theory.. pnc.....Please bhai koi bdia c suggest krdo...!! i would really appreciate the suggestions.. Aur please muje ek aur suggestion do bhaiya.. Muje lagrha mai shyd ISI k liye paper du but mai uske liye eligible hi nhi hu bhut dimag khrab hota hai... Kya kuch ho sakta hai ?
Sir last que Maine 2 baar effort maarke dusare me solve akr diya Tanalpha - cotalpha solve kiya Vaha se pattern pakada aur age easily solve ho gaya simple que tha after applying your strategy
I solved the last question without hint and, ithought it in this way:- Last one was in cot form, so i should try that it should similar with tan term, so used tan2x =2tanx/1-t² formula. Took tan common and found that terms were cancelling leaving 4/tan4x.went on with this approach. Again, and proved it in 3,4 minutes. Thanks bhaiya for this wonderful series, and crash course due to which i have improved in maths
Well i took t and c at one side added with 4 tan 4alpha plus 8 cot 8 alpha basically rearrangement and proved with tan 2 alpha formula, but great initiative
Bhaiya please don't discontinue this series . It is ineed life changing series for students like me . I know how you are feeling right now that i am putting that much efforts but not enough views are coming . I know bhaiya ye bhot disaapointing lgta hai jb aap poora efforts daale aur log aake efforts ka value nhi krre . So please please bhaiya please countine this series and i hope you will eventually get what you want and mai thnks bhi nhi bol skta aapko coz aap jo ye kaam kr rhe ho hm hmlogo ke liye wo uske liye thnks ek bhot chhota chiz hai bhaiya so please bhaiya please continue tgis series for students like me ❤
The most important thing is how to solve jee adv questions within 5 min because the main problem is we are able to solve at home but not in paper with time constraints
SIR PLS HELP IM STUCK. WHILE DOING L TO R IN Q1 , AFTER MANIPULATING LHS A LOT I GOT (cosA + cosB)(2cos(A+B)-1) HOW DO I PROVE THIS TO RHS WHERE A IS THETA AND B IS PHI
bhaiyaaa thanks for this bohot bohot maza aa rha hai vaise ek request thi aap unbeatable crash course me coordinate geometry laa skte ho kya it'd be very helpful
bhaiya,One of the problem is remembering The entire syllabus of Jee.Can you please give some suggestions to remember all the things and improve striking time in exam.
Recently I came to know about this channel and I learnt a lot about manipulation and all. I just want to say that thank you so much bhaiyaa!❤️💡 I was looking for this series☺️ Pure TH-cam pe koi problem Solving pe itnaa khul k nhi bolta hai... Keep uploading such a fantastic videos!🥰
hw ka approach : by gods grace didn’t get stuck anywhere. Aapke laye jagah aya fir waha majne theta-phi/2 ko alpha bola toh terms bani 2cos(a)cos(a+2phi+theta) then got to cos(phi+2theta) +coa(2phi+theta) then phi + theta ko A boldiya and then just cos(a+b) then rearrange and common
Mai phir se apko batana chata hun dhayan dijiye ga ki mai apke channel je madhayam se batana chata hun ki please coordinate geometry ke notes de dijiye😢
Bhaiya wo jo cot ki term usko tan mein convert karke piche wale ke saath lcm le loge toh together they will be reduced to 1/tan4alpha fir iss term ko tan2alpha term ke sath loghe toh together they will reduce to 2/tan2aplha and finally iss ka last term tanalpha ke sath toh prove ho jayega
12:30 Iske baad product to sum transformation karne pe cos(2θ+ Φ ) + cos(θ+2Φ) mil jayega jisko split karke likh denge (θ+Φ)+θ and (θ+Φ)+Φ kyunki answer is in T ratios of these angles, fir bas re-arrangement
Bro thoda hint de skte ho ki kaise isko approach kre coz i am trying by using formula of cos 3 theta but i am getting stuck. denominator reduce hi nhi ho rha....
RD SHARMA QUESTION CHALLENGE SOLUTION after what you did take x common - x(a+b)+ab/abx now take ab common - ab(x(a+b)/ab+1)/abx x(1/a+1/b)+1/x=1/a+1/b+1/x ---(dividing by x)
i think there's an issue with that solution basically {x(1/a + 1/b) + 1}/x will be equal to 1/(a+b+x) here even if we cut out the x we'll get back to the original question after running in circles
Last question toh symmetry break hone wale idea se bohot easily hogaya, bas 8cot8α ko 8/tan8α likhna tha Then 8(1-tan^2(4α)/2tan4α = 4cot4α - 4tan(4α), in this way cancellation will take place. 2cot2(α)= cot(α)-tanα and hence proved. One more idea is definitely tan(α)-cot(α)= - 2cot(2α) Idea struck because LHS-RHS=0 also single angle ko multiple mein convert karna hai
In last question i did it by rearrangement. I saw ki cot alpha and tan alpha were like terms to un dono ko rhs le jaake i converted them to sin cos, they became 2 cot2alpha, aur fir same method continue karle i proved the whole thing
One more approach is possible in the case of LHS=RHS, Solve both sides with each other and get a universal truth like 1=1 or 2=2.(Multiplying both sides by 0 isn't allowed 😂). If we found a false statement then our equation is false or we have made mistakes in solving. While cancelling we must be aware about the fact that the quantity that is cancelled shouldn't be 0. Students should be aware while squaring and cubing because it generates false roots. If necessary to squaring and cubing satisfy each root by given conditions.
Bhaiya/Sir please ek video jisme bahut chote chote yet imp basic doubt area ko clear krne wala videos bhi layigea.. Bahut baat questions solve karne k bich Mai bhot basic basic and confuse kardene wale like square root, etc...please❤
Yeah! You can definately watch it this series will help you to do books like rd sharma , pre college mathematics .....etc and you will be way ahead of your peers in terms of solving tough problems in mathematics
Sir ! I just really want to ask i am a 2025 aspirant! If telegram get banned then where did i got all those lectures of nucleus group lectures and all that materials? Should i copy all the targets ??
I was able to do it by half angle formula cot8@=1-tan²4@/2tan4@ →8cot8@=4(cot4@-tan4@) →8cot8@+4tan4@=4cot4@ Similarly, 4cot4@+2tan2@=2cot2@ Similarly, 2cot2@+tan@=cot@=LHS LHS=RHS=cot@
Last one I tried but by shifting cot 8 a it becomes more tough rather change in 1/tan 8a that would be more easier if we take cot 8a there it will be more tougher
One more student gave this way to prove the intro problem: s^4+c^2=c^4+s^2
She used homogeneity: s^4+c^2(s^2+c^2)=s^4+c^4+c^2s^2=c^4+s^2(s^2+c^2)=c^4+s^2.
Its like shifting the 1.
How elegant this solution is really!
📖To buy the paid courses of Problem Solving Courses of Calculus you can whatsapp me at 7535818547(no calls)
🔥THE 8 SOURCES YOU JUST CANNOT MISS:
1⃣ The Unbeatable Maths Course(Theory storywise+ ALL PYQs Typewise)= th-cam.com/play/PL2dPD7oDhSn9sWNfHbD8_VAs4as19rD6J.html&feature=shared
2⃣ Solve BLACK BOOK/SAMEER BANSAL EASILY! My Zero to ULTRA ADVANCED Maths Courses: www.youtube.com/@MathsUnpluggedIndia
3⃣ ALL QUESTIONS IN ADVANCED COME FROM THIS : CALCULUS PROBLEM SOLVING EXCLUSIVE COURSES : th-cam.com/play/PL2dPD7oDhSn9eObmrHoL3z49OBAAZbuiC.html&feature=shared
4⃣My Zero to Ultra Advanced Handwritten Notes/Sheet Link: drive.google.com/drive/folders/1TEIdSlr5fLnDA6y9tyyvUgvXxPyo8XDc?usp=sharing
5⃣ If you are in mess(just cant do what you planned to)/existential crisis/brutal pains in life, you need to first understand yourself , your life, this world , this existence, hence for you: th-cam.com/play/PL8W_3lFy-6-WMRoOTcEPTWDxuWbsqBbd9.html&feature=shared
6⃣Eye Opener Series: th-cam.com/play/PL2dPD7oDhSn-mTqPxhryoyzoSi3DkelXV.html
7⃣PSIM Series(Exactly how idea strikes in tough math problems): th-cam.com/play/PL2dPD7oDhSn_lH-jOlSdChSWYeEfBxcUH.html&feature=shared
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bhai one request from my side please upload a lecture on straight line and more on 11th class topics🙏🙏.U are literally the best guy for teaching maths u take every topic in depth making me understand it ,i really appreciate all ur work.Someday i would love to meet u in person
same my 1st thought was to take power 4 same side and second was homogenity.......
OP SOLUTION
bhaiya 1st wale seedha cos^2x-sin^2x = cos2x dekh sakte the 2 step me hi ho jaata
❤❤❤🔥💯
your videos are very helpful. thank you!
I am super excited for this episode. I can see improvement in my problem-solving skills.
True
2 lec mein?
From start of the series
@@PwiansOfficiallyJuth bol rha hai
Nahi bro sahi bol raha hai
Maine bhi halka sa change dekha meri thinking process mai
Sir app pls pls crash course continue kardo pls i along with many students find u and only u as the best and ideal teacher for maths , jee mains 4 mahine baaki haai aadha syllabus baaki haai maths thoda bhaut strong hua due to u but pls continue the series everyone is looking onto it and personally i pray for ur life to be back to normal
what happened to him?
@@harshineevaja1513 he is dealing w/ some problems of his own
17:14 Done with LCM and manipulation.
Take [1/abx]
common on both sides them out whole equation with come in form of
1/ab + 1/bx + 1/xa = ab+bx+xa
Now by cross multiplication simplify. Then it will be in form of
[a+b]/x + x[1/a+1/b]=-[ a/b + b/a +2]
Now multiply both by ab in order to form equations in form of a+b and .
Then you will see the sqaure of a+b on one side simplify .. and thus you will get the answer
X= -a .... X= -b
Triple thala for a reason 🥶
77.7 k subscribers
Congratulations 🎉 sandal Bhaiya
Hope ki yeh aage bhi continue reh hai
Bhai pure world ki population 8 billion hai@thenameishitesh
@@misterno-one9441 koi baat nhi badha denge 🤣💀 humlog 💀☠️
KEEP HIM UNDERRATED....PHLE HI ITNA ZYADA COMPETITION HAI
bhaiya thank you 30 min ke andar video banane ke liye i try to stay away from youtube and internet overall except watching some youtubers you are one of them toh pls try krna ayese hi banao (im a dropper) 2025 jee
tanA + 2tan2A+ 4tan4A + 8cot8A = cotA
2tan2A+ 4tan4A + 8cot8A = cotA - tanA....because angle same hai toh solve karna easy hoga
2tan2A+ 4tan4A + 8cot8A = 2cot2A
4tan4A + 8cot8A = 4cot4A
8cot8A = 8cot8A
Thanks
I Love him That's not mean it's my Dent 🤓☝️
Just gay things
@@jeeveshdev993 If its him , i am 🤓
@@jeeveshdev993 said by a shemale🤓
Took the method 1 of solving taking long one and reducing it to reach RHS....
when you told about the dissimilarity I put cot8x as Tan half angle formula and then solved first expression as I did it I realised it cut the previous term and it was the Eureka moment for me where it hit then I just did it again and again untill reaching cotx=cotx
Ik it is long approch and it has shorter and better approch either by method 4 or 5.....waiting for bhaiyas way of solving
Ps-it was very helpfull I will be sleeping proudy
can you please explain what you did I didn't understood
Can't wait till 8 😊
bhagwaan ki daya se mujhse 1st try me ban to gya but
jinse nhi hua unke liye bhai ne bilkul shi hint diya hai jo symmetery ko break kr rha hai uske around kuch socho.
Bhayya mai batau apka content itna achha hone ke bavjut be bohot jyada logon ke pass kyon nahi pahuchta
Kyonki
Apka content bohot hi accha hai and Student usko share or suggest nahi karte kyoki unhi lagata hai ki itni ache learning mai mere pass hi rakhu fir vo dosto ko batate nahi apke baare main
Main be ase hi kiya
How are you sir?! actually i am not a science student neither do i have maths in my 12th subjects. I study maths just for enjoyment.. Tbh i came to know about you just a few months ago when one of my good friend who is preparing for jee told me about you... I watched some of your videos from playlist 'chapter 1' and that 4 hour long video (apparently your most viewed one) And those were really mind blowing.!!! i totally loved them.. I checked out your description and checked the books you have suggested for maths enthusiasts!! I stumbled upon the most lovely teacher in my entire life Mr Paul Lockhart.. His books are so good i mean just mindblowing.. I had a very good time reading his books and i really want to thank you a lot for recommending those books.. But now i have completed all three of this books.. I really request you to please do suggest me some nice books please?? i mean is there any teacher as lovely as him ? please suggest me shit ton of books from some writers like him... Maybe about trigno (other than that eli maor one) , Calculus , number theory.. pnc.....Please bhai koi bdia c suggest krdo...!! i would really appreciate the suggestions..
Aur please muje ek aur suggestion do bhaiya.. Muje lagrha mai shyd ISI k liye paper du but mai uske liye eligible hi nhi hu bhut dimag khrab hota hai... Kya kuch ho sakta hai ?
eligible kyu nhi ho
Sir last que
Maine 2 baar effort maarke dusare me solve akr diya
Tanalpha - cotalpha solve kiya
Vaha se pattern pakada aur age easily solve ho gaya simple que tha after applying your strategy
1 of the most Beneficial series!💫
I solved the last question without hint and, ithought it in this way:-
Last one was in cot form, so i should try that it should similar with tan term, so used tan2x =2tanx/1-t² formula. Took tan common and found that terms were cancelling leaving 4/tan4x.went on with this approach. Again, and proved it in 3,4 minutes.
Thanks bhaiya for this wonderful series, and crash course due to which i have improved in maths
Well i took t and c at one side added with 4 tan 4alpha plus 8 cot 8 alpha basically rearrangement and proved with tan 2 alpha formula, but great initiative
Need someone like you in chemistry......❤
He is the 🐐 of maths🔥🔥🔥🔥
Bhaiya please don't discontinue this series . It is ineed life changing series for students like me . I know how you are feeling right now that i am putting that much efforts but not enough views are coming . I know bhaiya ye bhot disaapointing lgta hai jb aap poora efforts daale aur log aake efforts ka value nhi krre . So please please bhaiya please countine this series and i hope you will eventually get what you want and mai thnks bhi nhi bol skta aapko coz aap jo ye kaam kr rhe ho hm hmlogo ke liye wo uske liye thnks ek bhot chhota chiz hai bhaiya so please bhaiya please continue tgis series for students like me ❤
13:12 Sir I tried it ,but approch hi nhi lagi maybe bcz of trigo , but I got your point ❤
The most important thing is how to solve jee adv questions within 5 min because the main problem is we are able to solve at home but not in paper with time constraints
The state of immersion is fulfilled by maths unplugged channel only ❤
SIR PLS HELP IM STUCK. WHILE DOING L TO R IN Q1 , AFTER MANIPULATING LHS A LOT I GOT (cosA + cosB)(2cos(A+B)-1) HOW DO I PROVE THIS TO RHS WHERE A IS THETA AND B IS PHI
LITERALLY FOLLOWING HIM FROM 8 MONTHS HE IS GOLD ❤
bhaiyaaa thanks for this bohot bohot maza aa rha hai vaise ek request thi aap unbeatable crash course me coordinate geometry laa skte ho kya it'd be very helpful
Vote for complete crash course series for Jee mains 2025 🙏
PLEASE Bhaiya make a video on this PLEASE ❤
2:56 Bhaiya I Solved it by method 2 in first go !!!!!!! I can see that My maths is improving 😭😭😭😭😭😭😭
+1
bhaiya,One of the problem is remembering The entire syllabus of Jee.Can you please give some suggestions to remember all the things and improve striking time in exam.
Recently I came to know about this channel and I learnt a lot about manipulation and all. I just want to say that thank you so much bhaiyaa!❤️💡
I was looking for this series☺️
Pure TH-cam pe koi problem Solving pe itnaa khul k nhi bolta hai...
Keep uploading such a fantastic videos!🥰
BHAIYA MENE LAST VALA ESE SOLVE KAR DIYA THA
tanA + 2tan2A+ 4tan4A + 8cot8A = cotA
2tan2A+ 4tan4A + 8cot8A = cotA - tanA
2tan2A+ 4tan4A + 8cot8A = 2cot2A
4tan4A + 8cot8A = 4cot4A
8cot8A = 8cot8A
BRUH ... IT IS SAME AS MINE ... LOOK AT MY COMMENT ...
hw ka approach : by gods grace didn’t get stuck anywhere. Aapke laye jagah aya fir waha majne theta-phi/2 ko alpha bola toh terms bani 2cos(a)cos(a+2phi+theta) then got to cos(phi+2theta) +coa(2phi+theta) then phi + theta ko A boldiya and then just cos(a+b) then rearrange and common
Last question me 8cot8a ko 8/tan8a lekar tan 2a ka formula lagake short kar denge ye mane phele kiya tha pyq book se
Mai phir se apko batana chata hun dhayan dijiye ga ki mai apke channel je madhayam se batana chata hun ki please coordinate geometry ke notes de dijiye😢
Bhaiya wo jo cot ki term usko tan mein convert karke piche wale ke saath lcm le loge toh together they will be reduced to 1/tan4alpha fir iss term ko tan2alpha term ke sath loghe toh together they will reduce to 2/tan2aplha and finally iss ka last term tanalpha ke sath toh prove ho jayega
22:42 Cotx - tanx = 2cot2x
Yes
Thanks bhaiya, 👍🙏💫 ❣️ ✨❣️
It was really awesome 😎
Thank you so soo soo much 🙏☺️
✨✨✨✨✨✨✨✨✨
12:30 Iske baad product to sum transformation karne pe cos(2θ+ Φ ) + cos(θ+2Φ) mil jayega jisko split karke likh denge (θ+Φ)+θ and (θ+Φ)+Φ kyunki answer is in T ratios of these angles, fir bas re-arrangement
Bro thoda hint de skte ho ki kaise isko approach kre coz i am trying by using formula of cos 3 theta but i am getting stuck. denominator reduce hi nhi ho rha....
thanks a lot.
bhaiya meko lagta hai aapko uthwana padegaa 😂😂 kitti baar kahun bache hue chapters ke pyqs typewise le aao nhi la rhe .😢😢
Plz complete the "each pyq solved" series for vector 3d and coordinate geometry
Hint:22:34 tan ko cot mein badal do
18:58 proved 8cot8alpha ko tan ke form me laake then 2thetha form me tod diya. Fir aage terms kat te jayenge aur last me cot alpha bachega
Bhaiya why you discontinue pyq series please continue that series.😭😭
0:51 proved using homogeneity
Lol 😂 that's 10th class problem where only Pythagoras identity of sinx and cosx is used jee aspirant solve these problems in blink of an eye
@@ankitbishnoi4470 happy to see that your are happy
@@Harsh-hr1yq it's joyful to see that your annoyed but not showing 😂
@@ankitbishnoi4470 bro i also proved that using identity but in last lec bhaiya told us about homogeneity. Isliye try kiya mai isme galat kya hai?
bro is literally cooking with these thumbnails
Its just like watching series but different in which we inplement everything or learn
Last q I got two methods 1st cot8alpha ko tan4 me likhlo fir ho jayaga ya r-l approach se cot -tan hoga 2cot2alpha
not gonna lie but aapki videos se itna motivated tha ki sirf 10 seconds mai wo1988 wala question khud se kar liya..
keep doing bhaiya!!
Thankuu so much sir it is really awesome ✨💓💓💓💓💓💓
RD SHARMA QUESTION CHALLENGE SOLUTION
after what you did take x common - x(a+b)+ab/abx
now take ab common - ab(x(a+b)/ab+1)/abx
x(1/a+1/b)+1/x=1/a+1/b+1/x ---(dividing by x)
i think there's an issue with that solution basically {x(1/a + 1/b) + 1}/x will be equal to 1/(a+b+x)
here even if we cut out the x we'll get back to the original question after running in circles
Thank u so much bhaiyya itna achha content ke liye
Last question toh symmetry break hone wale idea se bohot easily hogaya, bas 8cot8α ko 8/tan8α likhna tha
Then 8(1-tan^2(4α)/2tan4α = 4cot4α - 4tan(4α), in this way cancellation will take place.
2cot2(α)= cot(α)-tanα and hence proved.
One more idea is definitely tan(α)-cot(α)= - 2cot(2α)
Idea struck because LHS-RHS=0 also single angle ko multiple mein convert karna hai
i did the same
Advance congrats for 100k bhaiya
Finally the legend is back 🔥 🔥
superb episode bhaiya .🤍
14:06 LHS-RHS=0 ??? Maybe
In last question i did it by rearrangement. I saw ki cot alpha and tan alpha were like terms to un dono ko rhs le jaake i converted them to sin cos, they became 2 cot2alpha, aur fir same method continue karle i proved the whole thing
2:40 the way my smile apeared 😂😂 damn mannnnn maths is truly beautiful
Bro the thumbnails are hilarious as always another banger for doing whats right
Outro is on god level 🎉🎉❤❤❤
FINALLY BHAI MAINE PROVE KARDIYA...
2tan2a + 4tan4a + 8cot8a = cota - tana= 2cot2a
4tan4a + 8cot8a= 2cota - 2tan a
4tan4a + 8cot8a = 4cot4a
8cot8a = 4cot4a -4tan4a
8cot8a = 8cot8a
HENCE PROVED
Me who jisne last wale question ko 1min me Bina pen ke prove kr liya💀....without even using the identity he said😅
16:58 bhaiya reciprocal kar ke ho gya bina lcm
great session sir, it really made me think deep in understanding process of problem solving
11 ma PCB main subject hai additional subject ma maths hai toh jee main aur advanced da sakta hai kya please reply 🙏🙏
Co ordinate geometry sir
Outro 🙏🙏❤❤❤❤
bhaiya ap physics chemistry bhi padhate kaash kitna acha hota 🥲🥲
ye Channel initially chemistry ka hi Tha😅
Chemistry?? Or physics...@@AtharvKumar-tm5jx
One more approach is possible in the case of LHS=RHS,
Solve both sides with each other and get a universal truth like 1=1 or 2=2.(Multiplying both sides by 0 isn't allowed 😂).
If we found a false statement then our equation is false or we have made mistakes in solving.
While cancelling we must be aware about the fact that the quantity that is cancelled shouldn't be 0.
Students should be aware while squaring and cubing because it generates false roots. If necessary to squaring and cubing satisfy each root by given conditions.
Bhaiya in last question we can use
Cot8a = 4[ cot4a-tan4a]
tana + 2tan2a+4tan4a +4cot4a -4tan4a
tana + 2tan2a + 4cot4a
tana + 2tan2a + 2cot2a -2tan2a
tana +2cot2a
tana + cota - tana
cota
Hence solved 😉
Cot8a ko vaisa likhneka idea kaise aaya bataao
Last question idea : L - R = 0 and apply tanA - cotA = -2cot2A
Amazing.....
thankyou for this series bhai... maza aarha _/\_MU
cot ko dusre side lejake ek chain dhekege to fir waha se easily proof ho jayega
I love you content..... I will even pay to watch this channel.
Bhaiya/Sir please ek video jisme bahut chote chote yet imp basic doubt area ko clear krne wala videos bhi layigea.. Bahut baat questions solve karne k bich Mai bhot basic basic and confuse kardene wale like square root, etc...please❤
7:15 ....I almost pondered for 15 mins here... I should ve just moved on!!! Life lesson learnt😅😅
Same here 😂
Can a tenth class student watch it ??? As I really need this
No
Yes
if its a need watch it, or its a want also watch it bcz it benifits you in future problem solving
Yeah! You can definately watch it this series will help you to do books like rd sharma , pre college mathematics .....etc and you will be way ahead of your peers in terms of solving tough problems in mathematics
Most interesting videos for jeee aspirants
I hope you complete the rest of the chapters in crash course series. It is veryy helpful cum beneficial👍
Sir please upload more physics lecture i will be so thankful
isme 8cot 8a + 4 tan 4 a = 4 cot 4 a aisa pattern banrha hai cot ko sin cos me convert karenge to
Can't wait more
9:55 ho gya sirr
Sir ! I just really want to ask i am a 2025 aspirant! If telegram get banned then where did i got all those lectures of nucleus group lectures and all that materials? Should i copy all the targets ??
Bhaiyya pyq ka course complete karoooo 😊
S⁴+c²=c⁴+s²
S⁴-s²=c⁴-c²
-s²(1-s²)= -c²(1-c²)
-s²c²=-c²s²
Hence proved!!
Bhai take tan alpha to RHS and then expand to sin and cos tou baar baar ek pattern bnega and question very very easily solved
ye hui naa badhia thumbnail Sir/Bhaiya
16:16 summary slide for me
GOAT FOR MATHEMATICS AND LIFE TIPS
I was able to do it by half angle formula
cot8@=1-tan²4@/2tan4@
→8cot8@=4(cot4@-tan4@)
→8cot8@+4tan4@=4cot4@
Similarly,
4cot4@+2tan2@=2cot2@
Similarly,
2cot2@+tan@=cot@=LHS
LHS=RHS=cot@
Bhaiya ie kya bansal k tha ? 12:27
22:41 8cot8@ ko tod dooo!!!
Fir lcm lelo
Or solve karo pura answer nhi bataunga 😂
Kuud mahanat karo
Bhaiya please ISI CMI ke bhi Qs lo main us exam ki bhi preparation kar rha hu
start with cot alpha term
Last one I tried but by shifting cot 8 a it becomes more tough rather change in 1/tan 8a that would be more easier if we take cot 8a there it will be more tougher
bhaiya can you please continue the pyqs series
I look upto you as my mentor and also a greek god with the language of maths