sir, while calculating for the kinetic energy part you have cancelled the terms, i think it can only be cancelled when m1= m2 but in this case m1 is not equal to m2. so we can't cancel it. kindly check that part and please correct me if i am wrong.
At 19:50, we are canceling the 2ab terms of (a+b)^2 and (a-b)^2. Both terms have 2*m1*m2 as the common factor. I forgot to write the masses in these terms. Thank you for identifying.
Thank you sir. I have a question, when we translated our co-ordinate, we converted our problem from 6 DOF to 3 DOF. But we developed another formulation, parallel to r_1 and r_2. If we did translation in that formulation, we would again get 3 DOF. What was the need for formulation with respect to centre of mass vector and that small curly r vector. Thanks once again for great lecture.
The need for re-formulation is to reduce the number of degrees of freedom. In case if the center (CoM) of mass formulation is not capable of reduction of CoM, then there is no need of new formulation.
Why not from the beginning we define the coordinate system such that it's centered at m1 without the need to introduce the center of mass and all the other stuff? ?
At the beginning, we do not know that choosing a COM (center of mass) frame is more easier than otherwise. First we perform our calculations with origin at some arbitrary place. Then repeat the calculations with origin at COM. After doing all the calculations, we discover that COM leads to simplified calculation steps.
The equation (6) is the Lagrangian in the center of mass coordinates. Further continuation is in the next lecture, which is Lecture-22. See at 36 min 42sec of the lecture-22 where we get the equivalent one-body problem. Ultimately we are obtaining the Lagrangian in the center of mass frame of reference. So, what is your question/doubt? I could not understand your question. Lecture #22 th-cam.com/video/A8fExeJY40Q/w-d-xo.html Full Classical Mechanics Playlist th-cam.com/play/PLtUBquogGkRukyAAWOmq2LmQx8Yf9H_3E.html
MSc level Classical Electrodynamics Playlist th-cam.com/play/PLtUBquogGkRv5CME__m2oudBqW3_ffv33.html
MSc level Vector space and Hilbert space for Quantum mechanics Playlist: th-cam.com/play/PLtUBquogGkRuZH23UO-8AWR4dzcu-La8_.html
MSc level Classical Mechanics Playlist th-cam.com/play/PLtUBquogGkRukyAAWOmq2LmQx8Yf9H_3E.html
BSc level Electricity and Magnetism Playlist th-cam.com/play/PLtUBquogGkRu66Kqgs3HsEpHEP6IA8oQ7.html
Best explanation for solving centre force problems , thank you sir
Well explained sir! Thank you
Clearly understood sir
Thank you, sir!
Thanks a lot sir!
sir, while calculating for the kinetic energy part you have cancelled the terms, i think it can only be cancelled when m1= m2 but in this case m1 is not equal to m2. so we can't cancel it. kindly check that part and please correct me if i am wrong.
At 19:50, we are canceling the 2ab terms of (a+b)^2 and (a-b)^2. Both terms have 2*m1*m2 as the common factor. I forgot to write the masses in these terms. Thank you for identifying.
Thank you sir. ✨
Thank you sir!
Thank you Sir.
Very good and we understood well.
Glad to hear that.
Thank you sir.
Thank You Sir
Thankyou sir.
Thank You sir.
Thank you Sir
Very well explained sir. Thank You👍🏻
Best wishes.
Thank u sir❤️❤️
thank you sir
Thankyou sir
Thanks a lot sir❤️
Most welcome.
Nice lecture sir
Thanks for liking.
Thank you, Sir.
Thank you sir. I have a question, when we translated our co-ordinate, we converted our problem from 6 DOF to 3 DOF. But we developed another formulation, parallel to r_1 and r_2. If we did translation in that formulation, we would again get 3 DOF. What was the need for formulation with respect to centre of mass vector and that small curly r vector.
Thanks once again for great lecture.
The need for re-formulation is to reduce the number of degrees of freedom. In case if the center (CoM) of mass formulation is not capable of reduction of CoM, then there is no need of new formulation.
@@ProfSivakumarRajagopalan Thanks Sir
thanku sir
Tnq sir
Sir why can't we. Just use polar coordinates in which there just be r1 and r2 .. So 2 degrees of freedom
Why not from the beginning we define the coordinate system such that it's centered at m1 without the need to introduce the center of mass and all the other stuff? ?
At the beginning, we do not know that choosing a COM (center of mass) frame is more easier than otherwise. First we perform our calculations with origin at some arbitrary place. Then repeat the calculations with origin at COM. After doing all the calculations, we discover that COM leads to simplified calculation steps.
Sir..why you did not translated it directly to the point of centre of mass?
The equation (6) is the Lagrangian in the center of mass coordinates. Further continuation is in the next lecture, which is Lecture-22. See at 36 min 42sec of the lecture-22 where we get the equivalent one-body problem. Ultimately we are obtaining the Lagrangian in the center of mass frame of reference. So, what is your question/doubt? I could not understand your question.
Lecture #22 th-cam.com/video/A8fExeJY40Q/w-d-xo.html
Full Classical Mechanics Playlist th-cam.com/play/PLtUBquogGkRukyAAWOmq2LmQx8Yf9H_3E.html
@@ProfSivakumarRajagopalan Yes sir I have taken the next lecture and got it thank you for response
R Chandrajyoth
SHAKIR KEELAILLAM
PU20054267
V.Manikandan
Senthamizh B
PU20008913
Priyadharshini. M
PU20021311
Akshay K J
V. Nivedhitha
PU20002313
ANJALI CHANDRAN
PU20013201
Arupjyoti pathak
Pu20007303
Vasundaraa devi-PU20020891
PU20020795
M. Anupriya
AMAL K JOSE
PU20012371
Ardra Dhananjayan
PU20020727
sushree monalisha sahu
PU20041733
Shahana Sherin K
PU20008705
Ramzia k
PU20005057
V Kirthi
20PUSN0009
PRANAV.B
PU20002209
Kaviarasu (PU20008733)
PU20047457
S NADARAJ
Debangshu kalita..PU20018505
PU20006171
GOKULAKANNAN
Suneesh k
PU20010087
Swagatika sahu
PU20042205
Valarmathi
PU20001741
PU20003799
KABILAN P
Niranjana Suresh
17380316
BIPIN KUMAR PARIDA
PU20025473
BRILLIA BENNY
PU20013517
Mohanapriyadharshini. R
20374036
KADEEJA ANEESHA T K N
PU20038363
PU20077347
Ayana M A
RINDHUJA TREESA JOHNSON
17380319
K Lakshmi Priya
17380313
Athul P Jose
17380307
BANKERLANG MARNGAR PU20019809
17380325
S. Swathi
Deeksha D
17380309
JINU JOB
PU20059051
Sruthi.V
17380322
Adnan Ashraf
17380301
Athira S
17380306
Salva nourin
17380320
E.Poovizhi
17380317
Thank you Sir .
Thank you sir.
Thank you Sir
thank you sir
Thankyou sir
Thank you sir.
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir
Thank you sir