Watched 3 videos and was still stumped ....then I found this ....really well explained particularly the negative acceleration....many thanks from Scotland. 🥃
My book says that when the graph goes flat that there is no velocity no motion. It has a sample when a car is traveling as the graph is rising then the car is moving forward, when the graph is flat the car is stopped, and when the graph is falling the car is going in reverse.
So when there is an upward slope coming from below the x axis does this mean that an object is slowing down going backwards . The velocity would be getting closer to the x axis, but acceleration becomes positive. Could you also call this deceleration for the behavior i just described?
Deceleration is a term I recommend you avoid using. Because it gives a misguided idea that slowing down is the opposite of acceleration. In reality, slowing down, speeding up, and changing direction are all forms of acceleration the way the term is used in Physics. You are correct that that the object would be slowing down, if its velocity is negative, and its velocity is getting closer to zero. The magnitude of velocity decreasing, is what make it slow down. Remember that it is arbitrary which direction we assign as negative. We could've just as easily assigned the opposite sign convention to our directions, and this would then be an object moving with positive velocity that is decreasing.
Hi, if anyone can answer it’d be really helpful. If she says it’s a negative acceleration below x axis (at 1.34 timestamp), it would mean slowing down right? But she also says the graph below the x axis is acceleration just moving backwards (at 2.41 timestamp) hence speeding up. So which one is it?
No im pretty sure that the object is only slowing down (constant deceleration) until it reaches the x axis where it becomes stationary. Then as the line goes below the x axis the object turns around and goes backwards and increases in velocity (constant acceleration). Hope this helps
The velocity decreases until it reaches the x axis at which point it becomes stationary, as it continues to go below the x axis it starts speeding up but in the negative direction so the velocity would be negative
Watched 3 videos and was still stumped ....then I found this ....really well explained particularly the negative acceleration....many thanks from Scotland. 🥃
I have an AP Physics test tomorrow and this helped so much
Omg i have mine tmr too 😭😭😭
@@bethanyorea6659 I wish we could have studied together
@@adejanelson3870 heh, yup
How did you do?
also got an AP physics test coming up.
The clarity condenses the concept into visually understandable form. Words fail me. Thank you.
WOW this distance learning sucks, but this video helped so much. Thanks!
Excellent explanation, Jennifer, thank you!
this video is extremely helpful!
Bless your soul prepping for finals 🙏
My book says that when the graph goes flat that there is no velocity no motion. It has a sample when a car is traveling as the graph is rising then the car is moving forward, when the graph is flat the car is stopped, and when the graph is falling the car is going in reverse.
that might be displacement time graph
you are an awesome teacher!
cant believe the only person to comment on a 4 year old video was only 12 hours from me watching it :p
Awesome video. Very helpful
Thank you 🙏
U are a saviour!
Thank you now I won’t die
i wish i found this video last year when I took ap physics but it is very helpful for ap calc too
Thank you so much for that
Very good.
Thank you so much!
Thanks this helped with explaining these graphs to my daughter
Now how to describing such movement
AMAZING !
you right love from india
Thanks
Hi you are getting for which exam and what is your country
Thank you
The first graph I calculated the displacement as 8.5 can someone tell me if I’m right
Omg thankyou, I was so frustrated
Me too I from india
how i find displacement in t=5-7s
So when there is an upward slope coming from below the x axis does this mean that an object is slowing down going backwards . The velocity would be getting closer to the x axis, but acceleration becomes positive. Could you also call this deceleration for the behavior i just described?
Deceleration is a term I recommend you avoid using. Because it gives a misguided idea that slowing down is the opposite of acceleration. In reality, slowing down, speeding up, and changing direction are all forms of acceleration the way the term is used in Physics.
You are correct that that the object would be slowing down, if its velocity is negative, and its velocity is getting closer to zero. The magnitude of velocity decreasing, is what make it slow down. Remember that it is arbitrary which direction we assign as negative. We could've just as easily assigned the opposite sign convention to our directions, and this would then be an object moving with positive velocity that is decreasing.
Hi, if anyone can answer it’d be really helpful. If she says it’s a negative acceleration below x axis (at 1.34 timestamp), it would mean slowing down right? But she also says the graph below the x axis is acceleration just moving backwards (at 2.41 timestamp) hence speeding up. So which one is it?
No im pretty sure that the object is only slowing down (constant deceleration) until it reaches the x axis where it becomes stationary. Then as the line goes below the x axis the object turns around and goes backwards and increases in velocity (constant acceleration). Hope this helps
The velocity decreases until it reaches the x axis at which point it becomes stationary, as it continues to go below the x axis it starts speeding up but in the negative direction so the velocity would be negative
DANKE SCHÖN
Keep it up
Thanks mam tell me these things
Thanl youuuu
Love from india
🙌
I got the exact same graph on my board exam
those who still didn't understand try this link:
th-cam.com/video/Ka9xWAmWBow/w-d-xo.html
hope it helps
Too Bad
Thank you
thank you so much!