Sir if I am not wrong for finding viscous force the formula is (shear elasticity)*area*(velocity "gradient) But instead of velocity gradient which is dv/dx you took dv/dt
@@kavitasharma7483 voh sir nai equal isliye kara to make sure thatfluid flows in it with constant velocity . Had the dragging force was not there then the fluid might eventually stop flowing
Bhut hi acha explanation kiya bhai, but ek mistake hui h, back dragging force me Differentiation me dt ki jgh dx krna chahiye tha (dv/dx). Well explained, acha lga mujhe
12:00 sir integration variable to 't' hai na, then xdt = (x^2)/2 kaise hua?
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Sir viscous dragging force ar viscous force alg hote hain??
Sir if I am not wrong for finding viscous force the formula is (shear elasticity)*area*(velocity "gradient)
But instead of velocity gradient which is dv/dx you took dv/dt
@@kavitasharma7483 voh sir nai equal isliye kara to make sure thatfluid flows in it with constant velocity . Had the dragging force was not there then the fluid might eventually stop flowing
Ok
Thanks Sir, it was very helpful.
Very good explanation I truly love it ❤
Bhut hi acha explanation kiya bhai, but ek mistake hui h, back dragging force me Differentiation me dt ki jgh dx krna chahiye tha (dv/dx).
Well explained, acha lga mujhe
Nice explanation sir..
The way of explanation is amazing and very simple.
Great sir.....
Thank you ❤
sir nice video ,i understood the derivation very well ,
but dv/dx it is ,for viscous force.F=nAdv/dx not dt.
Apke pass sem 1 ki questions paper h
Please can you provide me pdf of it
wow top level explanation
The way of teaching was nice..
This is the perfect video to understand this derivation 👍👍👍
At 11:14 integration of xdt =xt and not x^2/2
Explain if I'm wrong?
Ur handwriting is really good sir, so is your teaching skills
Thank you for the explanation 👌👌
Very nice and useful explaination sir
Well understood...thanx a lot sir for this beautiful approach 👍👍🔥🔥
Why does the formula fail in the case of wide bore?
Nice explanation sir..... Thank you so much 😊
thank you so much it was very helpfull
Thanks....It is very helpful me
आपके वीडियो देखने के बाद मुझे इक्वेशन का डेरिवेशन समझ में आ गया
Helped a lot....thanks....😊😊
V gooood.....really helpful explanation
Superb explaination Sir. Thank you.
Thank you so much sir for such an awesome educational video
Thank god now i got it, and I'm reading this before exam
At newton's law of viscous flow it not dv/dt, according to law its dv/dl
Bht kmal Btaya
How did you get the area between the two imaginary tubes to be 2pixdx??? 15:09
Just imagine that area like a rectangular strip.
Thanks a lot sir ...
Please continue it...
Thanks you so mush for pdf note 📝 ❤❤❤
Well explained 👍
11:12 sir you integrate x with respect to dt ???
Very helpful video 😇
Very nice explanation.
❤❤❤
Amazing explaination
Konse book se hai bhai , jaldi bata do
Very nice explaination sir plz explain complete syllabus of bsc
Excellent explanation sir
Nice explanation sir ji 🙏
Nice teaching method
Superb👏
Thank u so muchh.... U explained very well ...
Nice appreciate that !
This video is very helpful me
Extremely good ....video....👌👌,Nicely explained😍
Helpful 🙂
dt nhi hoga, dx hoga...saare dt ko dx se replace koro...otherwise, explanation is quite good🤞🔥
There is mistake in velocity gradient
Thank you so much bhaiya 😌🤍🖤
Thanks sir. Great help for me
Nice explanation
you shd also explain background dragging force.
Helpful for my semester 🥲❤️
Thanks bhaiya for this video
Thanks sirr...Very useful🥳
thank you so much sir,,,bohot help hua
Is this a topic of class 11 cause our school is asking to drive this in exam of class 11 ?
Sir aap assam ke ho ya china
V integration with respect to t kaisa x ka integration hoga ?
Thanks sir it's really great..
Sir 2good padaya aapne lekin hindi medium me bhi mil jaata to aasani hoti..?
Sir kuch log V/t bhi likhte hai to Q=V/t hai Kya?
11:23 min me (x dt) ka integration hoga he nhi kyuki function x ke respect me h aur aap dt ke ke respect me integrate kr rhe ho
wo isne galti se dv/dt likh diya hai , asli mein formulae mein dv/dx hai
Full support
Viscous force is directly proportional to velocity GRADIENT
dv/dx....
Thank you very much👍👍👍
Very very nice
Helpful 🙏🏻
Tq sir its helping more sir
Sukriya bht
Sir how x can integrate w.r.t. dt
Thanks 👍
thaks bro😍
Pressure must be constant and then you put pressure difference
Bahut achha
Sir esii tera orr video bsc kelie banaoo thank you
Kamal sir
Superb
nyc explanation
Dhanyawad 😭
Thank you Sir 😇
Helped!!!
sir there is a mistake f=nAdv/dx instead of this you have written for=nAdv/dt
Sir apne integration t ke respect mai kara hai aur aap x ko xsquare/2 kaise likh sakte ho
wo isne galti se dv/dt likh diya hai , asli mein formulae mein dv/dx hai
Thank you sir!!!!!!!!
Thank you sir 🙏
Great
Thank you
Super
Outstanding
Thank you very much
Thanks you ...sir
Thanks sir .
sir explanation badiya tha par aap ne derivation thodi lambi karva dii
Thanks
Thank you sir
Nice
Good
Thank u
00:02
Tqq😊😊