ME3351 Engineering Mechanics april may 2024 question solved with bgm version

[@சஞ்சய்01444]

Thanks sir

[@rajamanirajamani2534]

❤❤❤

[@Madhan-t8y]

11 a small dout part 4 digram la fx(q) nenga yen 100 cos 40 use panninga pls tell

[@android2.049]

Force 100N acting towards y axis 40 deg..so fy is 100 cos 40..
Fx is 100 sin40..
All other forces towards x axis only..so fx is cos..fy is sin.

[@mekalakranthi5867]

Sir tomorrow engineering mechanics arrear exam sir , important questions upload pannungey sir

[@kingsmech]

Check the previous videos.

[@SHUNMUGAPRIYAV]

Sir 11) a.force 200N ku angle 26° aana en 30° eduthurukinga

[@kingsmech]

Just rounding off for taking values..please use calculator

[@Ajay-od9yl]

Sir 2024 nov /December exam me3351 ku poduga sir first question right illayanu paruga sir

[@kingsmech]

Coming soon

[@Ajay-od9yl]

@@kingsmech today varuma sir

[@kingsmech]

@Ajay-od9yl
Not sure boss..wait.,

[@RAGULGANDHIK-gn7to]

Voice kaakala sir

[@kingsmech]

No voice only questions and answers..
Refer playlist lot of solved questions with explanations

[@Madhan-t8y]

Sir pls upload more videos for engineering mechanics arrier😢😢😢

[@kingsmech]

So far 148 videos loaded..Will load more..dont worry😀

[@Madhan-t8y]

Pls anyone know tell pls😢😢

[@RAGULGANDHIK-gn7to]

Bro 4g silver parunga

[@RAGULGANDHIK-gn7to]

Atten all

[@kingsmech]

@SHUNMUGAPRIYAV @சஞ்சய்01444 @Mohanmuralidharan @MohamedShafik-kx1ny @KavirajanKkm @Ajay-od9yl @mohammedussin-wd9hq @musthafaabdul5919 @gopikamani-l8p @dharshan5138

[@Mohanmuralidharan]

14a Fx -0. 25-F=0 F= -0. 25 negative it's correct please explain details

[@kingsmech]

That step not necessary.. follow the next steps.,