I swear I´ve been watching for two days ,videos of 1 hour to understand this, and just now I found out your video. Perfectly explained! Thank you so much!
Because these are definitne integrals (that is they are integrated from 0 to 2 pi) the x goes away. This is true anytime an integral is evaluated at specific x values. Though in this specific case the x actually goes away before we even evaluate it because when you multiple e^-x and e^+x they add together to give you e^0. Does that help?
When normalizing you always multiply the complex conjugate time the original wavefunction. The complex conjugate is the same as the original wavefunction but with the signs of any i flipped. The i's will (at some point) cancel out and result in a real valued function. This is good because we should never get an imaginary probability haha :)
Perfect video, thank you so much, it really helped me (also your complex numbers video), but by the way, why I am learning this in grade 12 of school? And yet I still have to learn the momentum and solve Schrödinger's equation... :(
Hi Kathir, Its not that you only keep the real part, its that when you multiple the wavefunction by its complex conjugate you always get a real value. This is also good, because we shouldn't get imaginary probabilities.
Hours and hours reading a lot of text book with a tons of confusion solved by your explanation in a coupe of minutes. Thanks you very much
Absolutely outstanding! No one has explained this anywhere near as succinctly.
I swear I´ve been watching for two days ,videos of 1 hour to understand this, and just now I found out your video. Perfectly explained! Thank you so much!
Thank you for the clarification, youtube educators really are something special, you have a gift ty man
You are so awesome at explaining this complex concepts with ease.
I cannot tell u how easy u made it !!!!!!!!!!!! Definition are so damn confusing !!! Thank u sooo much sir !!!
where have you been all this time? my exam is in 2 days i was freaking out but you sir are the lord and savior , thank you sooooooooo much
That is certainly too high of praise lol. There is only one of those.
@@RealChemistryVideos :D
excellent explanation: THANK YOU very much
awsome explanation.
thankyou
Tnx man u are 10 times better than my professor
You explained this perfectly
Wow like this was so helpful even though its hours before my test this video saved my grade a little ! thank you!
So glad it helped!
Excellent Explanation...
It was simple and clear ....thank you..!!
Very helpful, thank you!!!!
THANK YOU! YOU ARE AMAZING
感謝~你解決了我困擾已久的問題
I have my Quantum Physics Exam in 21 hours and I think you saved my grade lol
what happened to the X when you integrate it?
Because these are definitne integrals (that is they are integrated from 0 to 2 pi) the x goes away. This is true anytime an integral is evaluated at specific x values. Though in this specific case the x actually goes away before we even evaluate it because when you multiple e^-x and e^+x they add together to give you e^0. Does that help?
what do you use for normalizing a wavefunction that is real (no i in the function)
When normalizing you always multiply the complex conjugate time the original wavefunction. The complex conjugate is the same as the original wavefunction but with the signs of any i flipped. The i's will (at some point) cancel out and result in a real valued function. This is good because we should never get an imaginary probability haha :)
Thanks a lot
Perfect video, thank you so much, it really helped me (also your complex numbers video), but by the way, why I am learning this in grade 12 of school? And yet I still have to learn the momentum and solve Schrödinger's equation... :(
Why we are taking real part only?
Hi Kathir,
Its not that you only keep the real part, its that when you multiple the wavefunction by its complex conjugate you always get a real value. This is also good, because we shouldn't get imaginary probabilities.
@@RealChemistryVideos yes.. Now it is clear.. Thank you for your reply
dude thank you
Thank you!!! :)
thank you!
this is the first time independent solution ive handled xD
Good ..