11:00 AM - RRB NTPC 2019 | Maths by Sahil Sir | Trigonometry Identities (त्रिकोणमिति सर्वसमिकाएं )

[@mahichouhan7343]

Jb tk Suraj Chand rhega tb tk Sahil sr ka pdhaya hua concept yaad rhega

[@ajeditx_]

27:29 tan(90-30) =Cot60 =1/✓3

[@rimjhimojha5749]

Love you sir ❤️❤️

[@BiharicomedianBhojpuri]

Achha

[@tarachandsolanki8548]

(1)tanA+cotA
(2) 2cos²-1
(3) cosecA+1/cosecA-1
(4) 2cosecA
(5) cot²Acos²A
(6) secA-TanA
(7) cosecA

[@vguruinstitute]

H.w. Ans.
1.secAcosecA
2.b
3.b
4.b
5.c
6.a
7.c
Thank u so much 🙏🏻🙏🏻🙏🏻
Sahil sir🙏🙏🙏

[@onlinefactsolution3265]

Aap to kaamal kar de rahe hai sir
Aaj tak kisi bhi teacher ke paas aise trigonometry padhe nahi
Please sir aap apna trigonometry ka class jaari rakhe
Mera to dimaag hi khulegi Gaya sir
Mai isse pahle iss chapter se darte the
Thanks sirjee

[@Rahulvishwakarma-ct3dd]

1.secA.cosecA
7.cosecA
4.2cosecA
3.2cos^2A-1
5.cot^2A.cos^2A
6.secA-tanA

[@sonalifarde2109]

Aaj se trignometry ka dar chala gaya.. thank you so much.. sir.. 🙏

[@foodielife2023]

Extraordinary mind-blowing sir🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@SailaKrushna]

Good morning sir...
Ans for homework...
1. C (tanA+cotA)
2. B (2cos^2A)
3. B ((cosecA+1)/(cosecA-1))
4. B ( 2cosecA)
5. C (cos^2 A .cot^2 A)
6. A (secA-tanA)
7 C ( cosecA)
Thank u sir....

[@itsaarushortsvideo]

Ans-
1)tanA+cotA
2)2cos²A-1
3)cosecA+1/cosecA-1
4)2cosecA
5)cot²A.cos²A
6)secA-tanA
7)cosecA
Thank you sir.......🙂🙂
Sahil sir math bahut hi achha pdhate h.......👌👌👌👌

[@alokkumar-yq2vm]

Nice Sir

[@Hxufydigydi]

thanks sir,
1-- tan A + cot A
2-- 2cos^2A -1
3-- cosecA+1/cosecA -1
4--2cosecA
5-- cot^2A.cos^2A
6-- skip
7-- cosecA

[@anshuroy8866]

Super session
Thank u sahil sir😍🙏🙏

[@yogeshgoswami2123]

Very nice class sir Maja aa gya 😊😊😊😊😊😊😊😊😊😊😊😊😊😊😊

[@tradersimi786]

Ans.
1.c
2.b
3.b
4.b
5.c
6.a
7.c

[@AbhimanyuKumar-hg3pe]

1)tana+cota &seca.coseca both hoga
2)x=2cos^2-1 &1-2sin^2a both hoga
3)coseca+1/coseca-1
4)2coseca
5)cot^2a.cos^2a
6)seca-tana

[@vikramkumar-mo8wq]

mera math bahut kamjor tha aap ke is video Se Ab Kuch lag raha hai ki majboot ho raha hai thank you sir

[@tapanpradhan3537]

H.w
1 tanA + cotA
2-2cos^2(A)- 1
3-(cosecA+1)/(cosecA-1)
4-2cosecA
5-cos^2(A).cot^2(A)
6-secA - tanA
7-cosecA....👍👍👍

[@gscorner6001]

1-secA.cosecA 2-2cos2A-1or cos2A 3-cosecA+1/cosecA-1 4-2cosecA 5-c 6-secA-tanA

[@iffatnazneen1320]

TanA+cotA
2cos²A+1
CosecA+1/cosecA-1
2cosecA
Cot²A.cos²A
CosecA+cotA
CosecA

[@SinghSingh-sz6my]

Luv u sir....

[@superplayer5889]

Homework question
Q1--tanA+ cotA
Q2--2cos^2A-1
Q3--b
Q4--2cosecA
Q5--cot^2cos^2
Q6--secA-tanA
Q7--cosecA

[@almagoal896]

Thanks sir aapse pdne me mja aata h

[@dancingrahul2599]

Khub sundor

[@anshugoyl7609]

Q. No. 1 Ans is option A
Q. No. 2 Ans is option

[@Bankatiwale]

home work answer
1. TanA+cotA
2.2cos Square A-1
3. cosecA+1/coseca-a
4.2cosecA
5cot square A *cos Square A
6. secA-tanA
7.CosecA
thankyou sir

[@Bankatiwale]

@@harshit8627 what ??

[@khomeshsahu1594]

1.. secA+cosecA
2.. 2cos^2-1
3.. cosecA+1 / cosecA-1
4.. 2cosecA
5.. cot^2-cos^2
6.. secA-tanA
7.. cosec©
thnku sir

[@AbhishekKumar-ej1bg]

(1)tan*+cot* (2)2cos2A-1 (3)cosecA+1/cosecA-1 (4)2cosecA (5)cot2A (6)cosecA-cotA (7)cosecA

[@Rose-yv9ze]

1)tanA+cotA
2)2cosec^2A-1
3)cosecA+1/cosecA-1
4)2cosecA
5)cot^2A.cos^2A
6)cosecA-cotA
7)cosecA
Thank you sir 🍁🍁🍁

[@shabnambano7155]

Nice 👌 👌 session sir

[@shahanbajkhan7575]

dil khus ho ho gya sir
1st time trigonometry achhi lag rhi hai
love u sahil sir ♥️♥️✌️♥️♥️

[@abhaypatel1522]

Bahut hi badhiya guru ji

[@seemakushwaha142]

2. 2cos sq a -1
3. Cosec a+1/cosec a-1
4. 2cosec a
5. Cot sq a* cos sq a
7. Cosec a

[@beenarathour9637]

1-cosec A.
2-sec A-ha tan A
3- cot2.cos2
4- 2 cosec A
5- cosecA +1/cosecA-1
6- 2cos2A +1
7-secA+cosecA

[@FINALTOUCHFORCOMPETITIVEEXAM]

Sahil Bhai Is One Of the best👍💯 teacher of mathematics on TH-cam 😃

[@Yourrr-ajay]

Thank you so much guru g 🙏
Ans. 1)-SecACosecA
2)x=2Cos²A-1
3-(CosecA+1)/CosecA-1
4-2CosecA
5-Cot²A.Cos²A
6-SecA-TanA
7-CosecA
Nice session Guru g 👌👌👌👏👏

[@Ambe765]

Sir, thanks

[@जोधपुरीबन्ना]

1 A
2 B
3 B
4 B
5 C
6 A
7 C

[@RohitYadav-hv7jp]

Sir AP bhut acha padhate h

[@yogeshwaimandiya9748]

Sir you the best teacher

[@Dgkstudy]

Nice class Sir thanks sir aap math super teacher ho👌👌👌👌👌

[@aryangyan8888]

2) 2cos2A-1
3) cosecA+1/cosec-1
4) 2cosecA
5) cot2A. cos2A
6) secA-tanA
7) cosecA
1) secA. CosecA

[@arvindmali3200]

Tq sir ji nice😎
Ans1- secA+ tanA
2-2cos2-1
3-cosecA+1/cosecA-1
4-2cosecA
5-cot2Acos2A
6-secA-tanA
7-cosecA

[@sb-hf7tw]

22:51 2p की जगह p^2 भी हो सकता है , इसलिए Pythagoras method is better...

[@gopaltanwar3201]

THANKS A LOT SAHIL SIR JI AWSM CLASS MJA AA GYA .THANKS A LOT WIFI STUDY

[@omparkashkumar6031]

1,tanA+cotA
2,2cos²A-1
3,cosecA-1/cosecA+1
4,2cosecA
6,secA-tanA

[@factzone777]

H W
A-1 - secA cosecA
A-2 - x=2cos2A-1
A-3 - cosecA+1/cosecA-1
A-4 - 2cosecA
A-5 - cot2A cosec2A
A-6 - secA-TanA
A-7 - cosecA

[@chandanpatel1863]

Apka class dekhta hu to bahut achcha lagta he dimag halchal hone lagta he so beautiful explanation sir

[@meenakshiroy299]

1-c
2-b
3-b
4-b
5-c
6-a
7-c

[@dancingrahul2599]

Awasome awasome awasome awasome

[@rj_choudhary2992]

nice sir jii aap bahut aavha padte ho ,,, mujhe trigonometry k question pheli baar smj me aaaye h

[@priyankamaji2553]

Thanks sir..
Nice session...
Homework:-
1) Skip
2) 2cos^2 A-1
3) (CosecA+1)/(CosecA-1)
4) 2CosecA
5) Cot^2A × Cos^2A
6) SecA-TanA
7) CosecA

[@smarty6435]

1 option c

[@smarty6435]

Go through option and square all of them

[@priyankamaji2553]

@@smarty6435 yes

[@Ambe765]

Mja aa gya Sir, thanks

[@MathsByMohitLakshakar]

Ans. 🔵🔵🔵🔵🔵✔️✔️✔️✔️
1. TanA+CotA
2. 2Cos*2A -1
3. CosecA+1/CoseA-1
4. 2CosecA
5.Cot*2A.Cos*2A.
6. SecA -TanA
7. CosecA.🙏🙏🙏🙏🙏🙏🙇

[@p-jc5rc]

48 is the answer... Am I right ??

[@harshraj85]

@@p-jc5rc yes absolutely right

[@harshraj85]

@Deepali vyas 48 is the right answer...
LCM 48
PQ - 4
QR - 3
PQ×5 + QR×2 + R×11= 48
R = 2 then Q = 1
Total work ÷ Q = 48÷1 =48 answer

[@harshraj85]

@Deepali vyas ok Deepali👍

[@tusharpowar9115]

1) CosecA.SecA
2) 2Cos2A-1
3) (CosecA+1)/(CosecA-1)
4) 2CosecA
5) Cos2A.Cot2A
6) SecA-TanA
7) CosecA

[@mandeepkalirawana7137]

Good job sir👍👍👍

[@ritakushwaha134]

Homework ans
1Q)(a)secA.coseceA
2Q)(B)2cos2A-1
3Q)(B)cosecA+1/cosecA-1
4Q)(B)2cosecA
5Q)(c)cot^2A.cos^2A
6Q)(a)secA-tanA
7Q)(c) cosecA
Thanku sir☺️☺️

[@durgaprasadpuhan3382]

Sir app ka class bahuti accha laaga

[@mohineevishwakrama6516]

Answers
1)=secA+cosecA
2)=2cos*2-A
3)=cosecA+1/ CosecA-1
4)=2tnaA
5)=cot*2A.cos*2A
6)=cosA-cotA
7)=cosecA
Thank you so much sir ji

[@asanasingh2462]

Thanks sir So much

[@poojarajput7388]

Ans📚📚
1} tanA+cotA
2}. (B) 2cos^2A-1
3}. (B) CosecA+1/cosecA-1
4}. (B) 2cosecA
5}. (c) cot^2Acos^2A
6}. (a) secA-tanA
7}. (c) cosecA
Thnks sir 👍👍👍

[@eeshanrajput9335]

Gudd sir keep it up. May God bless uh definitely

[@abhishekprajapati4584]

tanA+cotA
2cos^2 A-1
cosecA+1/cosecA-1
2cosecA
cot^2 Acos^2 A
secA-tanA
cosecA

[@shiulibodhak3229]

H.W ans...
1)tanA+cotA
2)2cos²A-1
3)cosecA+1/cosecA-1
4)2cosecA
5)cot²Acos²A
6)secA+tanA
7)cosecA
Thank U Sir🙏🏻

[@Pahariharyana]

Ek no .........sir

[@ravishankarkushwaha1655]

Gajab Sir g

[@pwshorts9698]

You are the maths wizards sir . Love u sir👌👌👌👊👊👊💖💖

[@gitapal1988]

HW Ans..
1) c
2) b
3) b
4) b
5) c
6) a
7) c
Thanku sir 🙇 🙇 🙇

[@ankitbhardwaj2231]

बहुत बढ़िया साहिल सर। बहुत बढ़िया trick से questions करवाये आपने। wizards of math , trigonometry aap dubara karva rhe ho. Crash course me badiya questions hai. Great sir. God bless you . May you live long. Es baar hssc harayana police me trigonometry ati hai. Double benifit 1 ntpc 2 harayana police. Thanks sir.

[@vilasverma6059]

Ans.
1. TanA+CotA
2. 2Cos*2A -1
3. CosecA+1/CoseA-1
4. 2CosecA
5.Cot*2A.Cos*2A.
6. SecA -TanA
7. CosecA.
mja aa gya sir such me

[@farhanaaz4072]

ans_1-tanA+cotA
2-x=2cos^A-1
3-cosecA+1/cosecA-1
4-2cosecA
5-cot^A.cos^A
6-secA-tanA
7-coseA

[@pushpendradix52]

Bhut acha class

[@ananyapalta8683]

Bariya sir ji...
Ans are-
1.c
2.b
3.b
4.b
5.c
6.a
7.c
Thanku sir..

[@shaileshparmar870]

Sir ye method.... Best he...

[@ShreeSwamisamarth-w8d]

Sir I love you

[@suchitsingh3057]

Very nice sir

[@er.sumanlatagautam1147]

HW ans
1)C- tanA+cotA
2)B- 2cos^2A-1
3)B- (cosecA+1)/(cosecA-1)
4)B- 2cosecA
5)C- cos^2Acot^2A
6)A- secA-tanA
7)C- cosecA

[@xillpankaz8316]

Sir mojja ah gaya😃😃

[@binodstudy3501]

1 ans. tanA+cotA
Q.2 ans. 2cos2A-1
Q.3 ans. cosecA+1/cosecA-1
Q.4 ans. 2cosecA
Q.5 ans. cot2A.cos2A
Q.6. ans. secA-tanA
Q.7. ans. cosecA
Thanks sir

[@debapamghosh4169]

1 ) tan a + cot A
2) (2 cos^2 a -1) = x
3) coseca+1/coseca-1
4) 2 cosec a
5 ) cot^2a cos^2a
6) sec a - tan a
7) COSEC A

[@aratikanwar8400]

Ans.
(1) = tanA + cotA
(2) = 2cos^2 - 1
(3) = cosecA +1/cosecA - 1
(4) = 2cosecA
(6) = secA - tanA
(7) = cosecA

[@neerajsinghd8999]

Thanks sir for this class 👌👍

[@nomzologaming1095]

Ans-
1-c
2-b
3-b
4-b
5-c
6-a
7-c
Heartly thanks......

[@rituvashodia8614]

Nice session

[@utterpradeshpoliceupcop4926]

Sir you are brealient

[@hanumatraj4533]

Sir I like u. To much mene sir ap ki sari class dekata hu... Me up ke lalitpur जिले के छोटे गाव kalyanpura से belong karta hu I like you again

[@Ramrajjangid7]

Shandar zindabad jbrdst 🙏

[@himanshuvaishanv9936]

Best hai sir

[@byasathati2777]

Thanks sir
I understand its chepter

[@rameshr5739]

1=tanA+cotA
2=2cossquare2A-1
3=cosecA+1/CosecA-1
4=2cosecA
5=cotsquare2*Cossquare2A
6=secA+tanA
7=cosecA

[@jyotigupta8891]

Gudmorng sr...
Home work ans
1=ans 4 jo option me ni h
2=2cos^2 A-1
3=skip
4=2cosec A
5=cosec A - cot A
6=skip
7=cosec A

[@ramavtarpandey4200]

Oh yarr aapki dp mujhe kisi ki yad dilati h😭😭

[@sarthaksrivastav4254]

Bhhut pyara sir.....to good ........thanks sir. ...ek kami h aapme sir...thorda jyada down chale jate hai....calculation and formula direct applied kiya kare..time .forward karna padta h ...basic ko leave kiya kare sir...pls

[@rohititare3649]

Thank you Sir

[@PauranikChitran]

Yes, sir you are the best.

[@rahulmodi175]

sir trigonometry ke baad please mean median mode ke question karaye plz sir

[@Manishkumaryaduwanshi0101]

What teacher yaar mind

[@khusboochouhan569]

Sir apne hw k simplification session k ques solve ni kraye h

[@factzone777]

Best class ever

[@astruggler4343]

Thank u sir...