@@sylvesterj95 Awesome man! Nice job, you were serious about passing this thing and that has been evident. Keep it going! I'm very happy to have helped in someways.
he said on the video that he could solve it using the trapezoid formula but he solved it using the breakdown method in order to apply different kinds of shapes
Hello, thanks so much for your videos it so much helpful. I just have one question concerning how you find dy, shouldn't it be dy= yc(total shape)- yc (the specific shape) instead of using yc of specfic shape?
He says it ALLLLLLL! good job and thank you for making it this simple.
I’m glad you found it helpful! Thanks Tarek!
Wow. I struggled a lot with MoI along an axis when I was in school. You explained it very well. Thank you!!
Thank you!!
Great video and explanation!
Well made video.
Thank you Albert!
Great problem. Got a very close answer using Yc, Ixc, and A formula for a trapezoid given in the manual. Approx 16,040 in^4
Nice! It should be very close, I'm glad you checked. Nice job!
@@directhubfeexam Passed the exam bro. Thank you for all your help in the process. I watched every single one of your civil videos.
@@sylvesterj95 Awesome man! Nice job, you were serious about passing this thing and that has been evident. Keep it going! I'm very happy to have helped in someways.
why couldn't we have just used the Ixc formula for trapezoidal shapes, and then add the deltaY*A?
[ (h^3*(a^2+4ab+b^2))/36(a+b) ] + dy^2*A
he said on the video that he could solve it using the trapezoid formula but he solved it using the breakdown method in order to apply different kinds of shapes
Hello, thanks so much for your videos it so much helpful. I just have one question concerning how you find dy, shouldn't it be dy= yc(total shape)- yc (the specific shape) instead of using yc of specfic shape?
Hello, I really appreciate your videos. Could you do a Dynamics video please and construction Engineering?