let a=(3-4costheta)i-(4sintheta)j and b=(4-5sintheta)i-(5costheta)j for theta belongs to (0,pi/2)

[@US-6STUDIO]

👌🏻

[@samrt_boy-f9n]

👌👍

[@ramprateekdharoor6626]

Wow sir awesome, another amazing video which is helpful as this also not available on google . And covered it so clearly. 👍🫡

[@chiragprakash2823]

👍

[@manasagangaraja]

Very nice explanation sir

[@sushmithapremkumar7213]

Nice explanation sir

[@su-jax]

Understood Sir 👌👍

[@divyadas_2504]

Understood sir 👍🏻

[@BhumikabaiBhumikabai]

👍👍

[@Hindutva_Hindu013]

Super sir.❤ understood Sir

[@srikanta.y.r.3110]

Got it sir 👌

[@pritham07]

Superb explanation Sir ⚡️

[@Ravikanth-283]

❤❤❤ Nice explanation sir ❤❤❤

[@aratipandit579]

I didn't understand how u got its decreasg func....shldnt u 1st check by differentiating it?

[@JEEMATHSADDA]

By substituting the given interval only, we will get a clarity. Like cosx is decreasing in interval [0,pi/2] (cos0=1,cos(pi/2)=0)
Like this , i explained in video by taking limits because in question it is open interval

[@Mou-d9u]

But it may decrease first and then it can increase know sir

[@rabiprakashsha3924]

Your logic is wrong why because f'(theta ) < 0 only for theta belong to ( 0.65,1.57) in this interval it is decreasing but in (0,0.65) derrivative > 0 please don't misguide the students with wrong logics.

[@JEEMATHSADDA]

Can you please tell me , is f(x)=x^3 is strictly increasing by using your concept of first derivative???

[@bullymaguiresdirtsupplier]

​@@JEEMATHSADDA it is strictly increasing using first derivative.

[@JEEMATHSADDA]

@@bullymaguiresdirtsupplier f(x) is strictly increasing then f'(x)>0 but f'(x)=3x^2 greaterthan or equal to zero

[@chamundeswarireddy3489]

This is not how you explain it sir

[@shobhakruthika81]

Nice explanation sir

[@BarryM-c1r]

Understood Sir 👌