BOLT TENSION and Tension at Non-Permanent Joints in Just Over 10 MINUTES!

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 24

  • @RavindraSingh-pr3rt
    @RavindraSingh-pr3rt 16 วันที่ผ่านมา +1

    I like all yours lectures, please never stop doing the great work you are doing, your lectures are a god sent gift for people who can't afford fees for expensive lectures

  • @vanzz3863
    @vanzz3863 8 หลายเดือนก่อน +3

    Man, props to the great editing and explanation of this topic!
    I’ve seen PAID courses with way less quality than your video
    Keep up the amazing work and I hope I can keep on watching your videos
    You just earned a new sub 😎

  • @forsakenV12
    @forsakenV12 2 ปีที่แล้ว +4

    My goodness.. your tutorial is awesome !
    Thank you !

  • @ianpemberton-f9p
    @ianpemberton-f9p ปีที่แล้ว

    Excellent clear explanations.

  • @sher.5027
    @sher.5027 3 ปีที่แล้ว

    Thankyou for your explanation, It is going to be helpful for my exam tomorrow.

  • @prashantbisht9884
    @prashantbisht9884 3 ปีที่แล้ว +1

    Thank u very much ... Now i can solve all the gate questions

  • @CarolineCA23
    @CarolineCA23 2 ปีที่แล้ว +1

    Thank you for your hard work! Do you have example where it asks for calculations finding the type of bolt (known weight, and external force)?

  • @rishabhjain1696
    @rishabhjain1696 2 ปีที่แล้ว +1

    What software are you using to present all these items?

  • @kittitattungsakul2672
    @kittitattungsakul2672 3 ปีที่แล้ว

    Thank you so much

  • @huuhungtran12
    @huuhungtran12 2 ปีที่แล้ว +1

    thanks you so much for this useful lecture.
    i just have a question about the way to define Pb load based on External load ( 03:44 )
    My understanding, for the pre-load condition, Bolt is under tensile load and members are under compression load.
    Then if we apply external load in tensile direction ( tensile load ), then members will be released the force.
    Mean that : force in bolt = Fi + Pexternal
    and Clamping force in plates = Fi - Pexternal
    Then it should not has C factor - Stiffness constant of the joint.
    please correct me if i was wrong.
    thank you so much !

  • @marwanabdelhamid7147
    @marwanabdelhamid7147 3 ปีที่แล้ว

    would you give us the slides or pdf to just keep up, and thank you for the videos.

  • @kristopherlowry1602
    @kristopherlowry1602 2 ปีที่แล้ว

    Great job explaining! Is there a reference book to this information?

    • @tomclwd4756
      @tomclwd4756 2 ปีที่แล้ว +1

      I personally have Shigley's Mechanical Engineering Design 11th edition (Chapter 8) and the video supports everyhting in the book. His videos are more clear and straight to the point.

  • @hazn136
    @hazn136 4 ปีที่แล้ว +1

    Hi, thanks for the great video.
    which drawing pad are you using sir ?

    • @LessBoringLectures
      @LessBoringLectures  4 ปีที่แล้ว +4

      Thanks! I was using a Surface Pro and the Whiteboard app. I've transitioned to an iPad Air 2020 since because of the constant stutter and slowdowns in Whiteboard

  • @axeld9108
    @axeld9108 3 ปีที่แล้ว

    Greetings! Another amazing lecture, thank you. Just one question related to the final example, about the value of the fc friction coefficient. Are both (fc and f) 0.15? Shigley do not show the value for the fc coefficient in a steel-steel combination.

    • @LessBoringLectures
      @LessBoringLectures  3 ปีที่แล้ว +1

      Yeah, the 0.15 values are just an assumption. Shigley's in fact doesn't show that steel to steel coefficient of friction. And thank you for the compliments!

  • @joshpineda308
    @joshpineda308 3 ปีที่แล้ว

    The equation shown at 5:42 (Fm = Pm - Fi), Fm is different from what you are stating and what is seen on the graph (Fm = Fi - Pm).

    • @joshpineda308
      @joshpineda308 3 ปีที่แล้ว +1

      Actually you are correct and my comment is mistaken. The graph shows the y-axis as absolute value |F|. So your equation for Fm is correctly depicted.

  • @jimf671
    @jimf671 ปีที่แล้ว +1

    Do not let this person or anyone who believes this near any substantial engineering project. This is the same mistake made in Eurocode 2 some years ago and has probably resulted in thousands of building and bridges across Europe being improperly designed.

    • @kelumo7981
      @kelumo7981 6 หลายเดือนก่อน

      who gives a shyt what you think or believe?😏its obvious you have never been in a classroom where such simplifications are common..we all know what is required,we are not dumb brainiac🤬

    • @Dwindledoodoo
      @Dwindledoodoo 2 หลายเดือนก่อน

      what do you mean? what happened?

    • @jimf671
      @jimf671 2 หลายเดือนก่อน

      @@Dwindledoodoo Hilti book showed the torque for the selected studs on a power station project as 270Nm. this was about 2007. Then the new codes were published and the new Hilti book said 150Nm. The workings that were published with the new code showed fasteners subject to factors of safety as though they were a concrete slab or a structural beam which is ridiculous. I put this to Hilti and it was referred back to their top people in Lichtenstein. The answer came back that yes, they knew it was wrong but it was the law now so they had to do it that way. So every building and piece of machinery in Europe is going to be improperly fixed to the ground? Yes. It's the law now. Not impressed. I haven't been doing that kind of work so I have no idea if any of that has been fixed in the intervening years.