Good evening sir 36:46 Q1 11.2g Q2 6.4g Q3 No. of atoms=GM/MM(N0) = 0.6/12*6.022*10²³=3.011*10²² 55:36 No. of moles =8.8/44=0.2moles No. of molecules=0.2*6.022*10²³=1.2044*10²³ CO2 molecules No. of oxygen atoms present in this=2*1.2044*10²³=2.4088*10²³ oxygen atoms Thnku so much sir 🙏🏻 Understood everything
I'm just so shocked that how can a teacher be like awesome. No words for you sir. U r the best teacher of science in India. Hats off respect to you sir🙂 . Keep it up, continue this. I'm sure one day you will great what you really deserve. Thank you sir 🙂
Tq tq tq tq so much sir.... Can't tell how much I used to fear from this chapter just before 1 h... My This weekend plan was really really successful just because of you... For because of u now I feel confident about this chapter tq so much sir
9:29 kya bolte munna Kya bolte munni 🤣🤣🤣 My parents also laughed and said "nice teacher. You should study from him only."🤣🤣😁🤭 I first time said something good about my teacher.🤣🤣🤣 You are the best teacher sirrrrr jiiiii.😄🥰 Edit: Thanks for 40+ likes🙃😅
00:00 Start 0:57 Avogadro number 8:50 Atomic mass 12:54 Molecular Mass 16:00 Molar Mass 26:17 textbook explanation 29:46 Question 1 31:54 Question 2 33:14 other questions 36:47 Formulae on the concept and questions 46:21 Textbook Exercise 52:02 Extra questions 55:14 Homework Questions 56:01 Outro
No of mole =0.2and no of molecules=1.2044 × 10 *23and no of oxygen=2.4088×10*23 thanku sir for teaching and solve all the questions related mole concept
One of the best teacher in my education and those who like edumantra dil se like thoko sir ko lagna chaiyhye me jo padha raha hu vo bachho ko samajh aa raha he salam he sir 🙏🙏
I was stressing so much over this mole topic and now I am shocked.. it was so easy and I wasted so much energy on it.. thankyou so much sir.. Ur a gr8 tchr
as we know, No. oo Moles = given mass / molar mass so no of moles is 0.2 no. of molecules will be = 0.2*6.022*10^23 answer for no of molecules : 1.2044*10^23 as we know two oxygen atoms there are so multiplying no of moles *2 0.2*2=0.4 no of atom = 0.4*6.022*10^23 that is 2.4088*10^23 sir aap ne bht accha samjhaya jo concept mein class 9 ke end take nhi samjh paya aaj minton mein samjh gya.
Video Timeline: 00:00 Start 0:57 Avogadro number 8:50 Atomic mass 12:54 Molecular Mass 16:00 Molar Mass 26:17 textbook explanation 29:46 Question 1 31:54 Question 2 33:14 other questions 36:47 Formulae on the concept and questions 46:21 Textbook Exercise 52:02 Extra questions 55:14 Homework Questions 56:01 Outro
Sir the way you explain is very clear. As sometimes during class we cannot understand and we think that we will ask afterwards that doubt . But, we won't and because of that small doubt we don't understand whole concept. U explain even those small doubts too. Which helps us a lot. U r the best teacher .☺
I think you are failure in your class because students who have to study asks the doubts And I also ask my every doubt But sanjiv sir is best so I see the videos of sanjiv sir
Sir you told about the magic in mole concept and when i understood the magic i realised you are a magician of one kind. Thanku sir. Pls keep your style.
55:38, Q is= Calculate number of moles and molecules present in 8.8g of carbon dioxide, also calculate the number of oxygen atoms present in this? 1st equation, number of moles= given mass/ molar mass. So, 8.8g/44g = 2.2 Ans=2.2 moles 2 equation, Number of molecules= given mass/ molar mass × Avagadro number. So, 8.8g/44g× 6.022×10²³ =2.2×6.022× 10²³ = 13.2484×10²³ And 3 equation, Calculate all number of oxygen atoms present in this, So, = 2× 13.2484×10²³ ( I multiply it by 2 because there are 2 atoms present in ) = 26.4968×10²³ ANSWER...... And thanks sir for this precious knowledge 😊
Sir tomorrow is my offline exam and I have lot of doubt in mole concept and just because of your amazing explanation I understand it easily..thanku sir...🙏🙏
Sir, I've got 50/50 in my science test , credit goes to u🙃, sir ur best teacher and Ur teaching style is amazing, 💕 keep supporting in our studies by making our study easier 🤗
OMG! Thank you so so so much sir! This explanation was the best. I saw so many other explanations, but just couldn't understand this concept. But now it so clear.👌🙏🙏
What a way of teaching. Education will not be a burden for students. When every teacher's thinking will be like you. Highly inspired. Your method of teaching by laughing and saying jokes touches a student's heart and reduce the stress of that student during exams. Thank you sir, never give up. Keep going, you are doing a very good work, god is always with you.
26:46 yes sir ,, I understood this .. Thanks a lot sir 🙏🙏 Your way of teaching is best for me. I am finding the best channel for my education since 2 months butt Today, I finded .... I'll always study from your channel ... Thank you so much...😊
26:47 Yes sir sab samj aa gya sir , aap our bkp dono he kamal ke teachers hai , backbencher ko toper banane ka dam rakhte hai aap dono ! Mere mujhe itna acche se samj nai aaya jitna yaha aaya!! Thank you very much sir☺️
Sir I really don't know if you see my comment or not but trust me I'm Preparing for competitive exams and your videos really turned the game for me. Thanks a ton sir🦇❤
16:30 Soooooo helpful Last day before exam and opened I opened my book for the first time Understood nothing from the textbook Sir explained it sooo well that I couldn't believe I got it and cried tears of happiness!!:) 😍
How can a teacher be this good????
not teacher legend
Exactly
@@saifamer1773 LEGENDS ARE SOMETHING WHICH ARE MOST PROBABLY NOT REAL LIKE TALES BUT SIR IS REAL
@@detectivejojo7025you are right
Why ? Teacher can't be good?
26:26 understood the overall concept which sir tried to explain 🙏
samajh mein aa gaya sir
😡jhut mat bolh
Sir I am your biggest fan ❤️❤️😍😍
Mole concept understanding from
Self-2%
School-8%
Edumantra-90%
Good bro
Correct yr 😂😀
Self 99%
School - 1%
Yes
Sir you EXPLAINATION is amazing. My Doubts are clear . Thank you sir
👍👍👍
Outstanding, Speechless, Mind-blowing!!!!!
Bhai tumne crazy tips ki video dekh kar ye logo banaya hai na😂😂......maine bhi uski videos dekh ke bohot logo banaye hai😂😂😂
ABD❤❤❤❤
Tham jaa bhai....
Fabulous ,, awesome , that's Gajab 😂👍👍
DJ DEKH KAR AA RAHE HO ?
Good evening sir
36:46
Q1 11.2g
Q2 6.4g
Q3 No. of atoms=GM/MM(N0) = 0.6/12*6.022*10²³=3.011*10²²
55:36
No. of moles =8.8/44=0.2moles
No. of
molecules=0.2*6.022*10²³=1.2044*10²³ CO2 molecules
No. of oxygen atoms present in this=2*1.2044*10²³=2.4088*10²³ oxygen atoms
Thnku so much sir 🙏🏻
Understood everything
How you got the answer of ques 3
Pls explain
@@suiii958 7.2g one?
@@v3nshika yes
@@suiii958
I made some mistake... Dn the correction
@@v3nshika okay baby, no problem I suggest you how to solve the problem 😊
I like how he himself questions what he says...
He knows every question a student is most bound to ask after watching his video.
sir you are great . may god give you 1000 million subscribers . best teacher
1000 million mai kitne zero hote ha bol na phle😂
@@effectioneffector4162 you are right 😂😂
Sahi kaha vahi
Ans of 1st 3 questions
1)11.2gm
2)6.4gm
3) 3.011*10²²
thoda zaada nahi hogaya???
36:40 que. calculate the mass of 0.4 moles of oxygen atom = 6.4g
que. calculate the number of atoms present in 0.6g of carbon atom=3.011*10^22
I'm just so shocked that how can a teacher be like awesome. No words for you sir. U r the best teacher of science in India. Hats off respect to you sir🙂 . Keep it up, continue this. I'm sure one day you will great what you really deserve.
Thank you sir 🙂
Tq tq tq tq so much sir.... Can't tell how much I used to fear from this chapter just before 1 h... My This weekend plan was really really successful just because of you... For because of u now I feel confident about this chapter tq so much sir
9:29 kya bolte munna
Kya bolte munni 🤣🤣🤣
My parents also laughed and said "nice teacher. You should study from him only."🤣🤣😁🤭
I first time said something good about my teacher.🤣🤣🤣 You are the best teacher sirrrrr jiiiii.😄🥰
Edit: Thanks for 40+ likes🙃😅
Sahi hai
😂😂👍🏻👍🏻
@@anshvashist5739 😅😅
@SHOOTER GAMING 😌
Calculate the mass of 0.8g of Nitrogen atom = 1mole = 14g of Nitrogen
0.8mole = x g
1/0.8 = 14/x
= 14 X 0.8
= 11.2 g of Nitrogen atom
❤️❤️❤️❤️❤️
Wah
00:00 Start
0:57 Avogadro number
8:50 Atomic mass
12:54 Molecular Mass
16:00 Molar Mass
26:17 textbook explanation
29:46 Question 1
31:54 Question 2
33:14 other questions
36:47 Formulae on the concept and questions
46:21 Textbook Exercise
52:02 Extra questions
55:14 Homework Questions
56:01 Outro
Your teaching and T shirt are all rounder💯💯
33: 50
1-11.2gm
2-6.4gm
3-.3011×10²³
U r right 👍👍👍👍👍👍
Yes u are really right but muje 3rd samaj nahi nahi aaya
Can anyone please explain how the last answer came? I’m a lil’ confused
Ans. 3rd is 3011×10ki power 19
@@harshalmudgal9558 ha aur agar 3.011 lenge to power 22 ayegi
55:45 ans is
O.2 moles of CO²
12.044×10²² molecules of CO²
24.088×10²² molecules of oxygen
Am I right sir ??
Plss ans this sir.... Btw ur the best sir
U are correct bro
You are correct 👍👍👍
Thank u 🤗
No bro molecular mass is 1.2046 x1023
@@ironman-gt8fk both answers are correct
No of mole =0.2and no of molecules=1.2044 × 10 *23and no of oxygen=2.4088×10*23 thanku sir for teaching and solve all the questions related mole concept
Thanks 😎😎😎😊😎😎😎
Mera Bhi Sahi Hai 🙂
Lol me matching my answer with urs🤡
One of the best teacher in my education and those who like edumantra dil se like thoko sir ko lagna chaiyhye me jo padha raha hu vo bachho ko samajh aa raha he salam he sir 🙏🙏
No. Of moles 0.2
No. Of molecules of co2 is. 1.2044*10²³
no of oxygen atoms is. 2.4088*10²³
My answer is also same
My ans is also same great
Same answer... I just came here to confirm 😂
Well done bro
HIS T - SHIRT ALWAYS HAVE A OUTSTANDING MORAL...!!😍
Really !
@@kirtisakhuja5666 ya😂😂😂😂😂😂 bro or sis😂😂😂😂
@@bikrampradhan618 simp
@@t-series2638 omg mind your language you ill manered peanut
Really bro
I AM SPEECHLESS FOR THE EXTREME NEXT LEVEL EDUCATION THIS MAN IS PROVIDING 😭😭..!!
I was so devastated with the mole concept .. but HATS OFF 2 HIM 🤌🪄
55:26 answer no. of moles = 0.2g, no. of molecules = 12.044*10^22 , oxygen molecules = 24.088*10^22
sir it it correct plz tell if you see
yes,aniruddh you are right
No of molecules=No. Of moles × arogardo no.=0.2×6.022×10²²=1.2044×10²²
But how oxygen atom became that plz help~
I know that it has been multiplyed by 2 but why??
@Varsha Bhargava [UHA] thanx bro XD
@@johnking8689 u gotta make it correct bro
Its 0.2 x 6.022 x 10²³ = 12.044 x 10 ²²
26:32 Aagya sir smjh me
Outstanding sir I have no doubts, and tomorrow is my science pre - board
Everything is clear sir
I am not able to understand the mole concept but now It has cleared everything🤗
55:20 number of moles=0.2moles, number of molecules=12.044× 10raise to power22
26:40 sir everything is clear like a ash. (I am not saying other bcue I love chemistry and according to chemistry nothing is more clear than ash.)
Itni acchi English mat bolo kariye uper se Nikal jati hai
@@middleclassgamer7567 haha 😅🤣🤣🤣
When you are in 11th but still dont know about Mole concept 🙂
Dropper bro 😐
Hum bhi h ..
Mai bhi
Kya mai aapka help kr skta hu
Lol thats exactly why i am here
I'm speechless, I can't explain about Ur teaching methods.sir U are the great 🙌🙌🙌
I was stressing so much over this mole topic and now I am shocked.. it was so easy and I wasted so much energy on it.. thankyou so much sir..
Ur a gr8 tchr
Ha great ki spelling to pata nahi hai
Aap jaise log hi science ke paper me maths ke question likh kar aate hai
Haa
Sanjiv sir soo best teacher , 😀
And your English teacher is stressed about your English..😂😂
waste some energy on me to bay
26:30 good teaching really got the concept
26:33
I understood.😊
Itna baar koun likhega " I understood" ,, sidhe like karo yaaro... Jisse sir ko pata chl jaaye.
@ULTRA GAMING 《RAJ》 like toh kr de bhai phir
as we know,
No. oo Moles = given mass / molar mass
so no of moles is 0.2
no. of molecules will be = 0.2*6.022*10^23
answer for no of molecules : 1.2044*10^23
as we know two oxygen atoms there are so multiplying no of moles *2
0.2*2=0.4
no of atom = 0.4*6.022*10^23
that is 2.4088*10^23
sir aap ne bht accha samjhaya jo concept mein class 9 ke end take nhi samjh paya aaj minton mein samjh gya.
A big thanks to Sanjiv Sir and his team
H.W Question answer
No. of moles = 0.2 moles
No. of molecules= 12.044 * 10^22
No. of O atoms= 24.088 * 10^22
Ki
Great
How
Sir answer of the question asked by you at the end (56:02) is
(i). 4.4 moles
(ii). 4.4 × 6.022 × 10^23...
You explained awesome sir.. 👍
26:20 aara sir apna aap ko badlne ki koi jarurat nahin hai apne aapko Jaise Ho vaise badhiya Ho😘😆👍👍👍
@Ritika jain thanks
Video Timeline:
00:00 Start
0:57 Avogadro number
8:50 Atomic mass
12:54 Molecular Mass
16:00 Molar Mass
26:17 textbook explanation
29:46 Question 1
31:54 Question 2
33:14 other questions
36:47 Formulae on the concept and questions
46:21 Textbook Exercise
52:02 Extra questions
55:14 Homework Questions
56:01 Outro
Sir the way you explain is very clear. As sometimes during class we cannot understand and we think that we will ask afterwards that doubt . But, we won't and because of that small doubt we don't understand whole concept. U explain even those small doubts too. Which helps us a lot.
U r the best teacher .☺
I think you are failure in your class because students who have to study asks the doubts
And I also ask my every doubt
But sanjiv sir is best so I see the videos of sanjiv sir
Very good explanation Sir
@@usharawat2468 some students are shy and cannot Ash doubts and the real failure is you who are making fun of others
@@gwsquad3457 abe to failure hai jo yaha aake reply padh raha
Hai
Sir you told about the magic in mole concept and when i understood the magic i realised you are a magician of one kind. Thanku sir. Pls keep your style.
Awesome sir , i understood everything best teacher. Thanks a lot sir i am doubtless🙏🙏
Yes sir I understood. Before watching this video i was in doubt now Im able to understand everything
Sir you are one of the best teachers I had ever seen in my life😊🤗😘😘
Speechless! Understood 1st half
What about other half..?
20:07 waah! Sir kya baat batai.👏👏
Clearly understood😃😃
Sir ko patalooo 😂 saadi karlrna
Numerical : Calculate the mass in milligrams of (I) 10*21 atoms of U-238 (ii) 10*20 molecules of oxygen gas.
33:50 answer 11.2
same bro
Sir answer of H.W. question is
12.044*10^22 molecules of CO2
0.2 moles of CO2 molecules
24.088*10^22 atoms of OXYGEN
0:00-0:59 intro
1:00-8:49 Avogadro number
8:50-12:55 atomic mass
12:55-16:00 molec. Mass
16:01-26:15 Molar mass
26:18-29:45 book question
And then some questions 😌😌☺
Sir I understood everything thank you very much sir ❤️❤️
26:28 everything understood crystel clear sir
we all have watched mind your studies
19:50 wallahh...!!!😂😂
55:38, Q is= Calculate number of moles and molecules present in 8.8g of carbon dioxide, also calculate the number of oxygen atoms present in this?
1st equation,
number of moles= given mass/ molar mass.
So, 8.8g/44g = 2.2
Ans=2.2 moles
2 equation,
Number of molecules= given mass/ molar mass × Avagadro number.
So, 8.8g/44g× 6.022×10²³
=2.2×6.022× 10²³
= 13.2484×10²³
And 3 equation,
Calculate all number of oxygen atoms present in this,
So,
= 2× 13.2484×10²³ ( I multiply it by 2 because there are 2 atoms present in )
= 26.4968×10²³
ANSWER......
And thanks sir for this precious knowledge 😊
36:28 sir answer 3.011* 10^22
It's worng
Answer is 3011 × 10^19
Tommorow is my exam and this video helped me a lot.Thank u very much!!
I have also a exam of science by tomorrow
One of the easiest video of mole concept which i found on utube ...😊♥️😘
Realy superb teaching😍..appreciate it👏
Yaha v youtube me you short hai,,,, pata nahi aur kitna short cut hogi ye duniya😶😑😕
Best teacher in the world 🌍🌍🌍💪🏻💪🏻💪🏻 of edumantra
Sir smjh aagya but revision karte rahna hoga warna puri mehnat pr paani phir jaega..thnk u sir aap pahle insaan ho jissne meko ache se smjha diya😍😍😍😍
Sir tomorrow is my offline exam and I have lot of doubt in mole concept and just because of your amazing explanation I understand it easily..thanku sir...🙏🙏
I am watching on examday morning 4 am😅😂😂😂
this is lecture - legend
@@Disappointment_official ＳＡＨＩ
@@adarshanand3989 i know
@@adarshanand3989 there is one more legend then me
Sir, I've got 50/50 in my science test , credit goes to u🙃, sir ur best teacher and Ur teaching style is amazing, 💕 keep supporting in our studies by making our study easier 🤗
Online me mere bhi aye the
@Shakti Techno SAVAGE OP RESPECT +
Mai bhi dakata hu sir ke video muzai to 25/2 and half hi milai
Also got 80/80 and 100/100 on my test
@@omkarmohite9955 kyunki tu khud se nhi padhta h
OMG! Thank you so so so much sir! This explanation was the best. I saw so many other explanations, but just couldn't understand this concept. But now it so clear.👌🙏🙏
Good teacher quality looks on his t shirt ..... motivation 💪
26:28 sb smjh aagya sir yha tk
Sir u r a great teacher the teaching way of urs is superb
Sir you are better than my school teacher . your are amazing teacher thank u 😊
What a way of teaching. Education will not be a burden for students. When every teacher's thinking will be like you. Highly inspired. Your method of teaching by laughing and saying jokes touches a student's heart and reduce the stress of that student during exams. Thank you sir, never give up. Keep going, you are doing a very good work, god is always with you.
Oversmart kahi ke tujhe yha bhasan deneki jaroorat nhi
Oversmart apne aap ko jyada talented samajhti he kya
@@crisworld8160 your exam are coming KYA??¿
@@shubhangishubhangi5654 no siso after vacation
@@crisworld8160 mtlb final exam???
Answer of the question to calculate mass of 0.8 moles of nitrogen atom = 1/0.8 =14/x
= x = 14 × 0.8
= 11.2
we know we also have mind
Bhai bhai 😂
@@Disappointment_official tab comment mai kyu aaya khud krleta
finally sir you make me understand this so called mole concept .......you are great sir ......hats off to you🙏🙏😍😍
Are u in kv school ???
@@chandrashekarrao2906 yes
Wheare do you leave
This is the best platform of education in free of cost i recommend to all of you ❤❤❤❤❤❤❤
Sir you explained in such a great manner that i will never forget this concept
It means bro that the Avagadro Number is equal to 1 gram??? Isn't it
😂🤣 yee budy
@@AdilBains 😅😅
Bro are you active on yt, i want to ask something
Sir I am from Afghanistan , I really appreciate with your video ! Thank you sir I am doubtless 😘😘😘😘
Thanks bhai, Love to Afghanistan and You from India
Tumhare number dedo me afganistan ke bare me kuch Janna chata hu cricket ke bare me bhi
🙄🙄🙄🙄 jhutha
@@Mansi7705 sahi pakde hain. Op bolte.
@ek inssan haan yaar pata nhi game me bhi aate hain aur kehte hain me tumhare india se nhi hu phir bhi tumhari bhasha aati hai.
Sir u are a great teacher I can't explain in word ....n I will pray to God that u always success in your life ❤️thanks alot from your student💝
Shi hai
Right bhai i also pray to God 😇🙏👼
Sir I love your teaching classes.....😀😀😀😀
amazing session !
perfect for pre exam revisions
thank you sir!
Sir Answer of Your question is -
3011*10^19 = x
*55:7* No. Of moles=0.2g
No. Of atoms in O2=1.2044×10^23
Ryt
Sir I understood of you teaching style . thanks sir
26:46 yes sir ,, I understood this ..
Thanks a lot sir 🙏🙏
Your way of teaching is best for me.
I am finding the best channel for my education since 2 months butt Today, I finded .... I'll always study from your channel ... Thank you so much...😊
maths- mkrgreenboard
hindi and english- bkp
sst- magnet brain
science- edumantra
best references
101% true
Could u pls tell me reference books for 9th
26:48 HAA SIR, BOHT ACCHESE SAMJHA 🙌🔥
Yes
Sir aap ne pura concept clear kar diya. Aur aap bahot easy way me samjhate ho. Thankyou sir.
26:47
Yes sir sab samj aa gya sir , aap our bkp dono he kamal ke teachers hai , backbencher ko toper banane ka dam rakhte hai aap dono !
Mere mujhe itna acche se samj nai aaya jitna yaha aaya!!
Thank you very much sir☺️
Yes bro 😎........
BKP+SANJIV SIR= MAKES ANY OF US TOPPER
Sanjiv sir j cbse class vedios ❤️❤️ best
Sir plz cover the whole ncert book
And your explanation is awesome
Yes
Before this I am struggling with this concept now my all doubt get cleared ☺️
Sir You teach very well . Like Crystal Clear
👍🏻👍🏻👍🏻👍🏻❤️❤️❤️❤️
ok
Outstanding performance sir😍😍😘
i loved you explaination sir... :)
35:46 answer is 3.011*10^23
3.011*10^22 Hoga na
Sir I really don't know if you see my comment or not but trust me I'm Preparing for competitive exams and your videos really turned the game for me.
Thanks a ton sir🦇❤
These are not game these are studies which make my , your and everyone life
@@Disappointment_official apna jada gyan mat bat
16:30
Soooooo helpful
Last day before exam and opened I opened my book for the first time
Understood nothing from the textbook
Sir explained it sooo well that I couldn't believe I got it and cried tears of happiness!!:)
😍
Sir your teaching methods are best....
34:36 Arre divide karo dhabha dhabh get the answer....
kfufuf
Finally I got to learn about mole concept
Thank u sir from bottom of my ❤❤
I understand everything but unfortunately I found this video after my test .but fortunately before my exam 😊😊😊😊😊
That's good
Me too
Sir very nice 🎉🎉🎉🎉🎉🎉 you are more good teacher means🎉🎉🎉 excellent , outstanding sir🎉
Sir everything is the best 1 thing that decrease our concentration is too many ads..
HE ALSO WANTS MONEY BRO/SIS ...... THIS IS LIKE HIS PROFESSION
SIR KO SIRAF YT ADS SE PAISE DETA HAI
Video download karlo then data off kar ke video dekho
yes sir please reduce adds please sir
Sir is giving the education free it means a lot to us and if we can pay him by ads it will be benefited to sir also
@@GRANTHBHARDWAJ31 ur absolutely right
Homework answer :
1) 0.2 moles
2) 1.2004 × 10^23
3) 2.4088 × 10^23
I think the second should be 1.2044*10^22
@@AnirudhPathakuroll bro , it should be 1.2044*10^23 or 12.044*10^22
@@AnirudhPathakuroll
No
the answer is 1.2044 * 10^22
@@AnirudhPathakuroll no you are wrong
The concept was clear sir. Thank you!!
Answer: Number of molecules = 1.2044 × 10^23
Number of O-atoms = 2.4088 × 10^23
34:46 that "are kar lenge yaar" was really motivating 😄
sir... U taught easiest method... I dont have to revise it again..! U made me learn this..thank u sir..! U r such an awesome teacher😊
Yss