6:05, the phase angle φ = tan⁻¹(1/wCR) there should be no (-) sign before tan⁻¹ For a high pass passive filter: A = R/(R + Xc) = R/{R + (1/jwC)} but j is in denominator so by multiplying j both in numerator and denominator we get 1/jwC = -j/wC so, R/{R + (1/jwC)} = R/{R -(j/wC)} And to get the transfer function we divide by R in the whole denominator and numerator, So transfer function is, 1/{1 -(j/wCR)} φ = -tan⁻¹[(coefficient of imaginary part)÷(real part)] Hence, φ = -tan⁻¹[(-1/wC)÷R] = -tan⁻¹(-1/wCR) = *tan⁻¹(1/wCR)* [ since, sin⁻¹(-θ) = sin⁻¹(θ) ]
Sir, your explanations are so easy like breathing and your way of speaking is very humble as well. I have shared this playlist and recommended your channel in our electronics whatsapp group ❤️
Sir, why didn't you connect R ' to ground?? What happens if we connect like that ? We can connect R' to ground and give the feedback signal to base from between of third capacitor and R' na sir ??
The topic is super clear organized...trust me thats a skill
Thank you for your kind words.
6:05, the phase angle φ = tan⁻¹(1/wCR)
there should be no (-) sign before tan⁻¹
For a high pass passive filter:
A = R/(R + Xc)
= R/{R + (1/jwC)}
but j is in denominator so by multiplying j both in numerator and denominator we get 1/jwC = -j/wC
so, R/{R + (1/jwC)} = R/{R -(j/wC)}
And to get the transfer function we divide by R in the whole denominator and numerator,
So transfer function is, 1/{1 -(j/wCR)}
φ = -tan⁻¹[(coefficient of imaginary part)÷(real part)]
Hence,
φ = -tan⁻¹[(-1/wC)÷R]
= -tan⁻¹(-1/wCR)
= *tan⁻¹(1/wCR)* [ since, sin⁻¹(-θ) = sin⁻¹(θ) ]
Sir, your explanations are so easy like breathing and your way of speaking is very humble as well. I have shared this playlist and recommended your channel in our electronics whatsapp group ❤️
Thank you Dear.
Keep learning Beta ✌
Bhai aap ka bhoat shukriya definitely i will share this video list with my friends 😊
Thank you Dear 😊
I will definitely recommend your videos to my friends 🌸.
Thank you Beta 😊
maine to kar diya hai mera pura group sir ki video se padh rha h taki pass ho sake 2july ko AC ke exam me 😅
Simply Great sir , you made the topic so easy to understand
Sir in the same way make video's on multivibrator using transistors and their applications
Thank you for your kind words ❤
Thanks sir for such great explanation.
Welcome Dear.
Sir your teaching style just looking like a wow 🤩 🤟🤟
😄😄
Very funny Dear. Please share ❤️
Thank sir.
Subscribe kar diya hai
Thank you Dear ❤️
Good content sir please keep providing good quality content
Keep supporting me.
Thank you 😊
Thanks u dir👍👍👍🙏🏼🙏🏼🧡🧡😀😀
You are welcome Beta 😊
Keep learning.
thodi theory bhi de diya kroo
Sir, why didn't you connect R ' to ground??
What happens if we connect like that ?
We can connect R' to ground and give the feedback signal to base from between of third capacitor and R' na sir ??
Sir sir please can you tell this.....
Please don't ignore
I want it in telugu or english language please
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