Electronic Devices: Direct Recombination - life time of minority carriers

แชร์
ฝัง
  • เผยแพร่เมื่อ 28 ธ.ค. 2024

ความคิดเห็น • 25

  • @mengzhenc3704
    @mengzhenc3704 3 ปีที่แล้ว +2

    very hardcore and math-intensive, it took me at least half of a hr to figure out everything. Love it!

  • @FlowofElectronics
    @FlowofElectronics ปีที่แล้ว +1

    good lecture sir, please change the icon to reach more people.

  • @luismisanmartin98
    @luismisanmartin98 6 ปีที่แล้ว +2

    In minute 9:25, you say that when we shine the laser, the concentration of minority charges (holes in this case) goes
    from p0 to p0+GL*Tp, where Tp is the lifetime of the holes.
    I don't understand why this is the case. Why does it involve Tp? Shouldn't it be GL*T where T is the time the laser is on?

    • @devbratsrivastava9987
      @devbratsrivastava9987 3 ปีที่แล้ว

      If the laser is on for T, the number of generated carriers would be GL*T, but the number of added carriers won't be equal to that since so many carriers recombine too. That's why Tp (which is the carrier lifetime) is used.

  • @sateeshprathapani
    @sateeshprathapani 8 หลายเดือนก่อน

    very informative...

  • @hazwanharon2147
    @hazwanharon2147 9 ปีที่แล้ว +1

    Thank you great presentation.

  • @thugstatZ
    @thugstatZ 7 ปีที่แล้ว +1

    excellent

  • @alwaysrocks6302
    @alwaysrocks6302 4 ปีที่แล้ว +2

    I even forgot my name after watching this video

  • @b__p_
    @b__p_ 8 ปีที่แล้ว

    is law of mass action valid for steady state e.g voltage applied across a semiconductor?

  • @ankuracademykarera2929
    @ankuracademykarera2929 7 ปีที่แล้ว

    Sir ,Please explain tou at 7:50. from where it came...

    • @chenyuhwu
      @chenyuhwu 6 ปีที่แล้ว +1

      β and n_no are both constants, so we define them as tau, and its unit just equals time's unit.

  • @블랙퍼그뚱이
    @블랙퍼그뚱이 4 ปีที่แล้ว +2

    반갑습니다🥰

  • @007Bedant
    @007Bedant 7 ปีที่แล้ว +1

    Thanks

  • @nethikarrahul6333
    @nethikarrahul6333 7 ปีที่แล้ว

    Sir can u please tell the major difference between recombination , Direct recombination and steady state injection . it's creating a lot of confusion .

    • @techgurukula
      @techgurukula  7 ปีที่แล้ว +1

      Injection: is adding more carriers => can be done by light incidence or forward bias (in case of diode)
      Recombination: conduction band electron combines with hole in valence band => resulting in a valence electron => electron concentration (in C.B) and hole concentration (in V.B) reduces.
      Direct Recombination: They recombine directly - without the help of intermediate states.

    • @nethikarrahul6333
      @nethikarrahul6333 7 ปีที่แล้ว

      thank you sir got a bit clarity , but is it true that in case of recombination and direct recombination we do not apply any voltage across the the semi conductor and the electrons in C.B itself try lo lose its energy and fall in the V.B to recombine with holes .

    • @techgurukula
      @techgurukula  7 ปีที่แล้ว +1

      Hi Rahul,
      I would suggest you to watch the videos in series - follow this playlist:
      th-cam.com/video/HRt0_TlxAl4/w-d-xo.html
      Thanks,
      Techgurukula.

  • @muhammadibnwahid6405
    @muhammadibnwahid6405 5 ปีที่แล้ว

    U is the recombination rate of excess carrier which is equal to the generation of excess carrier GL.

    • @kousikdas9177
      @kousikdas9177 5 ปีที่แล้ว

      Muhammad Ibn Wahid Thanks

  • @ayooshsharma529
    @ayooshsharma529 8 ปีที่แล้ว

    please explain:----- dp/dt = d(pn-pn0)/dt

  • @gateexcellenceece3910
    @gateexcellenceece3910 5 ปีที่แล้ว

    Konsi book se yh topic pdhe

  • @achyuthakrishnakoneti6238
    @achyuthakrishnakoneti6238 9 ปีที่แล้ว +1

    +techgurukula Thanks for the video!!!

  • @fernandoluis53
    @fernandoluis53 8 ปีที่แล้ว +5

    i barely understood anything. u bring in new variables without explaining. might as well skip pointless derivations and just cut the video short and more relevant

    • @techgurukula
      @techgurukula  8 ปีที่แล้ว +5

      +yashfernandojain
      I hope you are watching these videos in series.
      This video is part of a playlist, and the videos are meant to cover derivations with necessary assumptions explained. It's your wish to skip the derivation.
      Thank you for commenting.
      Thanks,
      Techgurukula.