Solving Exponential Equation Having Variable Exponents | Challenging Exponential Equation.

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  • เผยแพร่เมื่อ 8 พ.ย. 2024

ความคิดเห็น • 21

  • @therichcircle.8819
    @therichcircle.8819 ปีที่แล้ว +1

    Great as always. Am beginning to learn this Lambert function from onlinemathstv gradually. Thanks Jakes.

    • @onlineMathsTV
      @onlineMathsTV  ปีที่แล้ว

      Thanks and we are glad you gained values from it. We are here to serve you.

  • @ProfeJulianMacias
    @ProfeJulianMacias ปีที่แล้ว

    Great teaching

    • @onlineMathsTV
      @onlineMathsTV  ปีที่แล้ว

      Glad it was helpful and like I did promise you in one of my reply to your comment sir, We will do our best possible to make sure we do not fail elderly people like you who out of their tight schedule always put out time to visit this channel to see what is going on and also comment. You are a big encouragement to this platform and we really appreciate that fact sir.
      Many thanks to you sir.
      We love you sir....💖💖💕💕❤️

  • @nicogehren6566
    @nicogehren6566 ปีที่แล้ว

    great question

  • @SidneiMV
    @SidneiMV 7 หลายเดือนก่อน

    3:25 very good trick (dividing by x) 😎

  • @ChristelleHilaire-lb6pu
    @ChristelleHilaire-lb6pu ปีที่แล้ว

    I am jawwing my mind up I like to do it I will be the winner

  • @MarcosSantos-sc7df
    @MarcosSantos-sc7df ปีที่แล้ว +1

    Congratulations

    • @onlineMathsTV
      @onlineMathsTV  ปีที่แล้ว

      Thanks for always be there sir.
      Many a time we have seen your comments @Marcos Santos on our videos. It is an indication that you believe in our little effort and we appreciate that fact sir.
      We pledge to put in our best into what we do in order not to disappoint fathers like you who out of their tight schedule still give our work some attention.
      Know this sir, everyone @onlinemathstv love and cherish you sir....💕💕💖💖💖❤️❤️

  • @StephieJoseph-io3wt
    @StephieJoseph-io3wt ปีที่แล้ว

    👍👍👍

  • @shoshosalah3447
    @shoshosalah3447 ปีที่แล้ว +4

    Take ln for both sides of the equation
    Xln(X+1)+(X+1)ln(e)=ln(-X/e)^X
    Xln(X+1)+(X+1)=X[ln(-X)-ln(e)]
    Xln(X+1)+(X+1)=Xln(-X)-X
    By comparing both sides of the equation
    Xln(X+1)=Xln(-X)
    ln(X+1)=ln(-X)
    Take e for both sides
    X+1=-X
    2X=-1
    X=-1/2

    • @onlineMathsTV
      @onlineMathsTV  ปีที่แล้ว +2

      Bravo👍👍👍
      You the master👌👌👌

    • @joeaberman449
      @joeaberman449 ปีที่แล้ว

      if you went through more detailed explanation would be great

  • @libardouribe7617
    @libardouribe7617 ปีที่แล้ว

    👏

  • @jaketan5172
    @jaketan5172 ปีที่แล้ว

    Specific learning method: After watching this video once, write it out on your own. If you are lost, watch the part of the video where you got lost. Then write it out again. Finally write out the whole solution one more time all on your own without referring to the video. It is normal to take up to 3 times to fully understand such a complex math question.

    • @onlineMathsTV
      @onlineMathsTV  ปีที่แล้ว

      Marvelous, wonderful and superb comment/observation/advice.
      You have spoken as a well trained teacher, maths tutor, a great trainer of all kind of fields of life endeavor.
      You have given nothing but a clever and a well lay down system of learning new things generally/globally accepted.
      Thanks for giving this outstanding advice to our viewers on behalf of Onlinemathstv and we say, we love you so so much and dearly💖💖💖💕💕💕❤️❤️❤️😍😍😍🙏🙏🙏👍👍

  • @ChristelleHilaire-lb6pu
    @ChristelleHilaire-lb6pu ปีที่แล้ว

    ×=+e

  • @ChristelleHilaire-lb6pu
    @ChristelleHilaire-lb6pu ปีที่แล้ว

    J'abandonne