Concentration of organic matter in a sealed water sample after remaining in dark for 4 and 8 days at 20 °C is calculated to be 160mg/L and 60mg/L respectively. ? (CLO-1,PLO-1,C1) (15 marks) a) Calculate value of k at 20 °C and at 25 °C.
I came across this question, where they are asking to find the distance from the point of discharge, at which the DO would be minimum when waste water is discharged into the river. Given are D.O of waste water, BOD-5 of both waste and river water De - oxygenation constant of both, discharge of both, Which de- oxygenation constant should be considered? velocity of river.
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Yes! I am aware of that but what I have told is correct. If it says clearly that the BOD becomes zero on the 5th day then you can take it to find out the average but here nothing like that is mentioned so you can do it as I have mentioned. Sorry for the late reply.
Dear sir sample is tested after 5 day we found DO zero ....it may be consumed in 1 or 2 or 3 or 4th day ......so the third result will give misleading result..so we should not use this?
Sir in the 2nd question BOD for 5days was given as 180mg/l but you have used the same value of BOD for 2.5days also can we do it like that also? Because i hope BOD will change from 2.5 to 5days
BOD also depends upon the Temperature because the bacterial activities depend on the temperature and as the Temperature increases bacterial activity also increases upto 60 degree Celsius. The BOD value for 5 days is given for a temperature of 20 degree Celsius and if you increase the temperature then same value of BOD can be exerted in lesser time so the question asks the temperature at which the BOD5 = BOD2.5
Concentration of organic matter in a sealed water sample after remaining in dark for 4 and 8 days at
20 °C is calculated to be 160mg/L and 60mg/L respectively. ? (CLO-1,PLO-1,C1) (15 marks)
a) Calculate value of k at 20 °C and at 25 °C.
thank you very much sir :) it is really very helpful.
If in the question it is mentioned deoxygenation rate constant how to know if it is base e or base 10?
K 0.1 IS BASE 10 , K 0.2 IS BASE E
love the way teach!
I came across this question, where they are asking to find the distance from the point of discharge, at which the DO would be minimum when waste water is discharged into the river.
Given are
D.O of waste water,
BOD-5 of both waste and river water
De - oxygenation constant of both, discharge of both,
Which de- oxygenation constant should be considered?
velocity of river.
very nice sir
How to solve 2nd ques equation in virtual calcy
sir very awesome idea sir....thanku so much
Excellent sir thank you so much..😘
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@12.4 (to convert /hour to /day) sir you mention divide by 24.. but we suppose to multiply.. pls correct if I was mistaken..
Bro the way he divided is correct because it will get reciprocaled and get multiplied.
oh i have to take ln instead of log.. am cleared bro...
aditya sir in avg BOD quest ....i have reffered a coaching material and ans they have given is 109.8mg/l. its confusing
Yes! I am aware of that but what I have told is correct. If it says clearly that the BOD becomes zero on the 5th day then you can take it to find out the average but here nothing like that is mentioned so you can do it as I have mentioned. Sorry for the late reply.
Dear sir sample is tested after 5 day we found DO zero ....it may be consumed in 1 or 2 or 3 or 4th day ......so the third result will give misleading result..so we should not use this?
in 22nd que how did u get the K value as 0.36. am confused with antilog and e steps...plz explain bro.
Sir same problem
kajal nirmal take exponential on one side and solve it, then use log on both sides, remember log e=1
Sir in the 2nd question BOD for 5days was given as 180mg/l but you have used the same value of BOD for 2.5days also can we do it like that also? Because i hope BOD will change from 2.5 to 5days
BOD also depends upon the Temperature because the bacterial activities depend on the temperature and as the Temperature increases bacterial activity also increases upto 60 degree Celsius. The BOD value for 5 days is given for a temperature of 20 degree Celsius and if you increase the temperature then same value of BOD can be exerted in lesser time so the question asks the temperature at which the BOD5 = BOD2.5
how to solve 1:37....?
Sir e bala part kese calculate kia
What i put at place of e?
nothing e mean exp at math you can find it at calculater
solution of question 2 is quite lengthy......it can be solved in just few steps
plz send typing wright not hand..
becoz ur wrigt not readable
Thanks sir
Bhai base10 waala problem chaiye
Gate 1998 Bod question ka ans batao
Thanks sir