Introduction to Clampers

แชร์
ฝัง
  • เผยแพร่เมื่อ 29 พ.ค. 2016
  • Analog Electronics: Introduction to Clampers
    Topics Covered:
    1. What is clamper circuit .
    2. Difference between clippers and clampers.
    3. Time constant of capacitor.
    4. Time constant constraint in clamper circuit.
    5. Clamper example.
    Support us through Patreon: / nesoacademy
    Website ► nesoacademy.org/
    Facebook ► goo.gl/Nt0PmB
    Twitter ► / nesoacademy
    Pinterest ► / nesoacademy

ความคิดเห็น • 160

  • @lordnaive
    @lordnaive 7 ปีที่แล้ว +70

    7:17 ....vi=-v
    then vo=-vi-v=0.
    i feel u did wrong. :-(

    • @bhavyanandwani3282
      @bhavyanandwani3282 6 ปีที่แล้ว +4

      Yes..here at the tym of applying kvl negative Vi had taken earlier so not using later at tym of substitutn

    • @ankitburnwal2569
      @ankitburnwal2569 6 ปีที่แล้ว +4

      Had the same doubt. Got it cleared by watching the linked video.
      Thank you so much neso academy.

    • @anuj6386
      @anuj6386 6 ปีที่แล้ว +1

      throught the episode ,while operation u said clipper ckt to clamper cky

    • @raghupatrunishashank7388
      @raghupatrunishashank7388 5 ปีที่แล้ว

      Yeah got cleared with same doubt

    • @taranisre3672
      @taranisre3672 3 ปีที่แล้ว +1

      @@ankitburnwal2569 link bro

  • @VersatileAnthem
    @VersatileAnthem 4 ปีที่แล้ว +12

    so far the best explanation because you showed through KVL or mathematically.Thats why easy to understand.

  • @alimuftah2716
    @alimuftah2716 7 ปีที่แล้ว +19

    you make clampers easy to me .. very thankful to you

  • @vyshnavdurgapu3096
    @vyshnavdurgapu3096 3 ปีที่แล้ว +9

    Oh shit I wasted my time reading other books to understand this
    This is way simple and so understanding

  • @amanagarwal8295
    @amanagarwal8295 3 ปีที่แล้ว +2

    Very useful course, thanks for helping us .

  • @priyanshnagar608
    @priyanshnagar608 6 ปีที่แล้ว +2

    Bro you do great job...i love your videos easily understanding..helpful..keep making many more interesting videos...

  • @sefalipatel3592
    @sefalipatel3592 3 ปีที่แล้ว +6

    Your explanation was really helpful.
    But I would like to add that practically there should be some voltage drop across the diode. So output signal will change a little bit.

  • @supersonic6734
    @supersonic6734 6 ปีที่แล้ว +1

    Well explained.. thank you very much sir

  • @SiddheshBorkar1
    @SiddheshBorkar1 7 ปีที่แล้ว +2

    very nice video! helped me understand clampers :)
    thanks a ton! :) :)

  • @myadamharshitha4519
    @myadamharshitha4519 5 ปีที่แล้ว +1

    Thank u. very good explanation in detail

  • @12_g_h
    @12_g_h 6 หลายเดือนก่อน

    sir , you done a great job in past . your videos are very helpful till today date .

  • @AndreSonsOfSamael
    @AndreSonsOfSamael 7 ปีที่แล้ว +3

    Thank you! great video! Subscribed :)

  • @shreyanbanerjee6834
    @shreyanbanerjee6834 6 ปีที่แล้ว

    sir you are a fabulous teacher

  • @yarasinikitha8972
    @yarasinikitha8972 4 ปีที่แล้ว +1

    THANKU SIR, it is very helpful

  • @abuelgasimahmed1723
    @abuelgasimahmed1723 6 ปีที่แล้ว

    thank u so mush , I hope u have a great day sir .

  • @dharmikkids7397
    @dharmikkids7397 4 ปีที่แล้ว +5

    Your channel is bringing an evolution in indian technology.

    • @sarthakchoudhury5237
      @sarthakchoudhury5237 2 ปีที่แล้ว +1

      Jyada ho gya 🤣🤣

    • @dharmikkids7397
      @dharmikkids7397 2 ปีที่แล้ว

      @@sarthakchoudhury5237 bhai bhai bhai 😂

    • @dharmikkids7397
      @dharmikkids7397 2 ปีที่แล้ว

      @@sarthakchoudhury5237 lekin explanation best and precise hota h enka m to college me esise pdhta tha exam ke ek din pehle

    • @sarthakchoudhury5237
      @sarthakchoudhury5237 2 ปีที่แล้ว

      @@dharmikkids7397 hn bhai sahi mein lekin engineering sucks and fucks 🤣🤣🤣

    • @dharmikkids7397
      @dharmikkids7397 2 ปีที่แล้ว

      @@sarthakchoudhury5237 ya bruh engineering ki mkb

  • @bhajarangabali430
    @bhajarangabali430 3 ปีที่แล้ว

    Super explaination yaaar,

  • @ajitjoshi6419
    @ajitjoshi6419 5 ปีที่แล้ว +3

    Thank you sir

  • @ronniesam9941
    @ronniesam9941 4 ปีที่แล้ว

    Excellent sir

  • @tirkeyk2923
    @tirkeyk2923 7 ปีที่แล้ว

    great video.☺

  • @philipligthart2435
    @philipligthart2435 4 ปีที่แล้ว

    great video

  • @balajisatrasala6535
    @balajisatrasala6535 5 ปีที่แล้ว +3

    Actually in the _ve half the capacitor is already charged so it has to discharge in the _ve half cycle right?

  • @rahulbhardwaj4380
    @rahulbhardwaj4380 5 ปีที่แล้ว +4

    isnt the direction of current across the resistance in the negative half wrong? shouldn't it be in the direction as indicated by the round arrow in the centre..and thus V0 be negative

  • @niteshmeena1959
    @niteshmeena1959 ปีที่แล้ว

    Thank You Sir 😊

  • @pradhyumnapradhyu7692
    @pradhyumnapradhyu7692 3 ปีที่แล้ว

    Awesome man

  • @sathishkumary3181
    @sathishkumary3181 4 ปีที่แล้ว

    Tq sir..... it's very clear

  • @alterguy4327
    @alterguy4327 6 ปีที่แล้ว +2

    *Thanks*

  • @shankarp9029
    @shankarp9029 3 ปีที่แล้ว

    Thanks a million,

  • @vaishnabiswas345
    @vaishnabiswas345 5 ปีที่แล้ว +1

    can we replace a capacitor charged upto 10 V by an uncharged capacitor with a 10 V battery in series?

  • @jeffersonnoble8921
    @jeffersonnoble8921 7 ปีที่แล้ว

    thank you

  • @HamzaAli-mk9tx
    @HamzaAli-mk9tx 7 ปีที่แล้ว +1

    what will be PIV of each diode in tripler and quadrupler corcuits?? and why??

  • @Harry001by7
    @Harry001by7 5 หลายเดือนก่อน

    What happens if we introduce a series resistor in the input side and for time varying square wave input signal, how to calculate R and C (if the input signal frequency is around 1MHz how the circuit behaves and what type of diode we have to chose ?).

  • @gehadelhawary5485
    @gehadelhawary5485 4 ปีที่แล้ว

    Thank you

  • @sagarjain4128
    @sagarjain4128 2 ปีที่แล้ว +3

    Sir, Generally at resistor there is voltage drop (so while using KVL we take - sign)
    then why sir you took +ve sign for load resistor ? ( does it mean that across load resistor potential increases?

    • @amankumaaryadava1627
      @amankumaaryadava1627 2 ปีที่แล้ว

      When we use tha mesh analysis then we first offer polarity to tha resistor according to direction of current in such way that first terminal of resistor taken as positive and second terminal will be negative .
      Now while moving through loop its our choice whether we take sign of first terminal of battery and resistor or sign of second terminal of battery and resistor .

  • @ashishbhaskar7609
    @ashishbhaskar7609 ปีที่แล้ว

    Thanku sir

  • @shrenikmane2633
    @shrenikmane2633 6 ปีที่แล้ว +1

    Nice.

  • @SifatAhmed144
    @SifatAhmed144 7 ปีที่แล้ว

    could you place tell me why did you take Vc as negative in KVL while Capacitor is charging??

  • @mahmoudmosleh749
    @mahmoudmosleh749 7 ปีที่แล้ว +2

    very nice, but can you solve problems with numbers? would be great if you did.

  • @KirkHammer-fj2of
    @KirkHammer-fj2of 6 ปีที่แล้ว +43

    Wow man , where were you all this time ??????????????????????

    • @amlanpanda3122
      @amlanpanda3122 11 หลายเดือนก่อน +4

      Chole baat Raha tha

    • @haquepnt8207
      @haquepnt8207 8 หลายเดือนก่อน

      😂

    • @ansariaburehan263
      @ansariaburehan263 29 วันที่ผ่านมา

      Chote aloo bade aloo alag kar raha tha

  • @sagarjain4128
    @sagarjain4128 2 ปีที่แล้ว

    East and West Neso is Best!!😎😎

  • @deveshagarwal2056
    @deveshagarwal2056 3 ปีที่แล้ว +4

    Sir pls give these slides as pdf
    it will be a great source of notes

  • @lx33941
    @lx33941 4 ปีที่แล้ว

    When input changes it's direction.. wont capacitor will change its polarity as capac oppose change of polarity???

  • @lovepaikra9911
    @lovepaikra9911 5 ปีที่แล้ว

    What will be output, if we reverse the direction of diode in this circuit with given input....

  • @nitinchaudhary1304
    @nitinchaudhary1304 7 ปีที่แล้ว +1

    How does the peak value change?

  • @paulboro5278
    @paulboro5278 6 ปีที่แล้ว +3

    are you sure you have applied KVL properly in the 2nd half?

    • @ubuandeyelbme
      @ubuandeyelbme 6 ปีที่แล้ว +5

      I had a challenging time with that as well. If you redraw the circuit it might make more sense. It seemed to for me at least. I put the capacitor underneath the source:
      __________________ +
      | | |
      | | |
      ~ V RL
      | | |
      = | |
      |_______|________|__ --
      It's basically just an output in parallel with the battery voltage + alternating source. Don't know if that answers your question regarding KVL or not.

  • @anchordeepikaojha5891
    @anchordeepikaojha5891 7 ปีที่แล้ว

    sir please give example if time constant is very less than time period as it is asked in gate 2017

  • @amantiwari8316
    @amantiwari8316 8 หลายเดือนก่อน +1

    You had taken tau (time const) = 0 as R=0 but we've asummed that tau > T/2 then it contradicts our assumption.

  • @palabandlababu5561
    @palabandlababu5561 3 ปีที่แล้ว +1

    (1)Sir if the capacitor charges within the time t/2, then it should discharge within t/2??
    (2) you have assumed that the time constant is much more compared to half of the time period then how the capacitor charges to V volts for the half cycle???

    • @BADASSBLADE
      @BADASSBLADE 2 ปีที่แล้ว

      Capacitor gets charged 99% in mean time but till the time reaches T the capacitor is charging betn 99-100 so we have to assume it has charged

  • @prof_as
    @prof_as 5 ปีที่แล้ว +3

    at 6:55 why the polarity of the output voltage Vo is not changing

  • @rishabsud7535
    @rishabsud7535 6 ปีที่แล้ว +1

    How did u apply kirchhoff's law for T/2 to T ??

  • @sagarjain4128
    @sagarjain4128 2 ปีที่แล้ว

    Why will current flow in downward direction across load resistance when you have the path anticlockwise with red pencil. I guess it should be in upward direction.
    kindly tell. See at 6:30

  • @thebrg
    @thebrg 2 ปีที่แล้ว

    Nice 👍 😊😊😊😊👍

  • @merinmaria
    @merinmaria 5 ปีที่แล้ว

    How does RMS remain same wen peak value changes?

  • @logicinsight
    @logicinsight 6 ปีที่แล้ว

    sir....if capacitor charges upto vm then while reversing the....supply voltage capacitors polarities must be revesed....then how? 2vm comes....correct me if iam wrng..

    • @AAA-kt6ve
      @AAA-kt6ve 6 ปีที่แล้ว

      pankaj prasad my teacher told you have to keep the capacitor polarity same even if u are giving the negative input

  • @abhinavpandey3356
    @abhinavpandey3356 6 ปีที่แล้ว

    How we have maintain the condition that tau is greater than t/2

  • @neerajgobari9748
    @neerajgobari9748 5 ปีที่แล้ว

    what will be the output waveform if time const

  • @justinmyth4980
    @justinmyth4980 2 ปีที่แล้ว

    In the ladt video clipper in short circuit of a diode the output voltage was equal toh the voltage passing through it wherease in this video output voltage is 0. 4:34

  • @9430943732
    @9430943732 7 ปีที่แล้ว

    sir why is RMS value remains same?

  • @vgautamraju4660
    @vgautamraju4660 5 ปีที่แล้ว

    Function of tou in both cycles

  • @rafiya8522
    @rafiya8522 3 ปีที่แล้ว

    I have a doubt. The current flows through the circuit during the first half cycle. Then why the output voltage becomes 0 and how.?? Kirchoff's law is not the same for the positive and negative half-cycles.

  • @abdulsami5843
    @abdulsami5843 6 ปีที่แล้ว

    at 5.08 how is Vc negative while the polarity you have made shows positive ?

    • @ubuandeyelbme
      @ubuandeyelbme 6 ปีที่แล้ว

      He's using Kirchoff's Voltage Law (KVL). Vc is negative in his equation (even though it shows positive in his circuit) because at that point, when the diode is forward biased, all of the voltage is on the capacitor, so Vin = Vc and so Vin - Vc = 0. This is because KVL states that the sum of all the voltages in a closed loop circuit will equal 0.

  • @samapanbhadury6228
    @samapanbhadury6228 7 ปีที่แล้ว +1

    Time constant is zero, in case of zero resistance. So in this circuit, how does the condition, tao>>T/2 hold?

    • @amanraj-fj2cr
      @amanraj-fj2cr 7 ปีที่แล้ว +1

      same quest. bro

    • @shakilabano840
      @shakilabano840 6 ปีที่แล้ว

      SAMAPAN BHADURY since tau is 0, the capacitor will be immediately charged to V volts.

  • @sudarsanareddy.k2337
    @sudarsanareddy.k2337 5 ปีที่แล้ว

    Tq

  • @zeeshankazi6382
    @zeeshankazi6382 7 ปีที่แล้ว +1

    Vrms=Vo/root(2) if Vo changes, Vrms is also supposed to change right ?

  • @ranjantripathy5932
    @ranjantripathy5932 6 ปีที่แล้ว +1

    Sir how rms will be same since the peak value of signal is changed

    • @dakbabu
      @dakbabu 4 ปีที่แล้ว

      Check the o/p of the signal, here we're just shifting the signal, there's no change in the magnitude to the overall signal.

  • @khushir956
    @khushir956 4 ปีที่แล้ว +1

    won't the capacitor change it's polarity in the second half cycle?

    • @Crusader2
      @Crusader2 4 ปีที่แล้ว

      it will change

  • @SHREEdharSimple
    @SHREEdharSimple 6 ปีที่แล้ว +1

    6:14 why Cap polarities not getting reversed?

    • @generalvegetal3049
      @generalvegetal3049 5 ปีที่แล้ว +4

      it has already charged in +ve half cycle, in -ve half cycle it will take more time to discharge because of the resistance(note that we have chosen the resistance and capacitance such that its time constant is much greater than the time period @ 2:10 ).

  • @halafeleccontrolengineering
    @halafeleccontrolengineering 6 ปีที่แล้ว

    ur lecter is amessing to be countioue i am halofom from ethiopia....

    • @singh_mk
      @singh_mk 5 ปีที่แล้ว

      can u understand hindi?

  • @ziqi711
    @ziqi711 5 ปีที่แล้ว +3

    Hi Sir, thank you so much for your explanation! However, I am still confused why τ is greater than t/2...May I ask why is it so?

    • @meghjitmajumder3468
      @meghjitmajumder3468 4 ปีที่แล้ว +1

      Because during half of time-period of the input signal,capacitor is going to discharge(during which cycle that depends upon the diode orientation though)

    • @vicallday3325
      @vicallday3325 4 ปีที่แล้ว +2

      Capacitor will be very well charged if Tau >> t/2 which would allow the capacitor to have its full effect at the output

    • @kishorkhatke9036
      @kishorkhatke9036 4 ปีที่แล้ว +1

      It seems like charging time of capacitor is very small as compared to discharging time of capacitor

  • @HussainSaro
    @HussainSaro 5 ปีที่แล้ว

    2nd loop.. KVL may be wrong.. if you don't mind clear it

  • @miraculoustales3331
    @miraculoustales3331 5 ปีที่แล้ว

    How to apply kvl

  • @riteshchaudhary1935
    @riteshchaudhary1935 7 ปีที่แล้ว

    Sir if the peak value is changing then how the RMS remain same ???

  • @ranjankumar-cz2jt
    @ranjankumar-cz2jt 6 ปีที่แล้ว

    what if tau < T/2 ?

  • @pmk2737
    @pmk2737 4 ปีที่แล้ว

    Peak to peak remain same is it true????

  • @jyotirmoybharali5232
    @jyotirmoybharali5232 3 ปีที่แล้ว +2

    I have one doubt. At the first half cycle, you defined polarity of capacitor as the input voltage, that is fine. But in the next half cycle, the polarity of input voltage got changed. So according to that, the polarity of the capacitor should change. Then why it did not change? Plz clear my doubt.

    • @va11bhav_rana
      @va11bhav_rana 2 ปีที่แล้ว

      bcuz time constant is very high,

  • @eggxecution
    @eggxecution 4 ปีที่แล้ว

    why did you open circuit?

  • @adityamankar8910
    @adityamankar8910 6 ปีที่แล้ว

    As Tau=0 the capacitor will also discharge in 0 time when diode will be reverse biased. Can't get it properly

    • @AAA-kt6ve
      @AAA-kt6ve 6 ปีที่แล้ว

      in reverse bias condition capacitor doesn't get discharged...it is acting as a battery in negative half that is why we get some output.

  • @successeasy11
    @successeasy11 6 ปีที่แล้ว

    Sir please write in big size b/c it no visible

  • @amitkumarsingh5822
    @amitkumarsingh5822 10 หลายเดือนก่อน

    I think that by clamping a signal RMS value will change

  • @joynobtasnim16
    @joynobtasnim16 10 หลายเดือนก่อน

    +Vi - Vc =0. Here can you plz explain why it is -Vc, not +Vc....according to KVL

  • @bituphukon6954
    @bituphukon6954 4 ปีที่แล้ว +1

    Sir why we take T(taw) >t/2

    • @meghjitmajumder3468
      @meghjitmajumder3468 4 ปีที่แล้ว +1

      Because during half of time-period of the input signal,capacitor is going to discharge(during which cycle that depends upon the diode orientation though)

  • @litcode702
    @litcode702 5 ปีที่แล้ว

    In the first half time constant was zero. Then how it can be greater than T/2??

    • @ayonbhuiyan2035
      @ayonbhuiyan2035 5 ปีที่แล้ว

      The condition is applied when the diode is nonconducting. According to this video the diode was nonconducting at second cycle with a finite time constant.There is nothing to be worry about first half cycle.

  • @sarveshshimpi3718
    @sarveshshimpi3718 6 ปีที่แล้ว

    why is tau>>T/2?

  • @goodguy7883
    @goodguy7883 4 ปีที่แล้ว

    What if it is a sine wave

  • @akashkumarsingh640
    @akashkumarsingh640 6 ปีที่แล้ว

    How should take this voltage intially= V

  • @sayandey1478
    @sayandey1478 6 ปีที่แล้ว

    rms should be root 2 times v.......right?..it cant be the same

  • @j4Naga
    @j4Naga 8 ปีที่แล้ว

    when does capacitor discharges?

    • @dakbabu
      @dakbabu 4 ปีที่แล้ว

      it discharges slightly during the -ve half cycle.

  • @sumanmahato9294
    @sumanmahato9294 6 ปีที่แล้ว

    7:01..
    How do you consider the direction of current in load resistance to be opposite to that of input voltage ?

    • @ubuandeyelbme
      @ubuandeyelbme 6 ปีที่แล้ว

      The direction of current through the load resistor should switch technically speaking, but I think it's so negligible because of the charge already on the capacitor from when the diode is forward biased that he doesn't include it because he's teaching from an "ideal" circuit. The circuit will do the exact same thing without a load resistor connected implying that the current is next to nothing when the input voltage is opposite. Basically when the diode is reverse biased we're almost literally just measuring across a battery in series with an oscillating source because the capacitor technically doesn't discharge. But you're right: in the real world the direction through the load resistor will change directions. If you lower the load resistance significantly in the "ideal" circuit then then the current through the load resistor switching directions becomes much more prominent.

  • @omkumarsingh4194
    @omkumarsingh4194 3 ปีที่แล้ว +1

    Agar input waveform sinusoidal hua to , output to st line hona chahiye
    Output bhi sinusoidal kyu ho ja Ata hai
    Koi Bata do plzz

  • @Abhisheksharma-eq4vj
    @Abhisheksharma-eq4vj 5 ปีที่แล้ว

    There is confusion in taking charge on capacitor

  • @sayanchakraborty3114
    @sayanchakraborty3114 2 ปีที่แล้ว

    TAU must be greater than t/2 but in the (+) half cycle TAU =0 , ????

  • @armed3719
    @armed3719 3 ปีที่แล้ว

    The negative half cycle is given wrong ( revered baised)

  • @motivationalforupsc916
    @motivationalforupsc916 9 หลายเดือนก่อน

    Sur note

  • @bvspragathiengineersadda1116
    @bvspragathiengineersadda1116 5 ปีที่แล้ว

    Good Explanation
    #BVSPRAGATHI

  • @nitesh7546
    @nitesh7546 5 ปีที่แล้ว

    Please detail why time constant is greater than time period..?😅

    • @alireza2470
      @alireza2470 5 ปีที่แล้ว

      τ should be greater than T, otherwise the capacitor will discharge sooner than the period and the circuit will not function as intended

  • @ayushjain1083
    @ayushjain1083 4 ปีที่แล้ว

    Wish my cheli happy birthday

  • @muhammadishtiaq9711
    @muhammadishtiaq9711 4 ปีที่แล้ว

    Capacitor block the DC if I am wrong crocet me

  • @HardikJain_YT
    @HardikJain_YT ปีที่แล้ว

    2:11 causes 2:58

  • @rishabhpatel3340
    @rishabhpatel3340 2 ปีที่แล้ว +1

    Bike race pro ka intro song h 😂😂

  • @vincentburdeos6152
    @vincentburdeos6152 3 ปีที่แล้ว

    That's KVL?