Thank you so much!!! I have a midterm exam coming up, and you made that really simple, thank you for taking the time to explain the concept!!! Your discrete math videos have been a life saver for not just me, but, many students in my university and around the world!!!!
well I realized you commented a month ago but ill explain anyway, reason why she substituted Cn2^n for an is because A2^n has the same root as C2^n, so you have to separate those two with Cn2^n so its A2^n + Cn2^n
i have the same doubt and my final is tomorrow help😢 Edit : I found a better explanation. they say that if the homogeneous solution and guessed value both have the same function (here 2^n) they will just get cancelled out so we multiply by n for the particular solution guess to linearize it. hope it helps!
Hi thanks for such a great video, but i have small doubt. Like my equation is an=(3*an-1)-(2*an-2)+3( -1 and -2 are in subscript) by solving homogeneous part, i get A*2^n+B. For particular solution my guess function is C. If we substitute we get C=C+3. So here what is value of C as C=C+3 has infinite soln. I will be thankful if you could help me in this
If your vedio is more than 20 minute i will be more happy,Not matter what the duration is.. If It's for 1 hour then Also I will looking forward to such Quality Content ❤️
can you explain more about why u implied that the coefficients in the equation: -2n(c+1) + (-2d+3c) = 0 are equal to zero?? I'm rly confused bout this. Hope u'd tell me ...
"Choose whatever variable makes your heartbeat faster."
THANK YOU!! You are playing a huge part in my discrete mathematics journey! I may end up passing Discrete math after all!
Awesome! Best of luck!
Wow. You made it that simple. Way to go!
I can't believe this channel hasn't hit a million subs yet.
Thanks so much ma'am for helping us out here.
Man, chapter 8 is a bit of a doozy!! Can't say thank you enough for these videos. I would be entirely lost if it wasn't for you.
Thank you so much!!! I have a midterm exam coming up, and you made that really simple, thank you for taking the time to explain the concept!!! Your discrete math videos have been a life saver for not just me, but, many students in my university and around the world!!!!
On duration 18:13, you have substituted an for Cn 2^n. Why tho? I didn't get it.
well I realized you commented a month ago but ill explain anyway, reason why she substituted Cn2^n for an is because A2^n has the same root as C2^n, so you have to separate those two with Cn2^n so its A2^n + Cn2^n
@@wrx1th873 Still don't get it
@@wrx1th873 this makes no sense at all
@@levylost8550 i get it
i have the same doubt and my final is tomorrow help😢
Edit : I found a better explanation. they say that if the homogeneous solution and guessed value both have the same function (here 2^n) they will just get cancelled out so we multiply by n for the particular solution guess to linearize it. hope it helps!
This channel deserves more views.
Hands down best vid on this topic 🙌
This was very helpful, Thank you truly for your service.
After discovering your videos I went from bieng scared to pass descrete math with a C- to the real possibility of passing with a A
at 18:00 why n is added there from table n should not be there am i right ?
yeah i'am confused
5:41 Didnt we write A(r)^n + B(n)(r)^n while solving the homogenous part in case we get a single root in the previous videos?
a_n = 3a_n-1 is a first order linear recurrence relation. Ar^n + Br^n is used for second order. Watch 8.2.1 then 8.2.2
I'm barely passing, the paper's at 9 in the morning and here I am at 3am watching through your videos as fast as possible. I hope i pass :_:
thanks..... your video is very helpful
Omg thankyou so much you made it way easier to understand😊
I got the inhomogenous relation a_n = 6a_n-1 - 5a_n-2 + 1.
Unfortunately, guessing a^p_n = c doesn't seem to work.
Can you help me out?
You are Really an Amazing Teacher
Thank you so much!
11:44 why did you replace cn with -n?
cuz c=-1
Hi thanks for such a great video, but i have small doubt. Like my equation is an=(3*an-1)-(2*an-2)+3( -1 and -2 are in subscript) by solving homogeneous part, i get A*2^n+B. For particular solution my guess function is C. If we substitute we get C=C+3. So here what is value of C as C=C+3 has infinite soln. I will be thankful if you could help me in this
Your content defeinly belongs on Udaicy or EDX or something. I've only seen a bit of it but it's so good.
thankyou mam my end sem is tomorrow OwO
what would your guess be if f(n) was of the form n * (r ^ n)?
Thank you very much 😊
If your vedio is more than 20 minute i will be more happy,Not matter what the duration is.. If It's for 1 hour then Also I will looking forward to such Quality Content ❤️
thanks alot ... teacher
can you explain more about why u implied that the coefficients in the equation:
-2n(c+1) + (-2d+3c) = 0 are equal to zero?? I'm rly confused bout this. Hope u'd tell me ...
That is the homogeneous portion of the function. Homogeneous means that it is equal to zero.
Thank you, seriously
Is there a video that u solved the first type witch is c?
Not sure I understand what you are asking, but please watch all of the 8.2 videos. They all go together
@@SawFinMath he means at minute 2:14 the first order in the table when it equals c
@@skdkdmdmsjdjdj2377 Thanks for the clarification! No, I don't believe I have an example like that.
thankyou i love you the course it is very nice again thankyou very much
🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Thanks
All respect
❤❤❤
👍👍👍