It isn't often that I subscribe to a channel after watching one video but that's what I did. I'm a retired math teacher and i feel like I had a similar teaching style to you, sir.
awesome, i smiled when i understood what you meant when you say dividing a sqroot by x is same as dividing by sqroot of x^2. i realised it after thinking about some basic surd rools.
The biggest takeway I get from your videos is a new perspective of algebra. I never thought about using formula manipulation with a term to make it fit within a problem's boundaries. Hence how you took Sqrt(x)/x is = to Sqrt(x)/Sqrt(x^2) and applied it to the problem. It was very abstract from what I'm accustomed to.
6:49.. getting rid of as much as you can... Hmmm that's all I wanted to know 😁😁.. thank you. And if you can please make a video of rules that are applicable every time when solving limits
good day sir ..if you please just try to explain more on the part where you explained saying dividing a square root term by x is like diving that square root term by the square root of x^2
From inspection, something does not look right. Sqr(64*x2+X) at infinite will be 8x+ infinite; take off 8x, and you have infinite. Having said that I cannot see your maths is wrong.
Wow. Always like how you get behind the intuition of the topic first before solving.
the way you solve problems makes it seem way easier to understand than the methods i have been taught. Thank you for the amazing teaching.
It isn't often that I subscribe to a channel after watching one video but that's what I did. I'm a retired math teacher and i feel like I had a similar teaching style to you, sir.
Thank you
Lots of Love and Respect from India... The energy and charisma you bring to your teaching is phenomenal..Keep Making such content..😀😀
Thank you for your kind words.
Well explained.. I couldn't find a better explaination than this.
You are a great teacher; you explain things very well. Thanks!
Thank you for making this clear and easy. I was struggling with a very similar problem, now not only do I know the answer but I also understand why.
My brother prime knows his shit keep up the good work my hero ur an inspiration to many of us
God bless u man! Ur such a good person it makes me wanna cry....
your enthusiasm is contagious
I love your teaching. I don,t have more words:)
The process of finding the limit in this example is so interesting. It makes infinity more comes alive. Thank you
Thank You a lot! I would like to meet teachers like you on my learning path... Keep it up!
My perfect math teacher
You're the best
awesome, i smiled when i understood what you meant when you say dividing a sqroot by x is same as dividing by sqroot of x^2. i realised it after thinking about some basic surd rools.
You have a smart mind ☺️
You are amazing! Your way of teaching is very impressive I found your channel and from now on I am stuck on it all the time
Lemme be honest i enjoy watching you tutorials 😂🎉
Let's keep learning 🔥🔥
Thanks for the video! it really helped me to grasp this stuff
Im still alive and still wanna learn more!
Appreciated. Thank you sir!
Dear sir you are the best.
I love your mode of teaching sir.
You are just too perfect sir any time when i find a challeng i will be running to you🏃♂️.sir you are a solution giver i love you explaination
The biggest takeway I get from your videos is a new perspective of algebra. I never thought about using formula manipulation with a term to make it fit within a problem's boundaries. Hence how you took Sqrt(x)/x is = to Sqrt(x)/Sqrt(x^2) and applied it to the problem. It was very abstract from what I'm accustomed to.
That's a significant observation. I never thought that's what I was doing. I was just looking for a solution. Thank you.
@@PrimeNewtons I love you you made me ace my calc exam !
I'll
You made it look so simple thank you Boss 🙌🙌
I love this guy.....Thank you very much💚
Thanks so much. I'm in year 10 but still managed to understand this . Very good explanations.
I am glad I could help. Thanks for the comment too.
It is how you make this easy for me❤😢, you just saved me days and days of headache...thank you Sir.❤❤ and I promise i won't stop learning ❤
best video I've seen for this concept
+1 subscriber
Thank you I was struggling with infinite limits
❤ cleared my thoughts 💭🎉🎉🎉tnx sir 😊😊
What an amazing teacher!!!
Thank you! U just answered all my questions ❤️❤️❤️
6:49.. getting rid of as much as you can... Hmmm that's all I wanted to know 😁😁.. thank you. And if you can please make a video of rules that are applicable every time when solving limits
wow! you make algebra become more livelyy niceeeee🤯
Simply great teacher , keep on please
You make everything easy kkk. love this
you the best thanks for such a good content
Glad you enjoy it!
amazing video
Thanks!
very well explained. very helpful
YOU HELPED A LOT..
keep up the good work.
Thank u 🙏🙏🙏🙏🙏
You really helping sir
Simply Great!!!
Love this 😍😍😍😍
Thank you!
You're welcome!
You are amazing like seriously thank you so much
Thanks, i was struggling with Limits during my uni 😂
Thank you 🎉❤
This video is really helpful🔥
Where is that heart-shaped button "Love it"!!!? Thank you! Fantastic explanation!
Well explained
Nice one
Thanks very much l have been trying limit for infinity
I didn't even need to know how to solve the problem in this video but you teach very well so I decided to watch anyways
This helped me understand!
I'm glad you found it helpful.
متابع ايءما طريقة ممتازة
Very good in solving
Thank you genius
متابع يشكرك من المغرب
Very good. Thanks!
GOATED!!!!!!!!!!!!!!
Finally... this makes sense
Loves from Bangladesh❤❤❤
Happy New Year.
Thank you so much!!!
thank you sir😁
You're the best
Thanks soo much
You are saving my ass right now, thank you good sir
Thanks Sir
That's nice
lakas!!
life saver
I think the answer is infinity. The square root of 64 is + or - 8. Taking -8 gives 1/0 = infinity. y= sq root 64. y^2 =64. (y-8)(y+8)=0.
What about the negative value if yo sqrt(64) in minute 9:44?
It's a square root function
Square function has range x ≥0
Please can u do the next one on the table of variation
I don't even know what that means. Updated. I googled it. Please email me a problem
good day sir ..if you please just try to explain more on the part where you explained saying dividing a square root term by x is like diving that square root term by the square root of x^2
learning math has become fun (for the first time in my life)
God sent me this video
you look handsome young man = D
From kenya❤I think know I can become professor😂
Why you not substitute the infinity in the solution
🎉 making limit easy 😅
Can you solve a limit on the cube root??
what do I do if its not square root but cube?
Hello sir
I am from India
Reply me
best
I find it interesting that in this case, subtracting one infinity from another infinity results in one sixteenth. 😅
And when x goes to minus infinity what happens?! 😀😉
oral question pretty easy
From inspection, something does not look right. Sqr(64*x2+X) at infinite will be 8x+ infinite; take off 8x, and you have infinite. Having said that I cannot see your maths is wrong.
That's why infinity is dangerous
Sir plz help me this question
Find the Limit of Lim tan7x/14x as x tends to 0
answer is 1/2
You teach well sir but I think you've gone wrong somewhere.You've divided the whole equation by X instead the X is under a square root.
Tried this, wamap said the answer was wrong. Granted this was 2 years ago
This calculation is correct. I'm sure wamap will fix that.
@@PrimeNewtons Considering the fact that the teacher requires us to use wamap, wamap is correct.
Lol. So, what was wamap's answer?
@@PrimeNewtons I don't know as it does not show the answer unless you get it right.
That's unfair to the student. I hope they've fixed it.
1/16
x= + inf
The answer is zero, check it out.