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Thank you professor for good solution.
Glad you found it helpful! 🙏You are very welcome!Thanks for the feedback ❤️
Fine!!!!!
Very nice Prof, you are the best!❤
Sir you wrote bec area as y+56 when it should be y+96 but when you cross multiply you use the correct y +96 😂😂
Very nice. Subscribed and saved off.
Thank you!
The next challenge will be to calculate the sides AB, AC, BC. Can you try it?
Good work, but at 5:28 it is y+96 but not y+56, but i really enjoy it
✨Magic!✨
{84A+DC35}+{56EB+40FB}={119°ADC+96EBFB}={215°ADCEBFB ➖ 180°}=135°ADCEBFB 10^10^35 1010^5^7 2^5^2^5^5^7^1 1^1^2^1^1^1^1 2^1 *ADCEBFB ➖ 2ADCEBFB+1).
I knew PreMath would show a more elegant solution than mine. I used x=3y/2+25 and the Ladder Theorem. The algebra was a bear but it was doable.
Very nice using principles of triangles in solveThanks Sir With my respects ❤❤❤
If all the altitudes are intersecting at the same point, is it possible to be a scalene triangle?
y+56 or y+96?
The answers are x = 70 and y = 30. We know bc 70 is 35 doubled and this is consistent with the ratio of the base. I hope that that makes sense.
这题有个问题，p点不需要是垂心，是任意一点都一样，即条件多余。
So challenging. I Didn't get it
84÷56=1.5)(35÷1.5=23.33333green 40×1.5=60 purple
84 : 56 = 3 : 2 140 : 40 = 7 : 2ADP=x CFP=yx+119 / y+96 = 3 / 2x+35 / y = 7 / 2 2x+238 = 3y+288 2x = 3y+502x+70 = 7y 2x = 7y-703y+50 = 7y-70 4y = 120 Purple area = ADP = x = 70Green area = CFP = y = 30
Very nice breakdown.
{84°A+35DC}+{56EB+40FB}={119°ADC+96°EBFB}={215°ADCEBFB ➖ 180°}=135°ADCEBFB 10^10^35 10^10^5^7 2^5^2^5^5^7^1 1^1^2^1^1^1^1 2^1(ADCEBFB ➖ 2ADCEBFB+1).
Thank you professor for good solution.
Glad you found it helpful! 🙏
You are very welcome!
Thanks for the feedback ❤️
Fine!!!!!
Very nice Prof, you are the best!❤
Sir you wrote bec area as y+56 when it should be y+96 but when you cross multiply you use the correct y +96 😂😂
Very nice. Subscribed and saved off.
Thank you!
The next challenge will be to calculate the sides AB, AC, BC. Can you try it?
Good work, but at 5:28 it is y+96 but not y+56, but i really enjoy it
✨Magic!✨
{84A+DC35}+{56EB+40FB}={119°ADC+96EBFB}={215°ADCEBFB ➖ 180°}=135°ADCEBFB 10^10^35 1010^5^7 2^5^2^5^5^7^1 1^1^2^1^1^1^1 2^1 *ADCEBFB ➖ 2ADCEBFB+1).
I knew PreMath would show a more elegant solution than mine. I used x=3y/2+25 and the Ladder Theorem. The algebra was a bear but it was doable.
Very nice using principles of triangles in solve
Thanks Sir
With my respects
❤❤❤
If all the altitudes are intersecting at the same point, is it possible to be a scalene triangle?
y+56 or y+96?
The answers are x = 70 and y = 30. We know bc 70 is 35 doubled and this is consistent with the ratio of the base. I hope that that makes sense.
这题有个问题，p点不需要是垂心，是任意一点都一样，即条件多余。
So challenging. I Didn't get it
84÷56=1.5)(35÷1.5=23.33333green 40×1.5=60 purple
84 : 56 = 3 : 2 140 : 40 = 7 : 2
ADP=x CFP=y
x+119 / y+96 = 3 / 2
x+35 / y = 7 / 2
2x+238 = 3y+288 2x = 3y+50
2x+70 = 7y 2x = 7y-70
3y+50 = 7y-70 4y = 120
Purple area = ADP = x = 70
Green area = CFP = y = 30
Very nice breakdown.
{84°A+35DC}+{56EB+40FB}={119°ADC+96°EBFB}={215°ADCEBFB ➖ 180°}=135°ADCEBFB 10^10^35 10^10^5^7 2^5^2^5^5^7^1 1^1^2^1^1^1^1 2^1(ADCEBFB ➖ 2ADCEBFB+1).