Trick 35 - Find the Day of Any Date II Calendar Problems II Complete Video II Concept & Examples
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- เผยแพร่เมื่อ 14 มิ.ย. 2017
- Watch this video to learn an easy method to find the day of any past or future date in JUST 15 SECONDS.....Amazing isn't it?
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day of week kaise nikalte hai
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Why my maths teachers can't be this patient while explaining..?!
Cause not every student understands this. They will be more confused :))
Thanks sir for u valuable lessons It's made easy to solve this type of questions I spent 20- 30 minutes to solve the 1 st one but after practicing 2 ,3 questions now I am able to solve this in just 2-3 minutes 🙏❤️🙏❤️🙏
Understood the concept extremely fast. Thank you so much, sir. Very well explained 😊😊
Way of explaining the concepts is awesome!
The video is very helpful for me. many many thanks to you sir. but I have a question.
when you divide a century by 4, you minus by 1 of the result . you explained that 100 is not a leap year.
my question is should we minus by 1 if the year is not divisible by 400 ??
Just fantastic. Very clear explanation. Thank you very much
Very good explanation, this the only video I find without a table to be remembered, your work is appreciated sir, keep on doing the same
Exactly ! because he explains the logic of it. So you don't need to memorize figures you can get them by yourself 🤗
The best explanation. I was so confused regarding this topic bt you explained it so well. Thank you so much for clearing my doubt.
Gd afternoon Sir! Though it is complicated, you explain so well,any lay man can understand. All d best. Tc.
WhatsApp 9896369963 for PDFs of short tricks
Thank you sir you literally saved me bcz after 3 days I had my exams and I was really scared but after watching your video I understood the concept very well
Very good explanation sir ! Saw a similar question come in my bitsat mock test and when i saw it i got worried , though i am not worried anymore because of you! Thank you sir. 😄
The method is good. Thanks for posting. I would like to understand the concept behind the odd days. I mean, the concept behind the circle ( 0-Sun, 1-Mon, 2-Tue ....). Why is 0 always a Sun and 1 always a Mon. It would be great help if you can provide an explanation behind this.
0 means 7 . When 7 is divided by 7 the remainder is 0 .
0=sunday is a serial number.
I use 0 as saturday and use codes January as 0 February as 3 and so on. I can explain to you how January is 0 feb is 3 march 3 April 6 etc.
Odd days denote the number of days after completing any number of week cycles. We could say that *A week starts on Monday and ends on Sunday by this concept.* When you say year 2000 has 0 odd days it means by the end of the year, an exact number of week cycles has been completed. Which tells us that December 31 is a Sunday. A new week starts on 1 Jan 2001 (1odd day= Monday.) By the next day there would be 2 odd days which means it's the second day of a new week therefore Tuesday and so on.
1.) I simply pre-memorized all 366 possible dates as a value from -3 to 3.
2.) Then I just add that to one of the 4 possible century codes of 2,0,-2, or 3 (7 possible century codes for Julian from -3 to 3) and finally,
3.) Add that to a pre-memorized value for each of the 100 years from 00 to 99.
For example, my birthdate of March 19, 1982 goes:
-2+3-3=-2 so Friday! Or shortcutting, I just cancel the 3 and -3, and -2 is Friday! The fastest way to do this is to pre-memorize all 100 year values from 00 to 99. Then I just add that to the century code and finally add that to a pre-memorized value for each of the possible 366 dates (these 3 values can be added together in any order you like). For example, June 15, 2012 would simply be:
2+2+1=5, so Friday!
June 15 always has a value of 2 (pre-memorized)
2000's has a century code of 2
and,
year 12 always has a value of 1 (pre-memorized)
2+2+1=5, Friday!
Anytime leapyear happens just subtract one from the answer for January or February only, all other months stay the same!
I calculate any day of the week using my method in less than a second, almost instantly to 2 seconds tops if I'm thinking a bit. I do both the Julian and Gregorian calendars in both AD and BC infinitely into the past or the future.I do other cool tricks that aren't heard of very often, for example since this calendar math can be viewed as just a simple addition problem, we can also solve for a missing value using subtraction! For example, if we already know the day of the week to be Friday for example, we can solve for a possible month/months or even a date from 1 to 31 or even a possible year or century.
Example: Which month or months did Friday the 13th fall on in 1899?
1899 was a Tuesday year (-2+4=2) or (5-3=2). So, Tuesday was the 10th since 3 days later was Friday the 13th.
So, 2+13+x=5 (Friday)
x=4 because 15+(-10)=5
-10+14=4
Mod7 arithmetic
Only January and October had a month code of 4 😁. So it only happened twice that year, in January and in October. Also we can say more intuitively that since 1899 was a Tuesday year, and Friday being 3 days later, which month/months had the Doomsday of 3,10,17,24,31? and obviously that is only January and October.
If the question changed to what were all of the Fridays in January and October for example in 1899?
We can say "the 6th, 13th, 20th, and 27th"
If someone were to instead ask for example on Friday the 13th from 1883 to 1900 what year/years did that happen?
We can say "only in 1893 and 1899"
In this situation we just needed to find the missing year code of (4 or -3) and only 93 and 99 have that year code in that date range. Likewise, we could have instead solved for the century 😉 also if already given a year.
Great man !!
can you share pre memorized values.
i'm very excited
Can you please teach me your technique
I'll be grateful forever.
Sir i dint understood ua method,, aggarwalz sir tricks also much complicated , plz explain once
@@surajmahale4187 Grab any common year (not a leap year) calendar you can write on. Starting on January 1 write -2, then January 2 write -1, then January 3 write 0
The pattern goes -2,-1,0,1,2,3,-3 repeat all the way until December 31 which has a value of -2.
Century Codes: 1600's, 2000's, 2400's and all multiple of 4 centuries: code 2
1700's, 2100's, 2500's and so on code 0
1800's, 2200's, 2600's and so on code 5 or -2
1900's, 2300's, 2700's and so on code 3
Year codes:
*00 code 0
01 code 1
02 code 2
03 code 3
*04 code 5 or -2
05 code 6 or -1
06 code 0
07 code 1
*08 code 3
09 code 4 or -3
10 code 5 or -2
11 code 6 or -1
*12 code 1
13 code 2
14 code 3
15 code 4 or -3
*16 code 6 or -1
17 code 0
18 code 1
19 code 2
*20 code 4 or -3
21 code 5 or -2
22 code 6 or -1
23 code 0
*24 code 2
25 code 3
26 code 4 or -3
27 code 5 or -2
*28 code 0
29 code 1
30 code 2
31 code 3
*32 code 5 or -2
33 code 6 or -1
34 code 0
35 code 1
*36 code 3
37 code 4 or -3
38 code 5 or -2
39 code 6 or -1
*40 code 1
41 code 2
42 code 3
43 code 4 or -3
*44 code 6 or -1
45 code 0
46 code 1
47 code 2
*48 code 4 or -3
49 code 5 or -2
50 code 6 or -1
51 code 0
*52 code 2
53 code 3
54 code 4
55 code 5 or -2
*56 code 0
57 code 1
58 code 2
59 code 3
*60 code 5 or -2
61 code 6 or -1
62 code 0
63 code 1
*64 code 3
65 code 4 or -3
66 code 5 or -2
67 code 6 or -1
*68 code 1
69 code 2
70 code 3
71 code 4
*72 code 6 or -1
73 code 0
74 code 1
75 code 2
*76 code 4 or -3
77 code 5 or -2
78 code 6 or -1
79 code 0
*80 code 2
81 code 3
82 code 4 or -3
83 code 5 or -2
*84 code 0
85 code 1
86 code 2
87 code 3
*88 code 5 or -2
89 code 6 or -1
90 code 0
91 code 1
*92 code 3
93 code 4 or 03
94 code 5 or -2
95 code 6 or -1
*96 code 1
97 code 2
98 code 3
99 code 4 or -3
@@surajmahale4187 Grab any common year (not a leap year) calendar you can write on. Starting on January 1 write -2, then January 2 write -1, then January 3 write 0
The pattern goes -2,-1,0,1,2,3,-3 repeat all the way until December 31 which has a value of -2.
Century Codes: 1600's, 2000's, 2400's and all multiple of 4 centuries: code 2
1700's, 2100's, 2500's and so on code 0
1800's, 2200's, 2600's and so on code 5 or -2
1900's, 2300's, 2700's and so on code 3
Year codes:
*00 code 0
01 code 1
02 code 2
03 code 3
*04 code 5 or -2
05 code 6 or -1
06 code 0
07 code 1
*08 code 3
09 code 4 or -3
10 code 5 or -2
11 code 6 or -1
*12 code 1
13 code 2
14 code 3
15 code 4 or -3
*16 code 6 or -1
17 code 0
18 code 1
19 code 2
*20 code 4 or -3
21 code 5 or -2
22 code 6 or -1
23 code 0
*24 code 2
25 code 3
26 code 4 or -3
27 code 5 or -2
*28 code 0
29 code 1
30 code 2
31 code 3
*32 code 5 or -2
33 code 6 or -1
34 code 0
35 code 1
*36 code 3
37 code 4 or -3
38 code 5 or -2
39 code 6 or -1
*40 code 1
41 code 2
42 code 3
43 code 4 or -3
*44 code 6 or -1
45 code 0
46 code 1
47 code 2
*48 code 4 or -3
49 code 5 or -2
50 code 6 or -1
51 code 0
*52 code 2
53 code 3
54 code 4
55 code 5 or -2
*56 code 0
57 code 1
58 code 2
59 code 3
*60 code 5 or -2
61 code 6 or -1
62 code 0
63 code 1
*64 code 3
65 code 4 or -3
66 code 5 or -2
67 code 6 or -1
*68 code 1
69 code 2
70 code 3
71 code 4
*72 code 6 or -1
73 code 0
74 code 1
75 code 2
*76 code 4 or -3
77 code 5 or -2
78 code 6 or -1
79 code 0
*80 code 2
81 code 3
82 code 4 or -3
83 code 5 or -2
*84 code 0
85 code 1
86 code 2
87 code 3
*88 code 5 or -2
89 code 6 or -1
90 code 0
91 code 1
*92 code 3
93 code 4 or 03
94 code 5 or -2
95 code 6 or -1
*96 code 1
97 code 2
98 code 3
99 code 4 or -3
Such a great video, I was searching for the same method for so long when I got your video sir ❤
Now the topic is clear 🔮
Thanks a lot sir 😊❤
All this in one take, with such great explanation skills, is truly commendable.
Keep up the great work sir.
😄
@Fashion Hub kaha pr?
Thanks a lot
Shit, if you were my math teacher during my highschool days. I would have secured some good marks. 😂
Such a wonderful video I was searching from many years
Easly understood sir ..nice way to explain the concepts...
Thanks sir. You cleared the Concept. It's better to understand the Concept rather than going for shortcuts.
Good one i got a clear understanding of the concept, god bless this channel
This explanation is very clear, perfect, thanks for your patience.🤗
But I have a question : what is the use of knowing what day was what date ?
😉😉
Come and attempt a competitive exam in India....you would require no answer for your question 😄😆
Lol we have this in our exams moreover isn't it a fun skill to have anyway?
@@sureshaggarwal 😀
I had no idea of odd days and even days before ... Now I got the clear idea.... Good explanation sir
Sure this works, but here's a simpler method that works for years 1900-2099. You only track one number throughout this method which makes it easy to do quickly in your head. The key is doing the mod 7 (remainder after dividing by 7), you can apply it any time to any number after step 2 through the calculation.
1) Subtract 1900 from the year.
2) multiply that number by 1.25 (add a quarter), round down, if its a leap year subtract 1. Reduce to mod 7.
3) walk through the completed months of the target year and add the mod 7 for that month (31 days=3, 30 days=2...). Reduce to mod 7.
4) add the target day of the month (or the mod 7 of it) and get the mod 7 for the sum. This is your day of the week (0=Sun, 1=Mon,.. 6=Sat).
Here's an example for a date later this year, 2019-06-21.
1) 2019-1900 = 119
2) 119 + 29.75 = 148 (rounded down), 148 mod 7 = 1
3) 1 + 3 (Jan) + 3 (Mar) + 2 (Apr) + 3 (May) = 12, 12 mod 7 = 5
4) 5 + 21 = 26, 26 mod 7 = 5, Answer is 5 - Friday (if you prefer, 5 + (21 mod 7) or 5+0)
For 1960-03-01
1) 60
2) 60 + 15 - 1 (leap year) = 4 (after mod 7)
3) 4 + 3 (Jan) + 1 (Feb) -> 1 (after mod 7)
4) 1 + 1 = 2 = Tuesday
This method works because of 2 factors. Jan 1, 1900 is a Monday (day 1 on date 1), and in that year span there are leap years every 0.25 years so you can calculate your "odd days" with the multiply by 1.25 trick. The other advantage to this method is that it doesn't require any memorization other than the method itself and the number of days per month.
I had @Sunanda Alapati reply to my comment, but I can't see it anywhere other than my notification. The question was about January 1, 2099 coming up as a Thursday using my method and Sunday using the video method. The correct day of the week is Thursday, I get that with either method, I don't know why you are getting Sunday. For the video method, you have no odd days for the century, 122 odd days for the year (74 normal years, 24 leap years) and 1 more day for the 1st. That leaves a 4 as the remainder which is Thursday.
@Sunanda Alapati by the video method :
2099
2000 = 0 odd day
98 = 24x2(98/4*2odd days for leap year) + 74(1odd day for normal year)= 48+74 = 122
@ 122/7 odd day = 3odd days .
Jan 1 = 1odd day ..
i.e; 3odd day + 1odd day = 4odd day = Thursday
---- SOLUTION BY VIDEO METHOD
you made the concept so clear, thank you sir i understood the calendar problems :)
Very helpful. Concise explanations and straight to the point with no background music. Just plain mathematics. Love it.
When i watched this vdo immediately i subscribed your channel. Then i wanted to know whether you are still making vdo s or not. So i went through your channel and saw your recent posts. It made me very happy because the world needs the teacher like you. I’m highly impressed by the way you make clear the concept. You are a real and true teacher. Please continue teaching online. The learners from abroad too can benefit from you.Thank you and best of Luck.
Sir I liked the video very much. The explanation was amazing , I learnt this trick after watching this video two times. Please upload more interesting tricks .
Thank You
Sir actually I was a fan if the channel dear sir and there I found out the same trick as here but was not able to understand it now by chance I came across this channel and now I was able to understand that trick. Thank you sir from the bottom of my heart
It is really very helpful sir. thank u so much
Can u please make our CSAT preparation easy by solving the PYQ by using easy tricks ❤️🙏❤️
I found exactly what I needed. Those videos with month codes were frustrating, but this solution is simple and doesn't require memorization.
Thanks sirr!❤
Thanks for posting such an informative video, Mr Aggarwal.
Now I can find the day of the week of a given date easily....thank you...
absolutely 💯💯 well explained concept
Way of explaination was really outstanding sir
Well explained
Thank you very much
This is a normal method but explanation is simple. It is good for beginners..
Really helpful, thanks a lot sir
Suresh, you are superb. Maths is so much fun with your tricks.My son loves them
Today morning I learnt this and now you taught.. Ur was better.. The morning session went tangentially
Sir, you are best and precise in what you teach. Thank you so much for helping us understand this concept so easily and quickly. Thank you so much for your contribution and hard work. I will keep following you and learn from you. Thank you again. Your faithful student
Great....
Amazing, step by step, without any trick or jumps, very cool..
Thankyou very much for helping out the basics with clarity
I searched some videos for this problem... But ur only given the solves from the beginning... Tq so much sir....
Thank you sir for all concept cleared in one video....
Agarwal sir can you please explain the
14 - 7 - 2010
When I solve the above problem I get the answer as per your theory Thursday but actually answer is Wednesday.
Please clarify my doubt
Watch my method
no it comng wednesday only do it again
Even I got Thursday for the mentioned date.
@@niharikagamedhar1612 no do it precisely you will get thursday
It's Wednesday
3 comes as answer
have you made a video for writing a series using sigma and pi notation?
Sir, based on your concept the day for date 22-02-2020 is coming Sunday, (D22+M4+ C6+Y20+Q5= 57/7 remainder is 1 and as per your week num. It is Sunday) where as 22-02-2022 is on Saturday.. please solve..
Not only for children appearing for competitive exams, these tricks can help adults too. Great videos Sir !
L
Sir you are the best
Thank you so much
a best explanation to understand these type of competitive problems
Kuch log kya kya tricks yaad karwa dete he, but this video is fully conceptual and remember for a long time, thank u
very helpful sir...thank u so much for this amazing trick and session
Calendar which are having the same calendar
“Ordinary years” - after every 6 or 11 years.
Leap years- after every 28years. Same calendar will be repeated!!
Hey, please help
1-11-2020
2020 = 2000 + 20
2000 ->> 0
20 ->> 5 leap + 15 normal
so , 10 +15 = 25
25 % 7 = 4 odd days
now ,
3 + 1 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 1 = 26
26 % 7 = 5
so , total = 0 + 4 + 5 = 9
9 % 7 = 2
by 2 its tuesday
but it's a sunday ????
why ???
Dhiraj ,, let’s us understand that the month is given till Nov which is incomplete year of 2020.
For the calculations we have to take complete year ie2019 as per rule
2019
2000 + 19 /4 ( 4 leap year and 15 ordinary years
0+(4x2+15x1)+3+1(lepyears)+3+2+3+2+3+3+2+3+ (***1)
8+15+26= 49/7 = O odd day ie Sunday
Follow my method times less consume to be honest Sir method is quit complicated
(***)
given date may be 15,17,25,35etc whatever may be always divided by 7( applicable when it’s (= or greater than 7) and put the remainder in that month..
I can't find the day of 19/01/1988
@@dhiraj.govindvira you shouldn't count the number of years as 2020 but 2019. so 2000>>0 and 19 >> 15 normal+ 4 leap = 15+8= 23----> 23 mod7=2 instead of 4 and then do the rest and it will sunday
@@debkumarbose5683 Tuesday. I don't need a perpetual calendar to tell me that when i already have one in my head.
Hello does this work for any date in 1752. For example September 14, 1752?
Thank you sir for explaining in such a simple way, now I can compute the day of any date, thanks a lot sir.
Hello , may I ask?
Why is
0 = Sunday,
1 = Monday,
2 = Tuesday, ect ?
Thank you so much for your Trick .
Kristianto Raharjo because it was Monday on 1-1-1. :)
This is predefined by calendar system we follow ( gregerion calender ) .
The initial Gregorian calendar 1-01-01 Monday..
Because when God created the world he finished his work and relaxed on the last day of it was a Sunday point of origin of the world, then the full process started to work on the next day the first day n°1 the Monday 😉
No i'm joking...
But it works, right?
@@answhiganswhig377 😂😂😂
it was truly well explained. but in my opinion i dont really think i can do it without a paper and pen. and this takes a little bit more time then it should. still i learn quite a lot from this and i am thankful for that.
100% Working. Taking very less time after Practice
Thank you sir🙏.
I am thinking why didn't our teachers teach these techniques when we were learning it for the first time. Then Life would be so much easier now
Thank you sir i was searching for this method.
Do share the links with your WhatsApp groups and contacts
Sir, Can u plz explain the same for 31/12/2017 as i am getting a different answer
Kashif A kg tar
1)2000-0 odd days
2)2000-2016 = 4 leap years and 12 normal years = 12 +8(4×2) =20 odd days
3)till 31 december = 3+0+3+2+3+2+3+3+2+3+2+31=57
0+20+57=77 =77/7=0 odd day
it was sunday
Nice trick. I have a suggestion you should increase your font size because some time it is not visible or not clear visible.
What if when u add the odd days, it adds to a number less than 7. Because then you have no remainder then meaning no odd days
The Doomsday method (1970 Conway) requiring 3 tables, one sentence and two divisions by 4 and 12 and 3 additions is far easier/faster and much more versatile as it also gives anchoring dates...
Thanks for that....will try it.
Too much to memorise and less to understand in doomsday
@@sureshaggarwal sir 2000 aru 2001,2002,2003 year ka keise
Thank you 😊😊😊
Sir today i feel happy because this video clear my doubts... Thanks for sharing your concepts
Do share the links with your WhatsApp groups and contacts
it's the best explanation ever seen, thank you, sir.
Hi sir,
Can u pls check this date 06-08-2019
As per trick i got wenesday
But actualy it is tuesday in the callender
Jayaraj V P
At 2000= 0 odd days
So we have 18 yrs and 8 months and 6 days
In 18 yrs, 4 yrs are leap yr
So we have 4*2= 8
And 18-4= 14
14+8= 22 odd days till 2018
And remaining 8 month and six days are 3+0+3+2+3+2+3+6=22odd days
So we have total 44 odd days
So we get 44/7= 2 reminder which is *TUESDAY*
I don't think I can do it in 15 seconds. I lost track in the middle.
Same here
I lost trick at 7;52 sec
very superb explanation of the concept. however there must be a simpler way
The explanation is very nice, smooth and easy. Thank you
This is one of the hard question in competitive exams.This trick is very beneficial for me .
I could help you to fo it in 5-6 seconds.
And For me it takes 1-2 seconds
@@themasterji8252 how ??
Sir I am learning in class 10 I will give the NTSE exam ( can I aske to question Sir please)
So did you crack NTSE?
Thank you so much sir for this concept
Thank you so much sir for the best explanation 🙏🙇♂️
Sir, you are great
watching this from Boston right now. Jai hind 🇮🇳
nice explanation. It is very helpful to me in revision of calendar chapter
Ty sir your method of doing this is really easy and there is no need to remember any code
you the best teacher compared to the highly paid teachers in the coaching centres like carrer launcher,aakash etc you made my concept crystal clear thank you so much sir i was worried because i was not able to grasp the concept in carrer launcher in 4 long hours and i was searching on the internet for the exact same method for whole 1 day
Go on career will
Y
Ml
I0jlqp0q7
I0jlqp0q7
Ek number..gajab
This is the best explainatory video on this topic. Thank you so much Sir.
Sir plz answer me what will be the day on 1 march 2020 with explanation
very good explanation sir. after understanding actually it can be solved in about 15 seonds
Well, I can't do that in 15 seconds, but here's my approach. After using it many times, I can "think" it a lot faster than I can explain it.
1956 Aug 15 = what day-of week (DOW)?
Every 28 years there's an exact repeat of the calendar (so long as no Gregorian century non-leap year is crossed; last one was 1900; next is 2100, so we're safe here).
1956 + 2·28 = 2012; so 1956 Aug 15 = 2012 Aug 15
And every forward jump of one year adds one DOW, so long as no leap day (LD) is crossed. Each LD adds one additional DOW.
That means that jumping to the same date, either 5 or 6 years forward, preserves DOW, depending only on how many LD's are crossed
(5 y + 2 LDs or 6 y + 1 LD, makes 7 days either way = same DOW). August 2012 is just past a LD.
So 2012 Aug 15 + 6 years = 2018 Aug 15
has the same DOW. Now as I write this, it is Jan. 12, 2019, Saturday. Add 3 days to make the day-of-month match:
2019 Jan 12 Sat. + 3 days = 2019 Jan 15 Tue.
Now go back to August 2018, for which we must add the days of Dec. backward through August:
31 + 30 + 31 + 30 + 31 = 153 = 7·22 - 1
so subtracting those 153 days, adds one to the DOW.
Therfore,
1956 Aug 15 was Tue + 1 = Wednesday.
This doesn't show how to do a general DOW problem, however. For that, I have a number of other tricks; such as which months within a calendar year, match:
Non-Leap:
Jan = Oct
Feb = Mar = Nov
Apr = July
Sep = Dec
May, June, and Aug, don't match any others.
Leap:
Jan = Apr = July
Feb = Aug
Mar = Nov
Sep = Dec
May, June, and Oct, don't match any others.
Always:
May = the following Jan
June = the following Feb
When the latter year is non-leap:
Aug = the following May
Sep = the following June
Oct = the following July
Nov = the following Aug
For longer-range problems, you must take account of missing leap days in those Gregorian exception years - century years that aren't 400-divisible.
And that the Gregorian calendar repeats every 400 years. (Because 400 Gregorian years = 146097 days = 20871 weeks.)
Anyway, this is just what works for me; and although it may not work for you, if it does, go ahead and use it.
A few additional notes:
1)
A lot of what Suresh is doing here is based on mod 7 arithmetic; if you know how to do that, a lot of his explanations can be greatly simplified. Of course, he's assuming an audience many of whom aren't familiar with modular arithmetic, so he couldn't make those simplifications.
2) If you have access to a JDN (Julian Day Number) calculator, you can just convert the date in question to JDN, then take that mod 7.
That remainder corresponds to: 0=Mon, 1=Tue, ..., 6=Sun.
Note carefully that JDN is *not* what is often mistakenly called, "Julian Day," which is actually just day-of-year, 1 to 365/366.
JDN was invented by historian Joseph Scaliger in 1583 (the year after the introduction of the Gregorian calendar) in order to convert all the multifarious calendars that were used by various nations and empires throughout history, to a single day-counting system. Today it is used in astronomy to time certain types of recurrent astronomical events; and by the various space programs to keep track of what spacecraft are doing. In these arenas, it includes fractional days, the "zero" of which is noon UT.
E.g., JDN 1 = Jan.1, 4713 BC (Julian Calendar).
JDN of Jan. 12, 2019 (Gregorian Calendar) is 2,458,496.
3) This video really amounts to a way to find a similar sort of count, starting on each Jan.1, 400n, all of which are Saturdays.
And I think it's more amenable to general use than my own method.
Fred
Sir can you explain it in hindi
I couldn't get you
Please sir .I am very eager to know this trick.that will be helpful for my competitive exam
@@AshokYadav-zq2kd In Hindi? I think you must have meant to ask Suresh that.
In any case, I know about as much Hindi as I know Martian.
And Suresh's method is more generally suitable than mine, which is more attuned to me personally.
Fred
@@ffggddss no sir absolutely not I asked you only.i have seen Suresh sir video but I want to know different tricks .so i asked you
Your all the concept is very nice sir and
You explain very well
Sir please do video on prime factrization
The trick finally revealed
Really extremely helpful.....
helped me a lot for NTSE preparations
Thank you so much, sir! This was really helpful.
Great sir, your method is very good..thank you
What if the year is less than 1600. I couldn't get that. Please tell
Check the complete steps in the video I uploaded in my channel.
@@AmulrajSundaramoorthyTAS ok
thank you so much sir...you give best tricks all the time... dislikers are losers..
Thanks for the motivation. ...Kindly do help in sharing
Poonam doll
Hi
It is good but not best.
Have you seen scot flansburg how fast he was... And now i am like him
And I am preparing my self to break the Guinness book of world record of Scot flansburg.
Sir I have learn this in my third standard in 1977 but where is fifteen seconds
sir in 15th April 2017.1st segment is caulculate odd day from 2016.please calculte odd number from 2016.15 th April is easy.but as 2016 itself is a leaf year calcution makes some mistakes.
2017=0
April= 6
15=15-14=1
So total 6+1+0=7=0 Saturday.
Thanks sir..@suresh aggareal
I have one question
As when you cancel the odd days in a month till 7(normal year) and 14( leap year), I am not able to sort out from march. If you may, can you help me sort this out?
I can understand crystal clear. You Sir are a wonderful teacher, I really hope I could be as good as you some day. My heartfelt thanks for setting an example.
nice trick .....but also complicated...
Yes....it needs a practice of one hour for mastering....keep learning :-)
Sir in first example you are cancelled by adding digits of month odd days which are equal to 7 only once, but in second example why you are cancelled by adding digits of month odd days which are equal to 7 twice, please give me solution
such a sweet gentleman. THANK YOU .