IQ Signals

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  • เผยแพร่เมื่อ 11 ม.ค. 2025

ความคิดเห็น • 23

  • @prutser67
    @prutser67 ปีที่แล้ว +3

    I like the explanation of the negative frequency. Haven't seen that so clear that far 😊

  • @yarenkaya7872
    @yarenkaya7872 6 หลายเดือนก่อน

    Wow, this was exactly what I was looking for, for the homodyne receivers.The reason behind why we use 2 orthogonal signals explained beautifully!

  • @bodstrup
    @bodstrup ปีที่แล้ว +1

    Finally, I think I understand ‘negative frequency’. Previously - my Q was ‘How can you have less than 0 oscilations per second ?’

    • @TheGmr140
      @TheGmr140  ปีที่แล้ว +2

      Negative frequency is just a signal below the lo frequency

  • @fernm2861
    @fernm2861 9 หลายเดือนก่อน

    The receiver block diagram presented @4:55 shows an ADC between the IF stage and the DDC block. I thought the output of an ADC was a binary value (composed of 1's and 0'S) that represented the level of the analog signal at the sampling time. How can such a binary representation of the signal level be used by the DDC? Thank you!

  • @weirdsciencetv4999
    @weirdsciencetv4999 ปีที่แล้ว

    I have an on-again off-again project for a SDR based on a superegenerative front end. Phase information is typically obliterated but I plan on recovering it using the fact that the tank circuit stays locked in phase with the carrier. So I want to make a circuit that can recover the phase AND amplitude of the signal in IQ form, just like a normal SDR. The idea is to eliminate the ADC and also have tremendous dynamic range. Most of the SDRs I have made suffer from artifacts when front end is overloaded.
    So far I can decode things like 8-PSK, but I hope to make it work for signals in general.

    • @philkarn1761
      @philkarn1761 ปีที่แล้ว

      Superregen is very difficult to keep stable, why do you want to use it? It made sense way back when every single tube was very expensive, as it saved components. Now that good RF amplifiers are cheap and perform well, why not use them?

    • @weirdsciencetv4999
      @weirdsciencetv4999 ปีที่แล้ว +1

      @@philkarn1761 i do still use conventional zero-IF and various IQ front ends. Doesn’t mean I can’t experiment and play around right?

    • @philkarn1761
      @philkarn1761 ปีที่แล้ว

      @@weirdsciencetv4999 Sure! I still remember the superregen toy CB transceiver I got as a kid. Got me started...

  • @ravindergoyat4316
    @ravindergoyat4316 10 หลายเดือนก่อน

    Nice explanation

  • @martindegourcuff8854
    @martindegourcuff8854 5 หลายเดือนก่อน

    Super clear thanks! Is there an advantage to perform IQ demodulation in FMCW since dechirping only creates by construction positive beat frequencies?
    Many thanks and cheers from France

    • @TheGmr140
      @TheGmr140  5 หลายเดือนก่อน +1

      @@martindegourcuff8854 I would say yes, by having iq demod, the amp and phase of the chirps are preserved and sampled

    • @martindegourcuff8854
      @martindegourcuff8854 5 หลายเดือนก่อน

      @@TheGmr140 thank you for your answer

  • @alexturner2593
    @alexturner2593 ปีที่แล้ว

    Brilliant! Earned yourself a sub!

  • @robyounce4636
    @robyounce4636 6 หลายเดือนก่อน

    Nobody ever explains" why do we want to do this, to generate I and Q signals?" HOW do we use these to eliminate a Sideband?? What is the complete process?

    • @TheGmr140
      @TheGmr140  6 หลายเดือนก่อน

      @@robyounce4636 see my newest video: iq Modulation

    • @TheGmr140
      @TheGmr140  6 หลายเดือนก่อน

      Iq can make and decode any radio signals, iq measures amp and phase of a radio signal

    • @SingleBitTech
      @SingleBitTech 3 หลายเดือนก่อน

      yeah I've been arguing the whole morning with chatgpt about this until we both finally agree😂😂

  • @exponentmantissa5598
    @exponentmantissa5598 หลายเดือนก่อน

    That does not look like 10 Db of attenuation. Where did the 20 come from? You are dropping the signal level by a factor of 0.316 when the strength should 0.1. How is that 10 dB ???

    • @TheGmr140
      @TheGmr140  หลายเดือนก่อน

      @@exponentmantissa5598 math is correct, db to voltage, 10^(db/20)

  • @mirkozimmermann4682
    @mirkozimmermann4682 11 หลายเดือนก่อน

    Really good movie

  • @theoryandapplication7197
    @theoryandapplication7197 8 หลายเดือนก่อน +2

    thank you for shring

  • @kaikim7601
    @kaikim7601 5 หลายเดือนก่อน

    Thank u