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I got 5u^2 in the extension is that right ?
Yh
sir at 33:46 can you explain why your height is 6 and not 3
the x coordinate is 6 and the height is horizontal
@@callumsims1431 yeah so woudnt 3 - - 3 be 6
Im confused, dont you only use 1/2 b*h when theres a right angle in the triangle? surely you should be using 1/2abSinC for this
As long as the base and height are perpendicular, you can use this formula! www.mathsisfun.com/algebra/trig-area-triangle-without-right-angle.html Look at the first example here.
Your acc wonderful
I got 5u^2 in the extension is that right ?
Yh
sir at 33:46 can you explain why your height is 6 and not 3
the x coordinate is 6 and the height is horizontal
@@callumsims1431 yeah so woudnt 3 - - 3 be 6
Im confused, dont you only use 1/2 b*h when theres a right angle in the triangle? surely you should be using 1/2abSinC for this
As long as the base and height are perpendicular, you can use this formula! www.mathsisfun.com/algebra/trig-area-triangle-without-right-angle.html Look at the first example here.
Your acc wonderful