Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!!
What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on TH-cam) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. 11 chap 5 || States Of Matter - Gaseous State 01 | Introduction | Basic Gas Laws | IIT JEE /NEET| th-cam.com/video/H4h4vsJ9it0/w-d-xo.html 11 chap 5 || States of Matter - Gaseous State 02 || Ideal Gas Equation IIT JEE / NEET || th-cam.com/video/cgaNiTvh33E/w-d-xo.html 11 chap 5 || States Of Matter - Gaseous State 03 || Dlaton's Law Of Partial Pressure IIT JEE / NEET th-cam.com/video/mbowrScsq5I/w-d-xo.html 11 chap 5 || States of Matter - Gaseous State 04 || Grahm's Law Of Diffusion IIT JEE /NEET || th-cam.com/video/MS9Uk43U5eg/w-d-xo.html 11 chap 5 | States of Matter - Gaseous State 05 | Kinetic Theory Of Gases IIT JEE / NEET| KTG th-cam.com/video/EV6BNZ_F8zo/w-d-xo.html 11 chap 5 | States of Matter - Gaseous State 06 | Types of Speeds of Gas Molecules | RMS velocity th-cam.com/video/c9CRzUiDNMg/w-d-xo.html 11 chap 5 | Gaseous State 07 | Real Gas and Ideal Gas IIT JEE /NEET | Compressibility Factor Z || th-cam.com/video/MKo0d51Udxs/w-d-xo.html 11 chap 5 || Gaseous State 08 || Real Gas Equation || Vander Waal Correction || IIT JEE /NEET th-cam.com/video/dJHs85IPs-w/w-d-xo.html
The first drop of liquid will appear at a distance of 4m from end X. Those who are watching in 2020, hit the like button. Alakh Sir should be awarded National Award.
My base of chemistry is quite weak I need lot of time to understand a topic of chemistry But after watching your video now I can understand concepts more easily
When u see old lectures of alakh sir, and the advertisement came of physicswallah app or current alakh sir... Then i realised what hardwork always pays. He proves that consistency and honesty make someone successful. When his success makes a better future for a lots of students that's called real work. ❤️
Answer:- According to formula. d/t__d/t = √M(O)2/M(H)2. Solution:- d/t__5-d/t = √32/2 d/5-d = √16 d/5-d = 4 (by cross multiply) d=4(5-d) d = 20-4d d+4d=20 5d = 20 d = 20/5 d = 4m. So, the first drop of liquid will appear at 4m.
47:32 *4m* take a distance "d" and "5-d" where d is distance of H2 And 5-d is for O2 Note : time is same because it's happening at same time. now use formula : (d/t)/(5-d/t) = √(32/2) d/5-d = 4 d = 4m *hope it helps*
Attending your lecture is like sitting in class.... the moment u start speaking the whole atmos changes around. And the best part is each time I attend your lecture i go back with a better and improved version of mine.
Unacademy Vedantu byjus. All platforms are good but they want to earn money and make videos leanthy . But our ALAKH PANDAY sir wnt to videos as useful for students who want to crack any entrance exam. If you are agree then like here 👍❤️
48:3 Question- Let the distance from end X, first drop of liquid appears x metre And distance from end of Y, first drop of liquid appears 5-x metre Molar mass of H2=2 Molar mass of O2=32 Formula--- d1/t1 * t2/d2 = under root M2/ under root M1 x/t * t/ 5-x= under root 32/under root 2 x/x-5=4 x =20-4x 5x =20 x=20/5 x=4meter = distance from end of X , first drop of liquid appears Distance from end of Y , first drop of liquid appears 5-x=5-4=1(x=4) 😊😊😊😊😊😊😊
Sir. Answer is 4 m .sir you are great . your lectures are amazing . you are the best teacher in this world . who actually teach students in online portal . There are many videos of teaching on youtube . but your teaching is best no greed . perfect coaching full concept
i have attended classes from many channels but as per me "east or west , Alakh sir is the best"......physics wallah is is the best teacher of the world!!!!!!!!!!!!
Sir mere concepts weak hone ki wage se mai 3rd drop legayi..but abb apke lectures dekne ke baad i have full confidence that is baar mai neet zarror crack karungi...apki lectures ki wage se mujhe phh aur chem bahut halka feel hone laga...u r just awsm sir...👌👌
Solution to asked question At 4 meters from end of 'X' first drop of liquid appers & 1meter from the end of 'Y' side Alakh pandey I salute you for your help and supporting various students and helping them to contribute to our nation in future
Hamare yaha ke physics teacher kuch kaam ke nahi hai. Hum log roz aapki 1 video class le jate hain aur projector par laga ke padhte hain. 20 rupye ke samose hamari padhai aapke bharose.
U all r r8 guys same problem is here.... And we r able to understand each n every thing just becoz of sir n our interest towards study n sir's lectures...☺️
Today I opened youtube...typed "class 11 grahm's law" searched, Saw 2 videos in front of me...both of physics wallah..but...one is of amit sir and one is of ALAKH sir....no confusion in mind....decided to watch video of physics wallah but only of ALAKH sir..no doubt..amit sir is good but trusty: Physics wallah-ALAKH PANDEY🙌🙌
4 is the answer sir. And thank you sir for this wonderful video. If I can understand from your teaching then I believe that every student of the world can understand. Thank you sir. 🇮🇳
i am in 12 and its my dream to work with alakh sir ji in the era of education(affordable) . i want education to reach at a greater height in our whole country. thanku for your videos. lakshya batch is for chemistry also. this is my question.
Sir please reply zaroor dena aap, Sir at 22:16, Aapne oxygen ka rate agar 1.73 liya h. Aur unknown gas ka rate apne 1 liya.but sir unknown gas ka rate 1.73 kam h oxygen se to unknown gas ka rate to 0 aa jaye ga 1 kaise liya apne agar aap oxygen ka rate 2.73 lete then unknown gas ka rate 1 aata
So utne times kam h ...matlb ...suppose if I say ram is two times greater than me in age ......so if my age is X....then his age will be...... 2X HOPE U UNDERSTOOD ACTUALLY Maine bhi yahi socha tha pehele 😅 Phir badme socha to Laga ki.....ooooo....ye hona chahiye
@Nelson Toizam THERE'S NO ERROR, it is stated as "1.73 time smaller"..... that means its smaller than a multiple of 1.73.......dont get me wrong guys.....STAY SAFE STAY HEALTHY
@Nelson Toizam from otherway round you can also solve it as... let rate of diffusion of U (unknown gas) be X then, rate of diff. for O2 = 1.73x now, Ru/Ro2 = x/ 1.73 x then still it's same {cut x from num. and denom.}
Congrats sir Morning me dekha to 3.33m subscriber n night me dekha to 3.34m Just wow🥳🥳🥳🥳 U r great 😘😘😘😘😘😘😘 U will surely cross 4 million very fast👍👍👍👍👍
Sir I am a girl and using from my father accout .you are doing very well sir,🙏...jbb app gaana gane lage toh papa bole kya pdha rha h mene video dekhayi last takk and he was amazed to see......
Rate of effusion is the rate at which a gas is allowed to escape from a given cross sectional area(orifice) due to pressure difference. While diffusion is the tendency of gases to mix with each other spontaneously and form a homogeneous mixture. In case of diffusion, increasing temperature increases the rate of diffusion because it increases the kinetic energy of molecules which increases the mixing ability of the gases and thus, diffusion. In effusion the same thing happens, kinetic energy of molecules increases, which increases the speed of the molecules. But Increase in speed of the molecules decreases the probability of the molecules to escape through the given orifice/hole in a given time. Therefore, rate of effusion decreases with increase in temperature. I founded this on the net i think the formula that sir wrote was of rate of effusion not diffusion because according to grahams law rate of diffusion is directly proportional to the square root of temperature
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LAKSHYA Batch(2020-21)
Join the Batch on Physicswallah App bit.ly/2SHIPW6
Registration Open!!!!
What will you get in the Lakshya Batch?
1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey.
2)Live Classes and recorded Video Lectures (New, different from those on TH-cam)
3)PDF Notes of each class.
4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level.
5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture.
6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021)
7)In case you missed a live class, you can see its recording.
8)You can view the videos any number of times.
9)Each chapter will be discussed in detail with all concepts and numericals
10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams.
****Test Series for XI & XII****
We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year.
The test series follows very logical sequence of Basic to Advance questions.&
Evaluation of Test and Solution to all the questions at the end of the test.
11 chap 5 || States Of Matter - Gaseous State 01 | Introduction | Basic Gas Laws | IIT JEE /NEET|
th-cam.com/video/H4h4vsJ9it0/w-d-xo.html
11 chap 5 || States of Matter - Gaseous State 02 || Ideal Gas Equation IIT JEE / NEET ||
th-cam.com/video/cgaNiTvh33E/w-d-xo.html
11 chap 5 || States Of Matter - Gaseous State 03 || Dlaton's Law Of Partial Pressure IIT JEE / NEET
th-cam.com/video/mbowrScsq5I/w-d-xo.html
11 chap 5 || States of Matter - Gaseous State 04 || Grahm's Law Of Diffusion IIT JEE /NEET ||
th-cam.com/video/MS9Uk43U5eg/w-d-xo.html
11 chap 5 | States of Matter - Gaseous State 05 | Kinetic Theory Of Gases IIT JEE / NEET| KTG
th-cam.com/video/EV6BNZ_F8zo/w-d-xo.html
11 chap 5 | States of Matter - Gaseous State 06 | Types of Speeds of Gas Molecules | RMS velocity
th-cam.com/video/c9CRzUiDNMg/w-d-xo.html
11 chap 5 | Gaseous State 07 | Real Gas and Ideal Gas IIT JEE /NEET | Compressibility Factor Z ||
th-cam.com/video/MKo0d51Udxs/w-d-xo.html
11 chap 5 || Gaseous State 08 || Real Gas Equation || Vander Waal Correction || IIT JEE /NEET
th-cam.com/video/dJHs85IPs-w/w-d-xo.html
Ans 4 or thankyou sir for your support
ans is 4 m guruji
Ans is 4m
Sir app PLZZ ans to bol dijiye
You are too good sir😊
48:00 The answer will be 4m from X end.
Thank you sir for making concepts 10 times more easier than it looks! 🙏🙏
Hii are you in class 11
@@anusportsprediction yes, just incase you need something 🙂
@@fatimahtanveer2565 yaa
Same answer
ans is correct 👍
The first drop of liquid will appear at a distance of 4m from end X.
Those who are watching in 2020, hit the like button.
Alakh Sir should be awarded National Award.
Which class are you
@@kundandas7699 11th
Same answer
Same answer 👍
Same class
My base of chemistry is quite weak I need lot of time to understand a topic of chemistry
But after watching your video now I can understand concepts more easily
Hardwork always pays off..
A pen
A paper
And our Alakh sir changed the world👌🏻🙏🏻🙏🏻🙏🏻
Wahhh 👏🏻❤
Whatever taught in this chapter in this playlist is enough for neet 2023??
@@nehajha4218 no
@@nehajha4218no
@@nehajha4218no but good for understanding concpets
Government should award our Sir with national award
really
Yes sir deserves that😊👍✌
International award bro
@@xmax8476 universal bol dete aap 🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣🤣😂😂😂😂😂😂😂😂😂
Modi sarkar ma ni milega... Modi jee unacademy ko de dege pr sir jise mahan logo ko ni
Distance= 4m
Those who are watching in 2020 Corona time,hit the like button
Alakh sir one man army!!!
Great teacher😊
me
M
Yrr kitna jldi kr liya Gaseous State tumne.
Mai to ab aaya hu ispe. Vo b inorganic ko skip krke.
@@gudda_noodles sahi kaha. Me bhi 😞
Same here
When u see old lectures of alakh sir, and the advertisement came of physicswallah app or current alakh sir... Then i realised what hardwork always pays. He proves that consistency and honesty make someone successful. When his success makes a better future for a lots of students that's called real work. ❤️
you are absolutely right
What a rare name
Sukanya
Btw i m from punjab
@@xyz_124 what a cringe way to flirt
btw im from nowhere
xD
I m a girl
@@pradeep8355 in ur language its called flirting
But in my language its called compliment 😏😌🤟
coaching tuitions school kahin bhi aise nhi padhaya jaata!! hats off to your sir!!
Your name is awesome 😎😎😎
@@suryanshverma9513 thankyou
48:04 answer= d/t/5-d/t = _/32/2
d/5-d = 4
5d = 20
d = 4
so at the distance of 4m first drop of water will appear.
Same here 😊
Yes
Thanks, I wanted to check my answer and its correct
🔥
4 current answer
Answer:-
According to formula.
d/t__d/t = √M(O)2/M(H)2.
Solution:-
d/t__5-d/t = √32/2
d/5-d = √16
d/5-d = 4 (by cross multiply)
d=4(5-d)
d = 20-4d
d+4d=20
5d = 20
d = 20/5
d = 4m.
So, the first drop of liquid will appear at 4m.
Right answer
5-d not 2-d
Right answer
Right mera bhi same 🤟
Sehi ha
48:00
Last question answers 4 meter from end X....
Yess correct
Yess correct
Yess correct
The 1st drop of water molecule is appeared at 4m.
Nice class😊
1.6
@@aunsoomro2005 yeah 1.67 m
@@aunsoomro2005Nah man H2 travels faster than O therefore distance is atleast more than 2.5
It is 4m
@@missaanvi8521Nah man
H2 travels faster than O2 therefore distance will atleast be more than 2.5
It's 4 m
Sir H2 gas na 4 meter distance cover kiya aur oxygen na 1 meter distance cover kiya the students who love physics wallh hit like👇👇👇
right..!! mera bhi yhi aya
Ha mera v
4m ANS
@@kumarilakshmi7918 ok bhai shai h ya
Ok
A paper
A pen
And alakh sir
Can change the whole world 💯💥💥
ak paper or pen sai sir kai sare notes nahi likh pao gai
@@aarushijindal2839 🤣 nice 👍
And a glove too
Good👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍
@@aarushijindal2839
Q nahi ho sakta hai
Alak sir hai to possibly hai
47:32 *4m*
take a distance "d" and "5-d"
where d is distance of H2
And 5-d is for O2
Note : time is same because it's happening at same time.
now use formula :
(d/t)/(5-d/t) = √(32/2)
d/5-d = 4
d = 4m
*hope it helps*
When life gives u last chance to understand chemistry 😇🙃
u can
@@devloyan9283 That is why you are watching a video which is nearly 4 years older than other videos but has more than any of the other videos have
Exactly
Right
Yep
I was wasting my time reading book but understanding 🔔. Then spent 1 hour here now i can sleep peacefully.
Love you sir!
Lol same 😂
True bro
Are you fool? Then earlier days you had provided smartphone to the good and intelligent students to see this channel.
Debjyoti Sarkar 😹😹
I am also with u.🙋🙋🙋🙋
29:11 sir apka control agar mere hath me hota
To mae apko screen se he bahar nikal leta😍😍
😂😂😂
bhai kya bat bhai kyaa bat h
😀😀
Or phir kya karte unke saath
@@bablumehera2524 fir mae ek fanfeast arrange krta sir ke fans ke lea aur sabko unko milne ke lea bulata
East or west physics wallah is the best
Yesssssssss 👍👍
Attending your lecture is like sitting in class.... the moment u start speaking the whole atmos changes around. And the best part is each time I attend your lecture i go back with a better and improved version of mine.
Awesome bro...
You are super correct
Right u r brother
Thnks for the likes everyone but Sis here..... not bro :-)
Sir ans is 4 sec
Same bro sir lecture is like addiction from which we cannot go out
Respected Physics wallah is best for physics and chemistry .really!
What do u want to say huh
Are you telling he is good or u r saying someone is better than him ??
Unacademy Vedantu byjus.
All platforms are good but they want to earn money and make videos leanthy .
But our ALAKH PANDAY sir wnt to videos as useful for students who want to crack any entrance exam.
If you are agree then like here 👍❤️
Leanthy?
48:00
Sir,the answer is 4m from x and 1m from y where the first droplet will form . 🌺
Physics Wallah has more subscribers than unacademy.......Alakh sir is the best teacher.......one man army......💪💪💪💪
kya koyi bata sakta hai ye ncert ka topic hai mai 11th me hu
@@arushikushwaha7848 haan ncert ka hei hai.. states of matter chp
@@taqikhan9808 thanks
bhai copy kyu kar rahe ho comment
@@arushikushwaha7848 this is not part of NCERT but necessary for Jee mains and Advance👈👈👈
I am telling u all a useful tip take the value of R as 1/12. It saves a lot of time
Nice
Its useful 💯👏👏
Thank you
Your welcome
@Darshan Prajapati skrra
4 m , The first drop of liquid will appear at a distance of 4m from the X end .
Yes...I got the same
Yes at distance 4 m
Yes
48:03 √32/√2=x/t/5-x/t
t is cancelled
4=x/5-x
20-4x=x
x=4m(ans)
Answer: 4m. The first drops of liquid appear
Hope ur feeling good sir. Saw ur interview in youtube heard ur grandfather expired. May his soul rest in peace. 💐💐
Rip
❤️
RIP
Rip
@SUCK GAMING rip matlab rest in peice hota h .
Bhai yahan bhi khol Galli sunna chata h.
Brilliantly explained. The biggest USP of yours is the down to earth manner of teaching. Keep up the good work Sir.
48:3 Question-
Let the distance from end X, first drop of liquid appears x metre
And distance from end of Y, first drop of liquid appears 5-x metre
Molar mass of H2=2
Molar mass of O2=32
Formula--- d1/t1 * t2/d2 = under root M2/ under root M1
x/t * t/ 5-x= under root 32/under root 2
x/x-5=4
x =20-4x
5x =20
x=20/5
x=4meter = distance from end of X , first drop of liquid appears
Distance from end of Y , first drop of liquid appears 5-x=5-4=1(x=4)
😊😊😊😊😊😊😊
@@pallavisingh4910 yes me
Attending your lecture are like diving deep into ocean full of knowledge where we both enjoy and learn
Yah
Absolutely right
Ya my coaching is full of teachers who have just memorised the lines of NCERT and Pradeep
Thank you sir you explain best
Sir. Answer is 4 m .sir you are great . your lectures are amazing . you are the best teacher in this world . who actually teach students in online portal . There are many videos of teaching on youtube . but your teaching is best no greed . perfect coaching full concept
Sir super infinity (second part of super 30) should be made on you
How about super million
or a better name would be "PhysicsWallah-The heartbeat of millions"
@@aritrabose8050 Sahi bola
Ek dum kamal ke lecture hain sir ke
A lot of respect increased towards sir
I don't know Hindi even i watch this channel only
Salute you sir
U even don't know english
@@shshankdhaka920 kaise
@@shshankdhaka920 I agree with you
@@shshankdhaka920 🤣
@@venomvirusgamer8603 see location of "even"
i have attended classes from many channels but as per me "east or west , Alakh sir is the best"......physics wallah is is the best teacher of the world!!!!!!!!!!!!
Hydrogen gas distance = 4m
Oxygen gas distance= 1m
😊
Me 4m same ans
Me too
Same here
Me too the same answer
oh! my answer is correct. happy for this
Sir mere concepts weak hone ki wage se mai 3rd drop legayi..but abb apke lectures dekne ke baad i have full confidence that is baar mai neet zarror crack karungi...apki lectures ki wage se mujhe phh aur chem bahut halka feel hone laga...u r just awsm sir...👌👌
updates?
Sir happy teacher's day , 2019. Lot's of love . You are the best best teacher
48:05 ans is 4 m 🔥🙏 thanks for lovely explaination ❤️
Mere 1m aa rha hai answer
@@thestxaviersschool2813 wo from y hai
Mera 3.3
@@Fun_Time3213 what
@@Fun_Time3213 itna easy question to hai😬😬😬tabhi galat aa rha hai tumhara 🤦🤦
2 years ago he had a great feel of chemistry and now greatest feel of Physics......
Now its four years 🙂
r1/r2 = D1/T1 ÷ D2/T2 = √m2/ m1
= D/t ÷ 5-D = √16
= D/5-D = 4
= 5d= 20
= D= 4
Hope you got it ❤️
Ye d/5-d 5d kese hoa
Bhai iit hua tujhse?
Sir ur great...ur providing us free quality education..thnx sir ..may gob bless you
R8 brother ...
,😂😂😂😂😂
Fucccccker nothing ever is free....see all this adds in video😂😉😎😂😂😂😂😂
R8😄🤔🙋
@@nandinipathak7602 ☺
One teacher one student one pen can change the world - Dr APJ Abdul Kalam and real life example is Alakh Pandey sir
Pakistani education activities Malala ka statement hai bhai ye
@@mangeshghadmode2864 Me bhi yahi bolne wala tha 😂
Yea this statement is of Malala yusuf zai
@@mangeshghadmode2864 🤣🤣I was like kalam ne kab bola se
Ab Albert ne bola hai naam mein kya rakha hai toh maan lete hai
Solution to asked question
At 4 meters from end of 'X' first drop of liquid appers &
1meter from the end of 'Y' side
Alakh pandey I salute you for your help and supporting various students and helping them to contribute to our nation in future
Ha bhai 3.98m aa raha hai.
@@wholechrist5631 nahi bhai poora 4m aa RHA hai
How????
"Y" se 1m answer kaise hota hai... O2 ka.... Plz xplain me
@@sania4132 5 mein se 4 gaya toh 1 bacha na
His videos are still very important in 2022 ❤️❤️❤️
In 2032 also
Hamare yaha ke physics teacher kuch kaam ke nahi hai. Hum log roz aapki 1 video class le jate hain aur projector par laga ke padhte hain. 20 rupye ke samose hamari padhai aapke bharose.
Bhai sir chemistry dhasu padate ha
Mere school ka chemistry chaupat hai. Sab kuch galat parhate hai mere sir.pata nahi alakh sir nahi hote to main kya karta
U all r r8 guys same problem is here.... And we r able to understand each n every thing just becoz of sir n our interest towards study n sir's lectures...☺️
saransh sharma . Shabash bahi
Wow amazing...
Nice explanation... better than any Indian teacher, one of the very nice teacher of Physics & Chemistry...
47:56 answer to the question is 4m is the distance at
which first water droplet is formed
Still 4 years but it is very helpful for us thanks you sir 🙏🙏
I request everyone to like the video plz..
Alakh sir is doing great work for us,..
Loveliest teacher of students awards goes to alak sir physics walllaaahhhh 👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏
O bhai aap 'h' bhul gaye hai. Sir ke naam Alakh Pandey hai not alak😁😁😁
Today
I opened youtube...typed "class 11 grahm's law" searched,
Saw 2 videos in front of me...both of physics wallah..but...one is of amit sir and one is of ALAKH sir....no confusion in mind....decided to watch video of physics wallah but only of ALAKH sir..no doubt..amit sir is good but trusty: Physics wallah-ALAKH PANDEY🙌🙌
This topic is not in NCERT?
@@ektapathak9350 yes but questions are asked from this in Neet and Jee..
Sir you are the god of physics and chemistry
48:04
Answer to question is 4m pe meet krenge and 4m measured from end X😇👍
48:03 answer of this question distance is 4 metre...
4 is the answer sir.
And thank you sir for this wonderful video.
If I can understand from your teaching then I believe that every student of the world can understand.
Thank you sir.
🇮🇳
I got the same answer
Haa bhai sahi answer hai mera bhi yahi aaya
After 5 yrs ❤️continuing the journey of physics with physicwala 😄
4 m is the answer of distance by time question😊👍
Mine is 4metres too
Coorrect💯
@@shobhajoshi4569 yuppp 😁
Yups diya absolutely correct 😍
@@abhijeetattri3483 please upvote my comment on the recent video uploaded by sir i want reply
U r class are super. I was struggling a lot to solve problem... Now I am able to solve problem
i am in 12 and its my dream to work with alakh sir ji in the era of education(affordable) . i want education to reach at a greater height in our whole country.
thanku for your videos.
lakshya batch is for chemistry also. this is my question.
Great sir and watching your lectures from Pakistan🇵🇰❤️
Sir please reply zaroor dena aap,
Sir at 22:16,
Aapne oxygen ka rate agar 1.73 liya h. Aur unknown gas ka rate apne 1 liya.but sir unknown gas ka rate 1.73 kam h oxygen se to unknown gas ka rate to 0 aa jaye ga 1 kaise liya apne
agar aap oxygen ka rate 2.73 lete then unknown gas ka rate 1 aata
So utne times kam h ...matlb ...suppose if I say ram is two times greater than me in age ......so if my age is X....then his age will be...... 2X
HOPE U UNDERSTOOD
ACTUALLY Maine bhi yahi socha tha pehele 😅
Phir badme socha to Laga ki.....ooooo....ye hona chahiye
@Nelson Toizam THERE'S NO ERROR, it is stated as "1.73 time smaller"..... that means its smaller than a multiple of 1.73.......dont get me wrong guys.....STAY SAFE STAY HEALTHY
@Nelson Toizam from otherway round you can also solve it as...
let rate of diffusion of U (unknown gas) be X
then,
rate of diff. for O2 = 1.73x
now,
Ru/Ro2 = x/ 1.73 x then still it's same {cut x from num. and denom.}
I m mother of 11th class student,I find ur videos awesome.i teach him after watching ur videos
48:05 - The answer is 4 m.
Absolutely a great teacher of physics mind-blowing 🙏🙏🙏 thank u sir
Congrats sir
Morning me dekha to 3.33m subscriber n night me dekha to 3.34m
Just wow🥳🥳🥳🥳
U r great 😘😘😘😘😘😘😘
U will surely cross 4 million very fast👍👍👍👍👍
Crossed ❤️❤️❤️
@@gamingwallah4325 yes alakh Pandey sir is best
Crossed ❤️
Sir deserve this
Sir I am a girl and using from my father accout .you are doing very well sir,🙏...jbb app gaana gane lage toh papa bole kya pdha rha h mene video dekhayi last takk and he was amazed to see......
Same here with me
Mee too
THE ANS IS 4M FROM END X SIR... THANKYOU SO MUCH FOR BEING OUR TEACHER N SPECIALLY A GR8 INSPIRATION ....☺☺☺
48:28 ans is 4m thank u sir paay lagu🙏🏻
44:31 sir ka reaction🤣🤣🤣🤣👌🤣👌👌👌👌👌🤣
th-cam.com/video/aXkw2Xrfbr4/w-d-xo.html👍
48:30 sec ans is 4m.
From x end the first drop of liquid appears in 4m distance.
sir i have no words how to express my gratitude towards you but u being a part of my study life is really something i'm thankful for
48:40 answer :- 4m
Sir the ans of the question that you
have asked to comment is 4 unis from X.
48:10 pe question ka answer 4 hai.
And sir, you are great 👍
You made my more intrest toward chemistry☺️👌
answer galat hai
@@amitchawla563 ha shi answer 4.70m from x
h2 and o2 reacts to form 1st drop of liquid 4m away from X
If you are studying by this great person you love that subject ...👍🏻
sir u r the best
if i cant understand from coaching classes i see ur vedios and my all doubts get cleared
thank you sir
Teaching style.....alag level ha
Sir ka.....best physics teacher...
The first drop of liquid will appear at d=4m from end X 🔥🔥🔥
48:20 The first drop of liquid willa appear at 4m from the end x and 1m from the end y.
Answer for the question asked by Alakh sir :-
ANS :- At 4m from the end X , first drop of liquid will appear..
22:15 Aap sach mein genius ho sir
Perfume waala example best tha
K.p. Singh 😂😂
At 35:01 the value of x is (×= 192 g)
Diffusion increases in higher temperature so rate of diffusion should be directly proportional to the temperature .....
Rate of effusion is the rate at which a gas is allowed to escape from a given cross sectional area(orifice) due to pressure difference.
While diffusion is the tendency of gases to mix with each other spontaneously and form a homogeneous mixture.
In case of diffusion, increasing temperature increases the rate of diffusion because it increases the kinetic energy of molecules which increases the mixing ability of the gases and thus, diffusion.
In effusion the same thing happens, kinetic energy of molecules increases, which increases the speed of the molecules. But Increase in speed of the molecules decreases the probability of the molecules to escape through the given orifice/hole in a given time.
Therefore, rate of effusion decreases with increase in temperature.
I founded this on the net
i think the formula that sir wrote was of rate of effusion not diffusion because according to grahams law rate of diffusion is directly proportional to the square root of temperature
48:00 Answer: 4m from x end.
Bro galat h
48:02 Ans will be : H2 will meet O2 at a distance of 4m from the end X 😀🌟
Right sir
I don't know what to say you're such a great sir
Homework Question Answer -
The First Drop of Liquid appears at a Distance of '4m' from the end X.
Thank You very much Sir.
Thanks for this wonderful teaching.and answer is 4m.
sir u made my 11th class amazing
thanku sir from heart
Sir our support will make u reach 1 million one day may god bless u sir ji
What a way of his explanation..just mind-blowing sir👍⭐
Pace Batch is already in the mind of alakh sir 29:14
The answer of the 8th question is 4metre from X .
When I will become doctor then I will definitely meet you,and do something for you.
Don't comment it, just do it when the time comes.
Lol wt will u do ?
Just curious
😂😂
@@bb-gb7jv nothing
@@dvsingh9232 thanku
why do you need gas laws for becoming doctor
Sir, my answer is 4 m. We will observe the first drop of water at a distance of 4m from X.
mee too
48:05 ans) 4m from X end