Plus Two Physics Chapter 3 | Current Electricity

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ANS 17Ω
പഴയ ഫൈനൽ എക്സാമിന്റെ തലേന്ന് ക്ലാസ് കാണുന്ന വൈബ് കിട്ടി 😌🙌🏼🤟🏼

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Ashiq sir thijj 🔥
10-(0.5×3) /0.5
17 ohm

[@crazy_krizz]

❤️‍🔥❤️‍🔥Thank you theeppori sir for giving a good class ❤️‍🔥❤️‍🔥

[@checkinbot217]

Answer of the day 2:09:10
R=(E-Ir)/I
R = (10-0.5*3)/0.5
R = 17 ohm
Option c is the right answer
Class was lit❤

[@angel_2006_]

Theepori sireyy.. Adipoli class aarunu... Elam set.. Powerooskki🔥🔥💥💥💙💙
Ans.
R=17ohm

[@sujithacs4368]

Ans = 17 ohm
Thankyou hashiq sir ❤& eduport team ❤🥰

[@dilna8310]

R=E-Ir/I
=10-(3×.5)/.5
=8.5/.5
=17ohm
Thank you hashiq sir and eduport❤❤

[@shalinikr8160]

iyya uvva hashiq sir🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥 ........ttattadattattattattaa..........❤❤❤❤❤❤❤❤❤❤🔥🔥🔥🔥🔥🔥🔥🔥

[@Minnaas_vlogs]

R=17ohm
Thankyuhh for eduport nd hashiq sirr🥰👍🏻nallath Poole rivision cheyyan Patty chapter, Ellam onnude clear cheyyanum sadhichuuu thankyouhhhh so much🤍✨️

[@maaaaaannanaanaaa]

5:40 start❤

[@Mushroom866]

Answer is 17 ohm,
Given,
E= 10V
r=3ohm
i= 0.5 A
Therefore, V= E-ir
V= iR
Therefore, iR = E-ir
R=(E-ir)÷i
= (10-1.5)÷0.5
= 17 ohm
Sir this lives are very useful ❤thanks sir

[@Artisticcreations6291]

Ans :17 ohm
Nalladhu pole revision cheyyaan sadhichu .....nalla effective class aayirnn 💯🔥Tnx for eduport team and hashiq sir ❣️🥰

[@fath_ima_3722]

Download option endha vekkaathe

[@adhithyanms5823]

Answer R=10-0.5×3/0.5 = 17 ohm And Sir class veree level chapter sett and thanku theeepori SIREEE for you effort❤❤❤❤❤❤❤❤❤❤❤

[@fasila2005]

IR:E-Ir
R:E-Ir÷I
(10-0.5×3)÷0.5
17 ohm..
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right answer 👏👏👏
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Adipoli classആയിരുന്നു എന്റെ തീപ്പൊരി siree ❤❤❤🎉

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Asipoli class ayinu theepori sir 💙💙💙💙💙 super ayitt eaduthu

[@NileenaT]

Ans: R=E-Ir/I
10-(0.5×3)/0.5
=17ohm
Thank you sir❤
Thanks eduport...

[@EduportPlusTwo]

right answer 👏👏👏
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[@a__m_n_ahh]

Ans = (c)17 ohm
I understood this cls very well. Thank you, hashiq sir ❤

[@vrindasivas]

Adipoli theeppori class🔥🔥🔥🔥💪💪💪

[@Roy11.33]

eqn IR=E-Ir
r=3 ohm
emf = 10v
I= 0.05
R=?
V=?
V=e-Rr
R=17ohm
V= 8.5V
thank you ❤

[@prathyunvava4789]

17 ohm...full conceptum clr ayi...so tq so much💙 EDUPORT💙

[@sreekalas4335]

Innathe class adipoliyayirunnu thank you hashique Sir. Today's question of the day answer : 17 ohm

[@shameemasam1685]

17ohm
Wonderful session, it made to understand the whole class. I loved the full class. It was very useful. Thank you hashiq sir and eduport for this wonderful session ❤

[@Rishann..]

Thankyou for the class hashiq sir
The answer is 17ohm

[@nived214]

17 ohm. Thanks eduport team for the live. 👍

[@ShalfinaShajahan]

Answer is 17 ohm
And Theepori Sir thank you for your amazing and powerful class

[@meera3294]

Question of the day answer : 17 ohm
Nice class hashiq sir and
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[@savithac.s8707]

R=E-Ir/l
=10-(3x.5)/.5
=8.5/.5
=17ohm
Thank you hashiq sir 🌟❣️

[@niyas_mon]

ans) 17 ohm..... super class..everything is crystal clear

[@dgak1046]

20 ohm
Good class sir enik nannayi manasilayi thankyou sir❤️

[@fathimahannathp]

R=E-Ir/I
Ans 17 ohm.
Thankss eduport🙌🏻❤️

[@sandeepalr]

Poli class, thipori sir poli🔥🔥🔥

[@_alth_x_z]

Ans=17 ohm
Live okke chumma 🔥🔥🔥
Examin mumbe e padam set akki thanna eduport❣️❣️

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Excellent Physics class I ever watched

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@@Hashiq_Eduport adutha live enna sir😊

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17 ohm sir classes use ful annu tough aaya physics easy aayi thanks eduport 😊 onam exam inu 4 chapters enna teacher paranjath

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17 ohm
Thanks eduport❤️🔥🔥

[@abhirami7578]

Qstn of the day
Ans: 17ohm
Tnq sir💙💙

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Right answer

[@shaimaa.3712]

17 ohm.
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ashique sir is better than nithin sir

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100%

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Don't compare bro everyone has their own abilities😊

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True ​@@selvanraj429

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Nah nithin sir better>>

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Angane parayalleda

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R=10-(0.5*3)/0.5=17ohm (c)

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right answer 👏👏👏
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Seeen class ❤ thanks sir❤

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[@kumari.m1976]

R=E-Ir/I
=10-(0.5×3)/0.5
=17 Ohm
Thank you so much eduport ❤

[@ThejaPmD]

Ans) 17 ohm
Polwi class aayirunnu sir,
Inikki onam examinu first 4 chapters ind.

[@haripriyak6943]

17 ohm
Thank you sir..❤

[@femidapv3859]

ans. 17 ohm
Sir class super. Thank you Hashiq sir and eduport whole ❤ 🔥🔥🔥🔥
Enikku 4th unit varee aanu examinu 🙌🏻

[@Anzilzain]

Thank you sir. Class നേരെ മനസ്സിലായി.

[@joicethomas5544]

Ans:- R=E-Ir/I
=10 - (0.5×3)/0.5
=17ohm
Clz Poli ayirunnu..............

[@abhilash_perne]

Sir last equation enhalle paranje....appol vere steps undo

[@aswathikrishnan49]

17 ohm
Thank you so much for this energetic class❤

[@edgerr_69]

Option c)17 ohm

[@devananda1936]

Ans=17 ohm
Adipoli class thank you theepori sir 😊

[@amritha542]

Ans:- R=E-Ir/I
=10 - (0.5×3)/0.5
=17ohm
Thank You Eduport❤️‍🔥Exam nte munne ellam manasilakkan sadhich.... Ee chapter set aan 🥹💗

[@anuzz..2145]

c)17 ohm
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[@fathimarana6150]

Answer: 17 ohm
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right answer 👏👏👏
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[@nivedhithamaneesh6915]

R=E-Ir/I
=10-(0.5×3)÷0.5
=17

[@rajikrishnakumarkrishnakum1850]

17ohm..
Adipoli class... Full set ane😁

[@nidhaayshamt2697]

17 ohm
Nalla class ayirunnu😊😊

[@sahalshank4227]

ans: 17 ohm
theepori sir power
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Thank you eduport

[@irfanasherin4030]

R=17 ohm thank you hashiq sir🔥

[@Manunsjskdkje]

Set ayi

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Thank you sir ✨✨

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Most welcome

[@aryaviswanath7356]

Ans 17 ohm
Thank you Hashiq sir ❤❤

[@thanveerabu]

Ans:- 17 ohm

[@anushageorge8973]

❤❤❤

[@neeraj1364]

C)17 ohm

[@infinityversa4465]

c)17

[@hawinsojan2815]

Ans) 17 ohm

[@krishnac5201]

AnB={2}

[@fiyas__nk]

Ans is →17 ohm

[@ANWARANNU-d9n]

Ans : 17 ohm❤

[@abhilash_perne]

Relation between I and Vd derivation athra tanneyano

[@fyh02129]

Given
E=10v
r=30ohm
i=0.5A
Therefore V=E-ir
V=iR
IR=E_ir
R=(E-ir)/i
=(10-1.5)/0.5
=17ohm
Thankyouu ❤️

[@ISAIQBAL-r8m]

resistivity depends only on material

[@white_testarossa_7]

Ans = 17 Ω

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Video downloard akkan pattunnilla 😢 ini idunna videos yenkilum download akkan pattunnareethiyilakkuu plzzz😊

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Live kazhinj kurach kazhinjaale download aakkaan patulloo

[@dityastik]

Answer is 17ohm

[@1secn]

Ippo kanunnavar indoooooooo😂🧠

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[@zodiac292]

17 ohm Thanks Sir

[@sunilorkkadavkumar6235]

R=17 ohm

[@Bronxx_0]

Theepori sareee ellan set ayi 🔥🔥🔥❤️‍🔥

[@sandeepalr]

17 ohm

[@shajeed7165]

Answer = 17Ω

[@sreya3746]

Ans = 17 ohm
Thank you sir

[@CALLGAMING1312]

17 ohm🙈 late ayi

[@alshifanowshad9590]

Sir is this cbse or state focuw

[@Everything_for_her]

😮❤Manthi (Menti) kitiyila 🙂 but class adipoli....❤ cheriya net issue indayi but full kandu.... thank you Eduport ❤💖 paranja pole anwer 17 ohm answer❤

[@an_uji_th]

ANS. 17Ω

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Good class

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Eduport is fking awsome
17 ohm

[@GayathryP-h4i]

R=E-Ir/I
=17

[@anjus6367]

17 ohm
No comment❤

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17 ohm poli class oru rakshayum illa

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Hlo 👋

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✨️

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Thanks sir

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Welcome♥️♥️♥️