Q. 2.4: Reduce following Boolean expressions to the indicated number of literals (a)A'C' + ABC + AC'

[@bhavyakarma8678]

sir plz explain (x'.y')'=(x+y) how

[@DrDhimanKakati]

It is as per DeMorgan Theorem drive.google.com/file/d/1DWP9mKhm_rjVb0hKpMfjg3sivqp5K9Mt/view?usp=sharing

[@shanmugapriya7554]

(X'+Y')'=x''+y''
Here(x''=x)(y''=y)
=X+Y.

[@_sanskriti903]

@@shanmugapriya7554 + converted into . While applying complement....

[@mohammedbalousha9467]

very nice ....
Fast and cool approach to solution

[@shradhanjalidigal317]

Thank you so much sir ❤️

[@SipraHouse]

Nice

[@garvitapun3749]

Sir having one doubt in these two following questions:
Could you please check whether their answers is correct or wrong.
Q. Obtain the complement of the following Boolean expression:
1) f= xy'+x'z
Ans: y.x+x'z'+y.z'
2) f= x(y'z'+yz)
Ans: x' + y.z' + z.y'
Sir could you please tell

[@parthomohanto2420]

Love from Bangladesh sir..this is really helpful.thank you sir for making this playlist

[@Revolutionshistory]

sir! in question (b), how can u write? from{(x.y).z'+z}=(x+y+z).z'+z??

[@cypryzraypanaguiton5286]

why's there no answer yet 😭😭

[@wolflexx]

@@cypryzraypanaguiton5286 yall figured that out??

[@oquackk704]

thank you doc dhiman

[@mondipeditz8578]

Well explained sir pls upload more vedio on digital logic💕💕

[@zaidemara7300]

THANK YOU SO MUCH

[@jeonie9682]

thank you for your explanation!

[@ranjangoswami4377]

Sir @ 2:30 i didn't understand how you've made {(x+y).z'+z} as (x+y+z) (z+z')

[@DrDhimanKakati]

Assume A=z, B=x+y and C=z'
We know A+BC= (A+B)(A+C)
Thus (z+x+y)(z+z')

[@ranjangoswami4377]

Got it.. thanks sir

[@Revolutionshistory]

@@DrDhimanKakatiwhat is the name of this property in bolean algebra?We know A+BC= (A+B)(A+C)

[@carterl8342]

@@Revolutionshistory Did u ever figure out what the name of this property is?

[@4sTaRzda]

@@carterl8342 Distributive

[@rynakiqbal]

You are amazing sir.

[@c.v.s.deepthi543]

final equation we get is (AC+A'C') we should count A and A' as seperate literals or same???

[@DrDhimanKakati]

Please mention the time duration.

[@chessmanjd]

Can You tell me the book from where these questions are from

[@Farhan4you]

sir plzzzzzz tell me how to download this book??? plz

[@laibanadeem6960]

Thank you sir

[@mondipeditz8578]

Sir in 1:30 I don't understand how that c'+ABC change into C'+AB

[@DrDhimanKakati]

A+BC= (A+B)(A+C). Here, in this case, we have considered A=C', B=A and C=B.

[@m.mubashar786]

Distributive property

[@nehasharma2341]

Helpful ❤️

[@ravisankarsangu7604]

Thank you sir 🙂

[@PetBuddies]

thank you so much Sir

[@varahalashome8308]

One thing I don't understand is that your questions and in the book are two different questions

[@sujisuji6772]

4th sum I'm not understanding sir plz once again explain

[@ashamselectronics]

❤❤

[@fahimiqbal5876]

how to solve this..B(CD+C'D')+AB'(C'D+CD')

[@ashwiniashu5866]

Sir, in (D) question why you took 2nd and 3rd terms to obtain common.. We can take 3rd and 4th terms na sir? (Time duration:6:15) and what is the answer for A'A'sir?

[@sahilrout37]

A'A'=A'

[@mariomakter4407]

sir please expalin X = A+AB’C+A’B’+AC’BD’

[@dhruvgupta1740]

in b part I m getting 2 literals xy

[@abdullahaljanabi6020]

Simplify by Boolean algebra: AB'C + A'B' + ABC'D

[@veerunaidua2453]

Tq sir

[@c7...741]

A'B'C'+A'BC'+AB'C'=C'(A'+B')
plzz ans batao sir isaka koi bhi batao plzz....

[@mondipeditz8578]

Pls upload 2-17 and 2-18

[@DrDhimanKakati]

It is already there. Check the playlist

[@sanaarif6924]

ABC+A'B'C+ABC+A'BC'+A'B'C' kindly Sir Solve this Expression to 5 literlas

[@DrDhimanKakati]

Plot in K-map and see what comes

[@sanaarif6924]

@@DrDhimanKakati A'B'.... nd Sir here ABC are twice

[@DrDhimanKakati]

@@sanaarif6924 Please ckeck again for ABC. May be there some printing mistake.
If it is twice it is same and ignore the 2nd ABC, because ABC+ABC=ABC

[@sanaarif6924]

@@DrDhimanKakati no sir here is no printed mistake this qs is as it is

[@sanaarif6924]

@@DrDhimanKakati ok sir then K_map of this is qs is equal to A'B'

[@naruabhishek2401]

👍

[@naruabhishek2401]

K

[@muhammadahmadyousaf2824]

just solving question not explaining

[@DrDhimanKakati]

You can ask your doubt here in comments.

[@khansaloosa4738]

Mataculas lecture

[@DrDhimanKakati]

Thank you 😊

[@khansaloosa4738]

Its ok its my dewty

[@abdullahmalik7459]

shzada

[@Raju_official567]

Thank you sir