How to Find Out Rank of Matrix

A common approach to finding the rank of a matrix is to reduce it to a simpler form, generally row echelon form, by elementary row operations. Row operations do not change the row space (hence do not change the row rank), and, being invertible, map the column space to an isomorphic space (hence do not change the column rank).
This video will show you how to find rank.

[@liberianewsagency199]

Thanks man, so simple to understand after 8 years

[@adamoja4295]

Wow

[@paleesemendy7497]

thank you for the simple and straight forward explanation

[@nazifataha8868]

Great explanation. I was writing a code in R to compute the rank of a matrix and I use this video to help me write the code in just a few minutes. Thank you1

[@zarinalee7702]

The best explanation! THANK YOU SO MUCH!!!

[@BUBULETA4772]

keep it up helpfull

[@dacheisiah6383]

good 👍 nice teaching short and direct have really understand

[@sagarika9861]

The best video on this topic, thanks alot.

[@HowTomakeitdone]

thanks dear.

[@kanishkaravindranath9314]

Found what I was searching for within the first two minutes

[@wizardofalledits8752]

This helped me A LOT..thank you so much

[@allanoh]

The best explanation..Keep it up

[@tessarml7157]

Thank you so much! finally understood!

[@muddassirghoorun4322]

Thank you for the clarity of your explanation. Keep up the good work.. Subscribed.

[@laurakuz55]

Best explanation ever! Thank u a lot! I searched for it several days !

[@HowTomakeitdone]

Thank you for your nice comment.

[@enesince909]

I understand you very well although i don't know English very well. Thank you for your explanatory statement.

[@donaldkimball7662]

you are a legend

[@kora2511]

thanks

[@rockyjoe3817]

Nice video but isn't the column[1 , 2] a multiple of [2 , 4] since it can be expressed as 0.5[2 , 4]? Correct me if something is wrong please, thanks!

[@mr.learner581]

sorry I didn't get it.can u explain again ?

[@zacariasboi3266]

I know I’m late to respond to this, but [1, 2] would be considered a product, not a multiple. On the other hand, [2, 4] is a multiple of [1, 2]. The difference is if you’re multiplying by a value below or above 1.

[@fauzansyauqi6912]

thank so much sir

[@khojanemoses9570]

You are right on point. I agree with Laura this is the best

[@maxhughesgray2591]

This was an excellent video! Thank you very much!

[@asal3169]

best explanation ever

[@elixar_]

why do we find the number of independent columns/rows? What is its significance?

[@magitobaetanto5534]

Great explanation!

[@sudheercherukuri5533]

Thanks very clear explanation.

[@kanishkashekhawat7660]

great.thanks

[@prakashj3436]

Thank soo much

[@borhanuddinkhan8781]

Great explanation. Thanks a lot 🖤

[@tahafarshbaf9348]

clear toturial👌

[@avinashkaur1950]

Very helpfull sir ty

[@vitalivardanidze503]

Great video, well explained, really helped

[@mykytakomarytskyi5066]

thanks! really simple and informative

[@Bunnxies]

Appreciate your help.

[@user-hn1qv3qh8m]

this video helped me a lot
thank you so much

[@HowTomakeitdone]

You are welcome :-)

[@staridrazenarhiva5720]

Well done thank you

[@chanakyatiwarifitness168]

You nailed it bro... Excellent

[@HowTomakeitdone]

thank you dear

[@hesarusenithwannigama9324]

what a genius.. Thank u sir.

[@HowTomakeitdone]

Thanks for your comment :-)

[@chanakyatiwarifitness168]

Plz add more and more videos....

[@niteshkumarmaurya1972]

Bahot hard...

[@JUSTaRANDOMkidXX]

thank you so much

[@anbitsprivateaccount7993]

Thank you so much! 😊

[@BOBofGH]

So is the first column vector always independent in your first method?

[@PravinJanjal92]

Great job

[@KayYesYouTuber]

Good job. thanks

[@MariaRuiz-xe2lv]

At time 2:44 wouldn't the column 2,3,4 be dependent since you can get to it by doing column1 - column 3?

[@kanishkansenthilkumar7262]

Yes, it can be. You can even say column1 is dependent on column 2 and 3 as (column2-column3).

[@BOBofGH]

Yes, but it's one way around or the other. They can't both be dependent on each other. One is considered independent and the other dependent.

[@josephineackah-cudjoe9943]

What is R2 and R1? The explanation isn’t clear

[@vader4200]

He meant row 1 and 2

[@BOBofGH]

This method doesn't seem to work for nxm matrices, only symmetrical ones.

[@felipeignaciocastrojara5065]

Squared matrix not symmetric ones*

[@acetob1739]

Amazing!
You deserve more subscribers.
Thank you.

[@HowTomakeitdone]

thanks

[@MSRana-ub5gr]

For the 1st example.. it is said that the first column is independent. But it is also a multiple of 2nd column in a way. If we multiply 2nd column with 1/2 we get 1st column. How is it independent? I would appreciate if you explain it to me please. I am confused. Thank you in advance.

[@nsathiya4169]

We won't get bro... Listen carefully
2/2 will be 1..what about 3/2 nd 4/2

[@memergamer312]

Is 4×4 also same?

[@aaskyboi]

Bravo!

[@Padmaguru1955]

In fact I am unable to write those operations plz help me how write those operations

[@Padmaguru1955]

How r u writing the row operation

[@naimgorgani953]

If we summarize your definition of Rank of matrix it is: "Convert the matrice to a lower zero Matrice. Count the Number of nonzero diagonal elements. That is the Rank of matrice." As far as I know this is wrong.
As far as I know You should turn your pivot elements into 1 then count,

[@coxixx]

i think there is a problem. in second example c1+1=c2 so c2 is dependent. am i right or not?

[@IkikaeruRaimei]

To be dependant, it needs to be scaled or a combinaison of independant rows... Doing +1 doesn't mean it's dependant.

[@mohammadalshawabkeh5791]

Gold.

[@LISA-wj8li]

how we know the rank is 2 please tell me

[@HowTomakeitdone]

if after converting your matrix into echelon form, you get two non-zero diagonal elements then it's rank 2 matrix.

[@sreecharan4300]

bro.. it is number of non zero rows and not number of non zero diagonal elements..rectify it.

[@abhishekgatla]

to For 4×4 matrix

[@kmviews928]

Legend watching in 2024 💥💥💯😅

[@zr0724]

nice , but make your videos a little fast

[@Padmaguru1955]

I am unable to understand

[@shmoemoe4718]

Baliskala Paticula La Donut!

[@hrithikkm3592]

Thanks