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All good comments, folks!
I also got -i.
How about a shorter path: raise both sides to the power -i and there's your principal solution.because (z^i)^-i = z^1Slightly longer is raising both sides to 1/i, but that's the same
Just draw e^(-i pi/2) in the complex plane. r = 1 theta = - pi/2 => (-i)
Raise both sides to the power i and you can miss out the ln bits.
That is so smart! Never occurred to me 😄
@aplusbi Thanks! Keep them coming 😁👍
I would start with z = r *(e^(i*(theta))). So now we got e on both sides.
Z(w)=e (w )lnz can anyone please tell me what the w stands for
All good comments, folks!
I also got -i.
How about a shorter path: raise both sides to the power -i and there's your principal solution.
because (z^i)^-i = z^1
Slightly longer is raising both sides to 1/i, but that's the same
Just draw e^(-i pi/2) in the complex plane. r = 1 theta = - pi/2 => (-i)
Raise both sides to the power i and you can miss out the ln bits.
That is so smart! Never occurred to me 😄
@aplusbi Thanks! Keep them coming 😁👍
I would start with z = r *(e^(i*(theta))). So now we got e on both sides.
Z(w)=e (w )lnz can anyone please tell me what the w stands for