sir, i think so the FBD for link 3 is incorrect bcoz F43 can not act along the link, because for three forces to be in equilibrium they must intersect at any common point.
Sir I think the last step is wrongly calculated.... the direction of the 3rd force should be taken where the 1st two coincides... so the h value will reduce.. in this case
This method is wrong. You cannot know the direction or line of action of f34 initially. You have taken directly the line of action of f34 for drawing force polygon for the slider. ..the f34 has to be resolved into normal and tangential and then from the force polygon for 3rd link you have to derive the direction of f34. Your method is only suitable for one force problem. What you are dealing here is two force problem.
Wrong😐..Link 3 is three force link so you can't take f34 in direction of the connecting rod .. It will be solved analytically or by method of superposition in graphical method🙂...
If watched the whole video you would understand this is the easiest method to solve it instead of going for the convoluted ass method you suggested. He even tells you at the end that this is one of the methods and the other is the one you have commented. You should probably watch the whole video before commenting some dumbshit.
Namaskara sir. I had a backlog in Dom. Because of your video i was able to clear my exam. Your explanation is very clear.Thanks a lot sir. 🙂
Thank you
How to pass bro please tell
@@karananand175 try solving all the problems which Santosh sir has solved. And practice previous years questions.
@@vikashsharma-wy3sk bro that's the problem still no clue about module 4 and 5
Thanks a lot Sir.
This was really helpful and you made it very easy to understand.
Sir thank you very much... Bjt can u please explain how to denote the forces F23 or F32 in which situations,😔
can we do this question by taking different torques of different forces?
Thanku u sir...u are a life saver❤️
sir, i think so the FBD for link 3 is incorrect bcoz F43 can not act along the link, because for three forces to be in equilibrium they must intersect at any common point.
Nope, the answer actually right. Three forces do intersect at the piston/slider ( as in figure ).
very nice video sir....and upload more videos
Simple and very informative
Sir u will do problems on balancing of several masses rotating in different palnes?
I have already done
Sir please increase your audibility
Awesome video sir
Sir plese solve dynamic force analysis problems
Sir I think the last step is wrongly calculated.... the direction of the 3rd force should be taken where the 1st two coincides... so the h value will reduce.. in this case
Sir can u solve the problem in whc two torques are given and 3rd torque is unknown...plz upload ths video sir after solving...
th-cam.com/video/4Vk1iWeq7mY/w-d-xo.html
Rubesh how r u bro in Bellary
In graph problem is there know that problem ur upload sir...in turbo machines
Ty sir
Thank u so much sir.
Sir how did yu get 10.. In second stage of solving... Hw did yu take 1cm =200N I dint get it sir...
bd=800N.. ND in final process yu took 800 as 4cm.. Hw sir.. Plzz can yu explain me...
@@babygixxy...4702 We took scale as 1cm = 200N so for 800N= 4cm ..
Finall ly done and dusted
Sir plzz upload the video velocity triangles on turbo machines
Sir pls upload dme 1
Sir can u do problems on balancing forces
helpeed a lot thankyou
Thanks a lot sir
Sir if they ask away from crank centre then what direction we need to take the load? (< Or >)
then its opposite to fixed point
@@اللهالله-ل7د means load acting towards right
@@Nova-jc4jn yes
Nice video
sir pls solve the type two problem....soon
Thank you sir
Thank you!
thanks alot sir...
tq so much sir....
What do yo call that rolling scale?
Tahil Ahmed is that a question or answer 😂😂
thank you sir
Sir I am getting some different answers
It will effect on marks in external or not
No
@@santoshsgaidhankar5795 I got for link one is 598 Nm and u got 621
Answer is correct.
@@santoshsgaidhankar5795 sir were to take this crank
When the crank is 60• away from IDC
Were to draw angle at right or left
dynamic also sir
Scale is 200 not 100
Acha
This method is wrong. You cannot know the direction or line of action of f34 initially. You have taken directly the line of action of f34 for drawing force polygon for the slider. ..the f34 has to be resolved into normal and tangential and then from the force polygon for 3rd link you have to derive the direction of f34. Your method is only suitable for one force problem. What you are dealing here is two force problem.
If you take transverse and radial components of the f34 force the value of tangential component is nearly negligible so, you can do it like this way
Comment and reply are correct
Wrong😐..Link 3 is three force link so you can't take f34 in direction of the connecting rod ..
It will be solved analytically or by method of superposition in graphical method🙂...
I agree
If watched the whole video you would understand this is the easiest method to solve it instead of going for the convoluted ass method you suggested. He even tells you at the end that this is one of the methods and the other is the one you have commented. You should probably watch the whole video before commenting some dumbshit.
@@kashin111 😂😂 agree
Ha Ja chal apne baap Ko mat sikha
Thank you sir
Thank you sir☺
Thank you sir